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eureka
I have been given a puzzle: It is a right triangle with the hypotenuse = 8.1m and one of the other angles = 49 degrees. How do I solve for the other two sides?
sin 49=Opp/Hyp=BC/8.1 =>BC=8.1*0.75=6.1 cos 49= AC/8.1 =>AC=0.65*8.1=5.3
Thank you mervin2293. I got it. :)