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eureka

  • 2 years ago

I have been given a puzzle: It is a right triangle with the hypotenuse = 8.1m and one of the other angles = 49 degrees. How do I solve for the other two sides?

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  1. eureka
    • 2 years ago
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    |dw:1357873903245:dw|

  2. mervin2293
    • 2 years ago
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    sin 49=Opp/Hyp=BC/8.1 =>BC=8.1*0.75=6.1 cos 49= AC/8.1 =>AC=0.65*8.1=5.3

  3. eureka
    • 2 years ago
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    Thank you mervin2293. I got it. :)

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