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with what

RADICALS

wat u mean

u i might be able to help u

\[-\sqrt{27}+3\sqrt{3}+2\sqrt{45}+3\sqrt{12}\]

all you can do here is simplify 3√12

\[2\sqrt{6}+3\sqrt{45}-2\sqrt{54}-3\sqrt{3}\]

3√12 is 3√4x3, the square root of 4 is 2 which pops out and u multiply the 3 by 2 to have 6√3

you should have 9√3

for the 2nd one or the 1st one

ok, i thought this was one problem, so you want to simplify the first one right?

yes

−√27 + 3√3 + 2√45 +2√45 + 3√12 is where we start right

crap i have 2squarerrot 45 twice

take one out

−√27 + 3√3 + 2√45 + 3√12

yes that is right

3√12 can become 3√(4)(3)

how do u work it out

3(2)√3 which is 6√3, now you can add this to the other 3√3 in the problem

add wat one and i think u so much for helpin me
thanks

−√27 + 3√3 +(6√3) + 2√45 you can only add radicals when they are the same inside

so i add 3and 3

alright think u so much

NP

http://imgur.com/sxDwY