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WILL SOMEONE HELP ME

Geometry
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with what
RADICALS
wat u mean

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Other answers:

u i might be able to help u
\[-\sqrt{27}+3\sqrt{3}+2\sqrt{45}+3\sqrt{12}\]
all you can do here is simplify 3√12
\[2\sqrt{6}+3\sqrt{45}-2\sqrt{54}-3\sqrt{3}\]
3√12 is 3√4x3, the square root of 4 is 2 which pops out and u multiply the 3 by 2 to have 6√3
you should have 9√3
for the 2nd one or the 1st one
ok, i thought this was one problem, so you want to simplify the first one right?
yes
−√27 + 3√3 + 2√45 +2√45 + 3√12 is where we start right
crap i have 2squarerrot 45 twice
take one out
−√27 + 3√3 + 2√45 + 3√12
yes that is right
3√12 can become 3√(4)(3)
how do u work it out
since 2 is the SRoot of 4, it comes out to me multiplied by the 3 on the outside, leaving the 3 inside to become 6√3
3(2)√3 which is 6√3, now you can add this to the other 3√3 in the problem
add wat one and i think u so much for helpin me thanks
−√27 + 3√3 +(6√3) + 2√45 you can only add radicals when they are the same inside
so i add 3and 3
we can actually simplify the 2 sroot 45. Give me a few min to show you how. Come back in about 5 minutes and it will be done
alright think u so much
NP
http://imgur.com/sxDwY

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