weekskeith15
WILL SOMEONE HELP ME



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owen97
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with what

weekskeith15
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RADICALS

weekskeith15
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wat u mean

owen97
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u i might be able to help u

weekskeith15
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\[\sqrt{27}+3\sqrt{3}+2\sqrt{45}+3\sqrt{12}\]

cammyabbo
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all you can do here is simplify 3√12

weekskeith15
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\[2\sqrt{6}+3\sqrt{45}2\sqrt{54}3\sqrt{3}\]

cammyabbo
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3√12 is 3√4x3, the square root of 4 is 2 which pops out and u multiply the 3 by 2 to have 6√3

cammyabbo
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you should have 9√3

weekskeith15
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for the 2nd one or the 1st one

cammyabbo
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ok, i thought this was one problem, so you want to simplify the first one right?

weekskeith15
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yes

cammyabbo
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−√27 + 3√3 + 2√45 +2√45 + 3√12 is where we start right

cammyabbo
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crap i have 2squarerrot 45 twice

cammyabbo
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take one out

cammyabbo
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−√27 + 3√3 + 2√45 + 3√12

weekskeith15
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yes that is right

cammyabbo
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3√12 can become 3√(4)(3)

weekskeith15
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how do u work it out

cammyabbo
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since 2 is the SRoot of 4, it comes out to me multiplied by the 3 on the outside, leaving the 3 inside to become 6√3

cammyabbo
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3(2)√3 which is 6√3, now you can add this to the other 3√3 in the problem

weekskeith15
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add wat one and i think u so much for helpin me
thanks

cammyabbo
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−√27 + 3√3 +(6√3) + 2√45 you can only add radicals when they are the same inside

weekskeith15
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so i add 3and 3

cammyabbo
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we can actually simplify the 2 sroot 45. Give me a few min to show you how. Come back in about 5 minutes and it will be done

weekskeith15
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alright think u so much

cammyabbo
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NP
