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If you are looking at linear equations it really its at your choice... you can solve any system of equations by any of the methods...
quadratic or higher and a linear, I use substitution most of the time... but again, this can be done graphically
you can solve any equation graphically
e.g. x + 3 = 5
just graph y = x + 3 and y = 5... it will show you x = 2
Depends on what the question looks like. Elimination is usually the easiest, but it gets tricky sometimes. I only use graphing as a last option and professor dont usually ask this
Those wt really know how to answer them. asked me , i dont really know how to answer them each individually
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If you're given:
`x` = 3 + y
2x + 5y = 7
Use `substitution` since in this case, x is isolated and you can substitute the expression for x in the first equation into the second equation.
However if you're given:
x `+ 2y` = 4
3x `- 2y` = 5
Use `elimination` since you can simply add both equations together to get rid of the y variable.
`y` = 2x - 3
`y` = 5x - 4
Then use `graphing` since both equations are in the form y = mx + b. You can simply enter both equations into your graphing calculator to find the (x,y) intersection point.