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jenn0814
 one year ago
Best ResponseYou've already chosen the best response.0x4−x3−6x2+4x+80 is your answer

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0you want to use grouping to factor this polynomial

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0for the first 3 terms, you can factor out an X^2

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0how should i group them?

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0i got x^2(x^2x6)+4(x+2)

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0x^2(x3)(x+2)+4(x+2) (x+2)(x^2(x3)+4) :/

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0x^4  x^3  6x^2 + 4x + 8 = 0

matricked
 one year ago
Best ResponseYou've already chosen the best response.0use factor and remainder theorem to solve it

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0x^2(x^2  x  6) + 4(x + 2) = 0

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0do you have to use special factors?

matricked
 one year ago
Best ResponseYou've already chosen the best response.0see by plugging x=2 the expression x^4  x^3  6x^2 + 4x + 8 becomes 0 hence x+2 is one of the factor for getting other factors divide x^4  x^3  6x^2 + 4x + 8 by x+2

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0no... (x^2+4)(x3)(x+2)^2=0 now solve each equal to zero

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0no to special factors, matricked is right also

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0you skipped a couple steps from x^2(x^2  x  6) + 4(x + 2) = 0

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0i further factored (x^2x6) and grouped (x^2+4)

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0can you show me how, from there, you got (x^2+4)(x3)(x+2)^2=0?

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0now set each equation equal to 0

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0the x^2 and +4 you pulled out go in their own equation

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0wait so from x^2(x3)(x+2) + 4(x+2) = (x^2+4)(x+2)^2 (x3)?

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0now set each equal to zero by themselves and solve for x

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0the rest i know how, but h\where's the logic in that move, where you can take x^2+4

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0you factored it out by grouping

jaersyn
 one year ago
Best ResponseYou've already chosen the best response.0it is my understanding that in order to factor by grouping both pieces need to have common factors like, "4(x+2)" doesn't have a (x3)

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0are you learning imaginary numbers?

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0right, but x^2x6 did

cammyabbo
 one year ago
Best ResponseYou've already chosen the best response.0you further factored

matricked
 one year ago
Best ResponseYou've already chosen the best response.0x^4  x^3  6x^2 + 4x + 8=0 x^4 +2x^3 3x^3  6x^2 + 4x + 8=0 X^3(x+2) 3x^2(x+2) +4(x+2)=0 (x+2)(x^33x^2+4)=0 (x+2)(x^32x^2x^2+4)=0 (x+2)(x^2(x2)  (x+2)(x2))=0 (x+2)(x2)(x^2x2)=0 (x+2)(x2)(x^22x+x2)=0 (x+2)(x2)(x(x2)+1(x2))=0 or(x+2)(x2)(x2)(x+1)=0 now set each equal to 0 thus the roots are 1,2,2,2
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