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Sophia.13
 2 years ago
Solve using two differemt methods. Explain which method you found to be more efficient.
a. 3x9y=3
6x  3y= 24
Sophia.13
 2 years ago
Solve using two differemt methods. Explain which method you found to be more efficient. a. 3x9y=3 6x  3y= 24

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wio
 2 years ago
Best ResponseYou've already chosen the best response.1The two methods are elimination and substitution.

Sophia.13
 2 years ago
Best ResponseYou've already chosen the best response.0There is also graphing

skullpatrol
 2 years ago
Best ResponseYou've already chosen the best response.0What have you tried?

Sophia.13
 2 years ago
Best ResponseYou've already chosen the best response.0Nothing yet, i know how to do elimination. But i dont know how to substitution or graphing.

skullpatrol
 2 years ago
Best ResponseYou've already chosen the best response.0Use elimination and find the answer first. All the methods should give the same answer, right?

skullpatrol
 2 years ago
Best ResponseYou've already chosen the best response.0$$ 3x9y=3$$ $$ 6x  3y= 24$$

Sophia.13
 2 years ago
Best ResponseYou've already chosen the best response.0I got 3x6y= 27 but i dont think its rigth is it?

Sophia.13
 2 years ago
Best ResponseYou've already chosen the best response.0well, how do i do it?

skullpatrol
 2 years ago
Best ResponseYou've already chosen the best response.0You said you know how to use elimination. Try multiplying the first equation by $$2$$ and add it to the second equation...

skullpatrol
 2 years ago
Best ResponseYou've already chosen the best response.0$$ (3x9y=3) (2)$$ 6x  3y= 24

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.1\[3x9y=3 [1]\] \[6x  3y= 24 [2]\] \[2\times [1]\] \[6x18y=6 [3]\] \[[2][3]\] \[(6x  3y)  (6x18y)= (24)(6)\]

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.1\[3y+18y=30\] The x's cancel out. Now you can solve for y. Once you solve for y, you can then substitute the y component that you just found, into any one of the equations above to find your xvalue.

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.1If you need further assistance, I will be happy to elaborate it in more simple terms.
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