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Babybee24
 one year ago
Best ResponseYou've already chosen the best response.1I factored a cos(x) out but then im stuck

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0cos(x)( ? + ? ) =0 So what should be in the places of those ?'s once you factor out cos(x)?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0Yes. Set both factors equal to 0. cos(x)=0 ; cos(x)+sin(x)=0

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0Solve cos(x)=0 for x And find the value x so that cos(x) and sin(x) are opposites (i.e cos(x)=sin(x))

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0cos(x)=0 for x=pi/2 cos(x) does not equal pi/2 But one value that satisfies cos(x)=0 is x=pi/2 Are there any other values?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0Ok and you can also say we have x=pi/2+2npi where n is an integer or x=3pi/2+2n pi where n is an integer

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0We also need to find the values of x where cos(x) and sin(x) have opposite values.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0dw:1357920385873:dw As you can see they will be opposite in quadrant 2 and 4.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0dw:1357920430907:dw These points is where cos(x) and sin(x) are opposite. Now what angle are these points at from the initial ray?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0Now should your answer be in radians or degrees?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0So 135*pi/180 or 315*pi/180

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0Don't forget we can go around the circle infinitely many times from those angles.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0So 135pi/180+2npi , 315pi/180+2npi

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0Don't forget the other solutions we wrote above. Good job. :)
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