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Babybee24
 2 years ago
Best ResponseYou've already chosen the best response.1I factored a cos(x) out but then im stuck

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0cos(x)( ? + ? ) =0 So what should be in the places of those ?'s once you factor out cos(x)?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0Yes. Set both factors equal to 0. cos(x)=0 ; cos(x)+sin(x)=0

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0Solve cos(x)=0 for x And find the value x so that cos(x) and sin(x) are opposites (i.e cos(x)=sin(x))

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0cos(x)=0 for x=pi/2 cos(x) does not equal pi/2 But one value that satisfies cos(x)=0 is x=pi/2 Are there any other values?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0Ok and you can also say we have x=pi/2+2npi where n is an integer or x=3pi/2+2n pi where n is an integer

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0We also need to find the values of x where cos(x) and sin(x) have opposite values.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1357920385873:dw As you can see they will be opposite in quadrant 2 and 4.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1357920430907:dw These points is where cos(x) and sin(x) are opposite. Now what angle are these points at from the initial ray?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0Now should your answer be in radians or degrees?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0So 135*pi/180 or 315*pi/180

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0Don't forget we can go around the circle infinitely many times from those angles.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0So 135pi/180+2npi , 315pi/180+2npi

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.0Don't forget the other solutions we wrote above. Good job. :)
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