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Babybee24Best ResponseYou've already chosen the best response.1
I factored a cos(x) out but then im stuck
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
cos(x)( ? + ? ) =0 So what should be in the places of those ?'s once you factor out cos(x)?
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Yes. Set both factors equal to 0. cos(x)=0 ; cos(x)+sin(x)=0
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Solve cos(x)=0 for x And find the value x so that cos(x) and sin(x) are opposites (i.e cos(x)=sin(x))
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
cos(x)=0 for x=pi/2 cos(x) does not equal pi/2 But one value that satisfies cos(x)=0 is x=pi/2 Are there any other values?
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Ok and you can also say we have x=pi/2+2npi where n is an integer or x=3pi/2+2n pi where n is an integer
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
We also need to find the values of x where cos(x) and sin(x) have opposite values.
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
dw:1357920385873:dw As you can see they will be opposite in quadrant 2 and 4.
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
dw:1357920430907:dw These points is where cos(x) and sin(x) are opposite. Now what angle are these points at from the initial ray?
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Now should your answer be in radians or degrees?
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
So 135*pi/180 or 315*pi/180
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Don't forget we can go around the circle infinitely many times from those angles.
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
So 135pi/180+2npi , 315pi/180+2npi
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Don't forget the other solutions we wrote above. Good job. :)
 one year ago
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