## yrelhan4 Group Title The driver of a car moving on a straight road applies brakes to come to rest, with a constant retardation 'a'. Assuming that the time of motion is more than 2 s, the distance covered by the car in secondlast second of its motion is one year ago one year ago

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Distance Travelled in nth Second $Dn = u + \frac{ a }{ 2 }[2n-1]$ Since the Question Talks about retardation $Dn = u - \frac{ a }{ 2 }[2n-1]$

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$v = u -at$ $u = at$ t - 1 = n t = n +1 u = a (n+1)

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Nw Substitute the Value of u in the 1st equation

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$Dn = an + a - an + a/2 = 3a/2$

5. yrelhan4

Thank you! (:

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Welcome...

7. yrelhan4

why is t-1=n?

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secondlast second of its motion

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let t be the total time

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secondlast = t-1

11. yrelhan4

oh.. haha.. ty again!