yrelhan4
  • yrelhan4
The driver of a car moving on a straight road applies brakes to come to rest, with a constant retardation 'a'. Assuming that the time of motion is more than 2 s, the distance covered by the car in secondlast second of its motion is
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Distance Travelled in nth Second \[Dn = u + \frac{ a }{ 2 }[2n-1]\] Since the Question Talks about retardation \[Dn = u - \frac{ a }{ 2 }[2n-1]\]
anonymous
  • anonymous
\[v = u -at\] \[u = at\] t - 1 = n t = n +1 u = a (n+1)
anonymous
  • anonymous
Nw Substitute the Value of u in the 1st equation

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anonymous
  • anonymous
\[Dn = an + a - an + a/2 = 3a/2\]
yrelhan4
  • yrelhan4
Thank you! (:
anonymous
  • anonymous
Welcome...
yrelhan4
  • yrelhan4
why is t-1=n?
anonymous
  • anonymous
secondlast second of its motion
anonymous
  • anonymous
let t be the total time
anonymous
  • anonymous
secondlast = t-1
yrelhan4
  • yrelhan4
oh.. haha.. ty again!

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