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yrelhan4

  • 2 years ago

The driver of a car moving on a straight road applies brakes to come to rest, with a constant retardation 'a'. Assuming that the time of motion is more than 2 s, the distance covered by the car in secondlast second of its motion is

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  1. Yahoo!
    • 2 years ago
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    Distance Travelled in nth Second \[Dn = u + \frac{ a }{ 2 }[2n-1]\] Since the Question Talks about retardation \[Dn = u - \frac{ a }{ 2 }[2n-1]\]

  2. Yahoo!
    • 2 years ago
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    \[v = u -at\] \[u = at\] t - 1 = n t = n +1 u = a (n+1)

  3. Yahoo!
    • 2 years ago
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    Nw Substitute the Value of u in the 1st equation

  4. Yahoo!
    • 2 years ago
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    \[Dn = an + a - an + a/2 = 3a/2\]

  5. yrelhan4
    • 2 years ago
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    Thank you! (:

  6. Yahoo!
    • 2 years ago
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    Welcome...

  7. yrelhan4
    • 2 years ago
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    why is t-1=n?

  8. Yahoo!
    • 2 years ago
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    secondlast second of its motion

  9. Yahoo!
    • 2 years ago
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    let t be the total time

  10. Yahoo!
    • 2 years ago
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    secondlast = t-1

  11. yrelhan4
    • 2 years ago
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    oh.. haha.. ty again!

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