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DLS

  • one year ago

A line passing through (2,2) is perpendicular to the line 3x+2y=3.its y intercept is?

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  1. Yahoo!
    • one year ago
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    Since the Lines are perpendicular m 1 * m2 = -1

  2. DLS
    • one year ago
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    m=2/3

  3. DLS
    • one year ago
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    kthx

  4. Yahoo!
    • one year ago
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    3x+2y=3 3x + 2y - 3 =0 m1 = -a/b = -3/2 m2 = 2/3 Nw use Point Slope Form

  5. Yahoo!
    • one year ago
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    y-y1 = m(x-x1)

  6. Yahoo!
    • one year ago
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    Hope nw u can Solve it

  7. DLS
    • one year ago
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    3y-2x-2=0

  8. DLS
    • one year ago
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    i got till here before too..im gettig 2/3..itswrrong

  9. Yahoo!
    • one year ago
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    (2,2) y-y1 = m(x-x1) y-2 = 2/3 ( x-2) 3y - 6 = 2x - 4 2x - 3y +2=0

  10. Yahoo!
    • one year ago
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    Nw to Find y intercept.....Put x = 0

  11. DLS
    • one year ago
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    IM GETTING 2/3 ITS WRONG:/

  12. Yahoo!
    • one year ago
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    So -3y = -2 y = 2/3

  13. DLS
    • one year ago
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    WRONG

  14. Yahoo!
    • one year ago
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    But that Shuld be it.....Can u Check ur Question and Answer Key Once Agian ?

  15. DLS
    • one year ago
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    4/3..

  16. Yahoo!
    • one year ago
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    hm..hm..

  17. Azteck
    • one year ago
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    Are you 100% sure you copied the correct equation and point? If not, then @Yahoo! is spot on.

  18. DLS
    • one year ago
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    yes..i just want to confirm is there any hope of getting 4/3 or is there defintely a misprint in my ans key..

  19. Azteck
    • one year ago
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    Read the second part of my comment. It already states that if it is the correct equation and point, then it's a typo/misprint.

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