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 one year ago
Can someone help explain how to do quadratic equations with the quadratic formula? I'll give you a problem. See comments.
 one year ago
Can someone help explain how to do quadratic equations with the quadratic formula? I'll give you a problem. See comments.

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poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge 0 = 4(4t^2 8t 1)\]

hba
 one year ago
Best ResponseYou've already chosen the best response.1Well the first step is to compare your equation with the standard form and get a,b and c \[\huge\ ax^2+bx+c=0\]

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1So, how would I do that with this one? Multiply the parentheses stuff by 4?

hba
 one year ago
Best ResponseYou've already chosen the best response.1Seeing your question i would suggest you to first divide your whole equation by 4 and then compare

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1\[\Huge 0=4t^2 8t1\]

hba
 one year ago
Best ResponseYou've already chosen the best response.1What is a,b and c in this ?

hba
 one year ago
Best ResponseYou've already chosen the best response.1Good,Now you can use the quad formula. \[\huge\ x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]

hba
 one year ago
Best ResponseYou've already chosen the best response.1The other think which you can do with your equation is that you can take 1 common and then compare so everything becomes positive.you can also do it straight away :)

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1so, t = 8*√644*4  2*4 ?

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1which would then be t=8*(8+4)  8

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1am I getting it right?

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1I don't get it... wouldn't you be multiplying 8 and \[\pm √644*4\]?

hba
 one year ago
Best ResponseYou've already chosen the best response.1t=8(+)(8+4)  8

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1Now I'm rather confused.

hba
 one year ago
Best ResponseYou've already chosen the best response.1I appreciate you working with me though.

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1I guess I could do that \(\Huge\mathsf{:P}\)

hba
 one year ago
Best ResponseYou've already chosen the best response.1a=4 b=8 c=1 \[\huge\ t=\frac{ (8) \pm \sqrt{(8)^24(4)(1)} }{ 2(4) }\]

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1Ok, but what does the \[\pm\] do? what's its significance?

hba
 one year ago
Best ResponseYou've already chosen the best response.1Well when we simplify it we would be taking the adding part on one side and subracting part on the other side.

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1so it'd be 8+√blahblahblah  2(4)?

hba
 one year ago
Best ResponseYou've already chosen the best response.1Either, 8+√blahblahblah  2(4)? Or, 8√blahblahblah  2(4)?

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1so the \[\pm\] just breaks up between the denominator and the numerator?

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1Ah. I guess I'll try another problem here and ask you if it's right or something.

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge 0=2x ^{2} +14x +20\] \[\large x=\frac{ 14\pm \sqrt{14^2  4(2+20)} }{ 4 }\] \[\large x= \frac{ 14+1472 }{ 4 }\]

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1and the answer is \[\huge \frac{ 7\pm \sqrt{89} }{ 2 }\]. Would I be right?

hba
 one year ago
Best ResponseYou've already chosen the best response.1Its is 4(a)(c) not 4(a+c)

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1oh. Well that ruins that then.

hba
 one year ago
Best ResponseYou've already chosen the best response.1Yes it does :) Do it on a paper and tell me what you got from that equation :)

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large x=\frac{ 14\pm \sqrt{14^2  4(2*20)} }{ 4 }\] \[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] \[\Large x=\frac{ 14\pm 14160} { 4}\] \[\Large x=\frac{ 14\pm 146} {4}\] set x to 0 and divide all by 2 to get \[\Large \frac{ 7\pm 73} { 2}\]

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1and now I'm confused.

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1oh wait, I forgot to keep the x's in there. Crap.

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1Think you could help me out here? My mind is about to implode.

hba
 one year ago
Best ResponseYou've already chosen the best response.1So just because of signs it goes wrong.

hba
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] Continue from here.

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1But I left the xs out of my work. ._.

hba
 one year ago
Best ResponseYou've already chosen the best response.1Continue working from here.

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] \[\Large x=\frac{ 14\pm 14+160} {4}\] \[\Large x=\frac{ 14\pm 174} {4}\] \[\Large x=\frac {\frac{ 14\pm 174} {4}} {2}\] \[\Large x=\frac {7\pm 87} {2}\]

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1And now what do I do?

hba
 one year ago
Best ResponseYou've already chosen the best response.1I don't know what you are upto ,where did that divide by 2 come in between ?

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1Well, I'm not sure. I just thought I had to do that. I'm rather confused ._.

hba
 one year ago
Best ResponseYou've already chosen the best response.1Hmm,If OS would be working on chrome i would have worked one problem for you. Can we do this later ?

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1I'm using chrome right now o_o But, I guess that'd be OK :P

poopsiedoodle
 one year ago
Best ResponseYou've already chosen the best response.1Thanks to you too :3
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