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 2 years ago
Can someone help explain how to do quadratic equations with the quadratic formula? I'll give you a problem. See comments.
 2 years ago
Can someone help explain how to do quadratic equations with the quadratic formula? I'll give you a problem. See comments.

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poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1\[\huge 0 = 4(4t^2 8t 1)\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Well the first step is to compare your equation with the standard form and get a,b and c \[\huge\ ax^2+bx+c=0\]

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1So, how would I do that with this one? Multiply the parentheses stuff by 4?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Seeing your question i would suggest you to first divide your whole equation by 4 and then compare

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1\[\Huge 0=4t^2 8t1\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1What is a,b and c in this ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Good,Now you can use the quad formula. \[\huge\ x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1The other think which you can do with your equation is that you can take 1 common and then compare so everything becomes positive.you can also do it straight away :)

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1so, t = 8*√644*4  2*4 ?

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1which would then be t=8*(8+4)  8

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1am I getting it right?

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1I don't get it... wouldn't you be multiplying 8 and \[\pm √644*4\]?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1t=8(+)(8+4)  8

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1Now I'm rather confused.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1I appreciate you working with me though.

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1I guess I could do that \(\Huge\mathsf{:P}\)

hba
 2 years ago
Best ResponseYou've already chosen the best response.1a=4 b=8 c=1 \[\huge\ t=\frac{ (8) \pm \sqrt{(8)^24(4)(1)} }{ 2(4) }\]

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1Ok, but what does the \[\pm\] do? what's its significance?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Well when we simplify it we would be taking the adding part on one side and subracting part on the other side.

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1so it'd be 8+√blahblahblah  2(4)?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Either, 8+√blahblahblah  2(4)? Or, 8√blahblahblah  2(4)?

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1so the \[\pm\] just breaks up between the denominator and the numerator?

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1Ah. I guess I'll try another problem here and ask you if it's right or something.

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1\[\huge 0=2x ^{2} +14x +20\] \[\large x=\frac{ 14\pm \sqrt{14^2  4(2+20)} }{ 4 }\] \[\large x= \frac{ 14+1472 }{ 4 }\]

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1and the answer is \[\huge \frac{ 7\pm \sqrt{89} }{ 2 }\]. Would I be right?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Its is 4(a)(c) not 4(a+c)

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1oh. Well that ruins that then.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Yes it does :) Do it on a paper and tell me what you got from that equation :)

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1\[\Large x=\frac{ 14\pm \sqrt{14^2  4(2*20)} }{ 4 }\] \[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] \[\Large x=\frac{ 14\pm 14160} { 4}\] \[\Large x=\frac{ 14\pm 146} {4}\] set x to 0 and divide all by 2 to get \[\Large \frac{ 7\pm 73} { 2}\]

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1and now I'm confused.

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1oh wait, I forgot to keep the x's in there. Crap.

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1Think you could help me out here? My mind is about to implode.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1So just because of signs it goes wrong.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1\[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] Continue from here.

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1But I left the xs out of my work. ._.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Continue working from here.

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1\[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] \[\Large x=\frac{ 14\pm 14+160} {4}\] \[\Large x=\frac{ 14\pm 174} {4}\] \[\Large x=\frac {\frac{ 14\pm 174} {4}} {2}\] \[\Large x=\frac {7\pm 87} {2}\]

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1And now what do I do?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1I don't know what you are upto ,where did that divide by 2 come in between ?

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1Well, I'm not sure. I just thought I had to do that. I'm rather confused ._.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Hmm,If OS would be working on chrome i would have worked one problem for you. Can we do this later ?

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1I'm using chrome right now o_o But, I guess that'd be OK :P

poopsiedoodle
 2 years ago
Best ResponseYou've already chosen the best response.1Thanks to you too :3
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