Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
poopsiedoodle
Group Title
Can someone help explain how to do quadratic equations with the quadratic formula? I'll give you a problem. See comments.
 one year ago
 one year ago
poopsiedoodle Group Title
Can someone help explain how to do quadratic equations with the quadratic formula? I'll give you a problem. See comments.
 one year ago
 one year ago

This Question is Closed

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
\[\huge 0 = 4(4t^2 8t 1)\]
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Well the first step is to compare your equation with the standard form and get a,b and c \[\huge\ ax^2+bx+c=0\]
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
So, how would I do that with this one? Multiply the parentheses stuff by 4?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Seeing your question i would suggest you to first divide your whole equation by 4 and then compare
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
\[\Huge 0=4t^2 8t1\]
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
What is a,b and c in this ?
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
a=4 b=8 c=1
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Good,Now you can use the quad formula. \[\huge\ x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }\]
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
The other think which you can do with your equation is that you can take 1 common and then compare so everything becomes positive.you can also do it straight away :)
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
so, t = 8*√644*4  2*4 ?
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
which would then be t=8*(8+4)  8
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
am I getting it right?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
It should be + not *
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
I don't get it... wouldn't you be multiplying 8 and \[\pm √644*4\]?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
t=8(+)(8+4)  8
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
Now I'm rather confused.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Lemme show you.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
I appreciate you working with me though.
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
I guess I could do that \(\Huge\mathsf{:P}\)
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
a=4 b=8 c=1 \[\huge\ t=\frac{ (8) \pm \sqrt{(8)^24(4)(1)} }{ 2(4) }\]
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
Ok, but what does the \[\pm\] do? what's its significance?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Well when we simplify it we would be taking the adding part on one side and subracting part on the other side.
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
so it'd be 8+√blahblahblah  2(4)?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Either, 8+√blahblahblah  2(4)? Or, 8√blahblahblah  2(4)?
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
so the \[\pm\] just breaks up between the denominator and the numerator?
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
Ah. I guess I'll try another problem here and ask you if it's right or something.
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
\[\huge 0=2x ^{2} +14x +20\] \[\large x=\frac{ 14\pm \sqrt{14^2  4(2+20)} }{ 4 }\] \[\large x= \frac{ 14+1472 }{ 4 }\]
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
and the answer is \[\huge \frac{ 7\pm \sqrt{89} }{ 2 }\]. Would I be right?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Its is 4(a)(c) not 4(a+c)
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
oh. Well that ruins that then.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Yes it does :) Do it on a paper and tell me what you got from that equation :)
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
\[\Large x=\frac{ 14\pm \sqrt{14^2  4(2*20)} }{ 4 }\] \[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] \[\Large x=\frac{ 14\pm 14160} { 4}\] \[\Large x=\frac{ 14\pm 146} {4}\] set x to 0 and divide all by 2 to get \[\Large \frac{ 7\pm 73} { 2}\]
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
and now I'm confused.
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
oh wait, I forgot to keep the x's in there. Crap.
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
Think you could help me out here? My mind is about to implode.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
x=7+73/2,x=773/2
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Btw, () *()=+
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
So just because of signs it goes wrong.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
\[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] Continue from here.
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
But I left the xs out of my work. ._.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
No worries about that :)
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Continue working from here.
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
\[\Large x=\frac{ 14\pm 14  4(40)} { 4 }\] \[\Large x=\frac{ 14\pm 14+160} {4}\] \[\Large x=\frac{ 14\pm 174} {4}\] \[\Large x=\frac {\frac{ 14\pm 174} {4}} {2}\] \[\Large x=\frac {7\pm 87} {2}\]
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
And now what do I do?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
I don't know what you are upto ,where did that divide by 2 come in between ?
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
Well, I'm not sure. I just thought I had to do that. I'm rather confused ._.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.1
Hmm,If OS would be working on chrome i would have worked one problem for you. Can we do this later ?
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
I'm using chrome right now o_o But, I guess that'd be OK :P
 one year ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
Thanks to you too :3
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.