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BrookeScharn
Group Title
Use the quadratic formula to solve for
2x^27x5=0
 one year ago
 one year ago
BrookeScharn Group Title
Use the quadratic formula to solve for 2x^27x5=0
 one year ago
 one year ago

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AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
Well, what is the quadratic formula for a general quadratic: \(ax^2 + bx + c = 0\)?
 one year ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
Once we have that established, we simply have to plug in the corresponding a, b, and c into the formula and evaluate.
 one year ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
The quadratic formula is: \( \displaystyle x = \frac{b \pm \sqrt{b^2  4ac}}{2a} \) From here, it is simply taking the a, b, and c from the original equation and inserting them. Please respond if you are having any issues. :)
 one year ago
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