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haleyking345

  • one year ago

Use a half-angle identity to find the evact value of each function. A.) Tan 165 degrees I have tried and cannot come up with the right answer. Can I have some help?

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  1. haleyking345
    • one year ago
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    Exact not evact sorry

  2. tkhunny
    • one year ago
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    2*165º = 330º = 360º - 30º Reference Angle -30º

  3. exraven
    • one year ago
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    \[\tan \left( \frac{x}{2} \right) = \frac{\sin x}{1 + \cos x}\] plug x = 330º

  4. haleyking345
    • one year ago
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    i did that, and i checked the answer in the back and it did not go right. I messed up somewhere but i do not know where.

  5. exraven
    • one year ago
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    maybe you forgot to rationalize the denominator?

  6. tkhunny
    • one year ago
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    Did you consider the quadrant? 330º is Quadrant IV (Tangent is Negative). 165º is Quadrant II (Tangent is negative) Please show your work and we'll be able to see where you wander off.

  7. haleyking345
    • one year ago
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    |dw:1357957749155:dw|

  8. tkhunny
    • one year ago
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    @exraven wins. Just rationalize the denominator!

  9. haleyking345
    • one year ago
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    how do you do that?

  10. exraven
    • one year ago
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    multiply by the conjugate

  11. exraven
    • one year ago
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    \[\frac{-1}{2 +\sqrt{3}}\]multiply by \[\frac{2 -\sqrt{3}}{2 - \sqrt{3}}\]

  12. haleyking345
    • one year ago
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    the answer is square root 3 minus 2 in the book. I cannot quite get it to match

  13. tkhunny
    • one year ago
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    Again, let's see your work. We'll be able to tell where you wander off.

  14. haleyking345
    • one year ago
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    |dw:1357958794041:dw|

  15. exraven
    • one year ago
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    yes, what is the value of square root of 9?

  16. haleyking345
    • one year ago
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    3

  17. tkhunny
    • one year ago
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    That's it. Don't panic that it does not yet match the book. Keep going!

  18. exraven
    • one year ago
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    continue then

  19. haleyking345
    • one year ago
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    |dw:1357959061747:dw|

  20. exraven
    • one year ago
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    yes, you got it

  21. haleyking345
    • one year ago
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    Thank you

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