Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Need a confirm, please. Am I doing this right?

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

I would use my trusty Distance Formula, although I'm not sure which is which to plug in.
\[d = \sqrt(x _{2} - x _{1})^2 + (y _{2} - y _{1})^2\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[d = \sqrt (a - (-b)^{2} + (0 - c)^2\]
What is it that you are trying to do? Perimeter? Area? Other?
"Find the lengths of the diagonals of this trapezoid."
Okay, first, we should observe symmetry and decide that the two diagonals are the same length. Agreed?
Super. Now, it appears you started working with (a,0) and (-b,c). It also appears that you are having some notaiton problems. That's probably why you are struggling with it. There are parentheses missing. \(d = \sqrt{(a-(-b))^{2} + (0-c)^{2}} = \sqrt{(a+b)^{2}+(-c)^{2}}\) That's what you had, it's just written with all the symbols int eh right places. Can we do nything else with it?
Eh, no, that's precisely what I had in mind! :)
Thank you.
We might be able to do one more thing. Draw a perpendicular line from (b,c) down to the x-axis. You should see a right triangle. Can we say anything about the relationship of a, b, and c because of this right triangle?
|dw:1357966403862:dw| My drawing is not entirely accurate, but I only see a scalene triangle and equilateral triangle?
No, no, that't not perpendicular to the x-axis. It should hit the x-axis at (b,0), not at (0,0). It is a vertical line segment.
That's it. The one on the right is the one I was looking for. Anyway, my little right triangle leads to \((a-b)^{2} + c^{2} = (a-b)^{2} + (-c)^{2}\) and we don't manage to learn anything, so let's just let that go. It can be very useful to poke around a little. In this case, we didn't learn much, but it was worth the effort to learn to communicate better. :-)

Not the answer you are looking for?

Search for more explanations.

Ask your own question