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enya.gold Group Title

Need a confirm, please. Am I doing this right?

  • one year ago
  • one year ago

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  1. enya.gold Group Title
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    • one year ago
  2. enya.gold Group Title
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    I would use my trusty Distance Formula, although I'm not sure which is which to plug in.

    • one year ago
  3. enya.gold Group Title
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    \[d = \sqrt(x _{2} - x _{1})^2 + (y _{2} - y _{1})^2\]

    • one year ago
  4. enya.gold Group Title
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    \[d = \sqrt (a - (-b)^{2} + (0 - c)^2\]

    • one year ago
  5. tkhunny Group Title
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    What is it that you are trying to do? Perimeter? Area? Other?

    • one year ago
  6. enya.gold Group Title
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    "Find the lengths of the diagonals of this trapezoid."

    • one year ago
  7. tkhunny Group Title
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    Okay, first, we should observe symmetry and decide that the two diagonals are the same length. Agreed?

    • one year ago
  8. enya.gold Group Title
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    Yes.

    • one year ago
  9. tkhunny Group Title
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    Super. Now, it appears you started working with (a,0) and (-b,c). It also appears that you are having some notaiton problems. That's probably why you are struggling with it. There are parentheses missing. \(d = \sqrt{(a-(-b))^{2} + (0-c)^{2}} = \sqrt{(a+b)^{2}+(-c)^{2}}\) That's what you had, it's just written with all the symbols int eh right places. Can we do nything else with it?

    • one year ago
  10. enya.gold Group Title
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    Eh, no, that's precisely what I had in mind! :)

    • one year ago
  11. enya.gold Group Title
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    Thank you.

    • one year ago
  12. tkhunny Group Title
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    We might be able to do one more thing. Draw a perpendicular line from (b,c) down to the x-axis. You should see a right triangle. Can we say anything about the relationship of a, b, and c because of this right triangle?

    • one year ago
  13. enya.gold Group Title
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    |dw:1357966403862:dw| My drawing is not entirely accurate, but I only see a scalene triangle and equilateral triangle?

    • one year ago
  14. tkhunny Group Title
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    No, no, that't not perpendicular to the x-axis. It should hit the x-axis at (b,0), not at (0,0). It is a vertical line segment.

    • one year ago
  15. enya.gold Group Title
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    |dw:1357966687931:dw|

    • one year ago
  16. tkhunny Group Title
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    That's it. The one on the right is the one I was looking for. Anyway, my little right triangle leads to \((a-b)^{2} + c^{2} = (a-b)^{2} + (-c)^{2}\) and we don't manage to learn anything, so let's just let that go. It can be very useful to poke around a little. In this case, we didn't learn much, but it was worth the effort to learn to communicate better. :-)

    • one year ago
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is replying to Can someone tell me what button the professor is hitting...

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