singhmmm
A , B , E ARE POINTS ON CIRCLE AB IS DIAMETER WITH O AS A CENTRE AC AND BD ARE PERPENDICULARS ON A LINE PQ . BD MEETS THE CIRCLE AT E . PROVE THAT AC = ED
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hba
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@singhmmm A diag would be actually helpful use the draw tool :)
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mathslover
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well I think there are many possible diagrams. Since PQ line is not specified whether it lies inside the circle or outside or...
hba
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The 9 point diag from the Halls book may resemble :P
hba
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@singhmmm Would you mind replying ?
mathslover
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well this is not an easy stuff.
singhmmm
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@hba ..i didn' understand vat u r trying to say
mathslover
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@singhmmm did you try this question ?
singhmmm
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yup .
singhmmm
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diagram is not making clear..
singhmmm
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i don't know where to mark point E
mathslover
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mathslover
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since the question says that :
i) BD meets the circle at E
ii) PQ is a line ( nothing mentioned that it will be inside or outside the circle )
mathslover
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r u sure that it is AC = ED ? @singhmmm
singhmmm
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yup
singhmmm
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somehow i think ques.statement is wrong
singhmmm
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vat do u think
mathslover
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it 'might' be but m confused something about the diagram.
Not sure for wrong but I think something useful is missing
singhmmm
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kk
singhmmm
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thanks buddy
mathslover
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Your welcome but I have invited some experts who can help us. Don't close this quest. now and stay updated
mathslover
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I got it
experimentX
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mathslover
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Wait the diagram is wrong. Let me draw a correct one
mathslover
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mathslover
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now let us join AE
experimentX
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mathslover
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by property that angle AEB will be 90 degree
similarly all the angles in the quad. AEDC will be 90 degrees
experimentX
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yep!! correct mathlover!!
mathslover
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Therefore AEDC is a rectangle and AC = ED ( opposite sides of rectangle are equal )
mathslover
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Thanks @experimentX
singhmmm
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thank u so much @mathlover and experiment X
mathslover
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you are welcome @singhmmm , hope you enjoy this site. Best of luck.
singhmmm
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yup
singhmmm
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sme 2 u
mathslover
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thnks