anonymous
  • anonymous
A , B , E ARE POINTS ON CIRCLE AB IS DIAMETER WITH O AS A CENTRE AC AND BD ARE PERPENDICULARS ON A LINE PQ . BD MEETS THE CIRCLE AT E . PROVE THAT AC = ED
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
hba
  • hba
@singhmmm A diag would be actually helpful use the draw tool :) |dw:1357992984759:dw|
mathslover
  • mathslover
well I think there are many possible diagrams. Since PQ line is not specified whether it lies inside the circle or outside or...
hba
  • hba
The 9 point diag from the Halls book may resemble :P

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More answers

hba
  • hba
@singhmmm Would you mind replying ?
mathslover
  • mathslover
well this is not an easy stuff.
anonymous
  • anonymous
@hba ..i didn' understand vat u r trying to say
mathslover
  • mathslover
@singhmmm did you try this question ?
anonymous
  • anonymous
yup .
anonymous
  • anonymous
diagram is not making clear..
anonymous
  • anonymous
i don't know where to mark point E
mathslover
  • mathslover
|dw:1357993427560:dw|
mathslover
  • mathslover
since the question says that : i) BD meets the circle at E ii) PQ is a line ( nothing mentioned that it will be inside or outside the circle )
mathslover
  • mathslover
r u sure that it is AC = ED ? @singhmmm
anonymous
  • anonymous
yup
anonymous
  • anonymous
somehow i think ques.statement is wrong
anonymous
  • anonymous
vat do u think
mathslover
  • mathslover
it 'might' be but m confused something about the diagram. Not sure for wrong but I think something useful is missing
anonymous
  • anonymous
kk
anonymous
  • anonymous
thanks buddy
mathslover
  • mathslover
Your welcome but I have invited some experts who can help us. Don't close this quest. now and stay updated
mathslover
  • mathslover
I got it
experimentX
  • experimentX
|dw:1357994247928:dw|
mathslover
  • mathslover
Wait the diagram is wrong. Let me draw a correct one
mathslover
  • mathslover
|dw:1357994306561:dw|
mathslover
  • mathslover
|dw:1357994444885:dw| now let us join AE
experimentX
  • experimentX
|dw:1357994482792:dw|
mathslover
  • mathslover
by property that angle AEB will be 90 degree similarly all the angles in the quad. AEDC will be 90 degrees
experimentX
  • experimentX
yep!! correct mathlover!!
mathslover
  • mathslover
Therefore AEDC is a rectangle and AC = ED ( opposite sides of rectangle are equal )
mathslover
  • mathslover
Thanks @experimentX
anonymous
  • anonymous
thank u so much @mathlover and experiment X
mathslover
  • mathslover
you are welcome @singhmmm , hope you enjoy this site. Best of luck.
anonymous
  • anonymous
yup
anonymous
  • anonymous
sme 2 u
mathslover
  • mathslover
thnks

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