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singhmmm

A , B , E ARE POINTS ON CIRCLE AB IS DIAMETER WITH O AS A CENTRE AC AND BD ARE PERPENDICULARS ON A LINE PQ . BD MEETS THE CIRCLE AT E . PROVE THAT AC = ED

  • one year ago
  • one year ago

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  1. hba
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    @singhmmm A diag would be actually helpful use the draw tool :) |dw:1357992984759:dw|

    • one year ago
  2. mathslover
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    well I think there are many possible diagrams. Since PQ line is not specified whether it lies inside the circle or outside or...

    • one year ago
  3. hba
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    The 9 point diag from the Halls book may resemble :P

    • one year ago
  4. hba
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    @singhmmm Would you mind replying ?

    • one year ago
  5. mathslover
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    well this is not an easy stuff.

    • one year ago
  6. singhmmm
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    @hba ..i didn' understand vat u r trying to say

    • one year ago
  7. mathslover
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    @singhmmm did you try this question ?

    • one year ago
  8. singhmmm
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    yup .

    • one year ago
  9. singhmmm
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    diagram is not making clear..

    • one year ago
  10. singhmmm
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    i don't know where to mark point E

    • one year ago
  11. mathslover
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    |dw:1357993427560:dw|

    • one year ago
  12. mathslover
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    since the question says that : i) BD meets the circle at E ii) PQ is a line ( nothing mentioned that it will be inside or outside the circle )

    • one year ago
  13. mathslover
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    r u sure that it is AC = ED ? @singhmmm

    • one year ago
  14. singhmmm
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    yup

    • one year ago
  15. singhmmm
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    somehow i think ques.statement is wrong

    • one year ago
  16. singhmmm
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    vat do u think

    • one year ago
  17. mathslover
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    it 'might' be but m confused something about the diagram. Not sure for wrong but I think something useful is missing

    • one year ago
  18. singhmmm
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    kk

    • one year ago
  19. singhmmm
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    thanks buddy

    • one year ago
  20. mathslover
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    Your welcome but I have invited some experts who can help us. Don't close this quest. now and stay updated

    • one year ago
  21. mathslover
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    I got it

    • one year ago
  22. experimentX
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    |dw:1357994247928:dw|

    • one year ago
  23. mathslover
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    Wait the diagram is wrong. Let me draw a correct one

    • one year ago
  24. mathslover
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    |dw:1357994306561:dw|

    • one year ago
  25. mathslover
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    |dw:1357994444885:dw| now let us join AE

    • one year ago
  26. experimentX
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    |dw:1357994482792:dw|

    • one year ago
  27. mathslover
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    by property that angle AEB will be 90 degree similarly all the angles in the quad. AEDC will be 90 degrees

    • one year ago
  28. experimentX
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    yep!! correct mathlover!!

    • one year ago
  29. mathslover
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    Therefore AEDC is a rectangle and AC = ED ( opposite sides of rectangle are equal )

    • one year ago
  30. mathslover
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    Thanks @experimentX

    • one year ago
  31. singhmmm
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    thank u so much @mathlover and experiment X

    • one year ago
  32. mathslover
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    you are welcome @singhmmm , hope you enjoy this site. Best of luck.

    • one year ago
  33. singhmmm
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    yup

    • one year ago
  34. singhmmm
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    sme 2 u

    • one year ago
  35. mathslover
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    thnks

    • one year ago
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