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singhmmm
Group Title
A , B , E ARE POINTS ON CIRCLE AB IS DIAMETER WITH O AS A CENTRE AC AND BD ARE PERPENDICULARS ON A LINE PQ . BD MEETS THE CIRCLE AT E . PROVE THAT AC = ED
 one year ago
 one year ago
singhmmm Group Title
A , B , E ARE POINTS ON CIRCLE AB IS DIAMETER WITH O AS A CENTRE AC AND BD ARE PERPENDICULARS ON A LINE PQ . BD MEETS THE CIRCLE AT E . PROVE THAT AC = ED
 one year ago
 one year ago

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hba Group TitleBest ResponseYou've already chosen the best response.0
@singhmmm A diag would be actually helpful use the draw tool :) dw:1357992984759:dw
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
well I think there are many possible diagrams. Since PQ line is not specified whether it lies inside the circle or outside or...
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
The 9 point diag from the Halls book may resemble :P
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
@singhmmm Would you mind replying ?
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
well this is not an easy stuff.
 one year ago

singhmmm Group TitleBest ResponseYou've already chosen the best response.0
@hba ..i didn' understand vat u r trying to say
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
@singhmmm did you try this question ?
 one year ago

singhmmm Group TitleBest ResponseYou've already chosen the best response.0
diagram is not making clear..
 one year ago

singhmmm Group TitleBest ResponseYou've already chosen the best response.0
i don't know where to mark point E
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
dw:1357993427560:dw
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
since the question says that : i) BD meets the circle at E ii) PQ is a line ( nothing mentioned that it will be inside or outside the circle )
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
r u sure that it is AC = ED ? @singhmmm
 one year ago

singhmmm Group TitleBest ResponseYou've already chosen the best response.0
somehow i think ques.statement is wrong
 one year ago

singhmmm Group TitleBest ResponseYou've already chosen the best response.0
vat do u think
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
it 'might' be but m confused something about the diagram. Not sure for wrong but I think something useful is missing
 one year ago

singhmmm Group TitleBest ResponseYou've already chosen the best response.0
thanks buddy
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Your welcome but I have invited some experts who can help us. Don't close this quest. now and stay updated
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
I got it
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
dw:1357994247928:dw
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Wait the diagram is wrong. Let me draw a correct one
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
dw:1357994306561:dw
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
dw:1357994444885:dw now let us join AE
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
dw:1357994482792:dw
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
by property that angle AEB will be 90 degree similarly all the angles in the quad. AEDC will be 90 degrees
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
yep!! correct mathlover!!
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Therefore AEDC is a rectangle and AC = ED ( opposite sides of rectangle are equal )
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Thanks @experimentX
 one year ago

singhmmm Group TitleBest ResponseYou've already chosen the best response.0
thank u so much @mathlover and experiment X
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
you are welcome @singhmmm , hope you enjoy this site. Best of luck.
 one year ago
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