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anonymous
 3 years ago
A , B , E ARE POINTS ON CIRCLE AB IS DIAMETER WITH O AS A CENTRE AC AND BD ARE PERPENDICULARS ON A LINE PQ . BD MEETS THE CIRCLE AT E . PROVE THAT AC = ED
anonymous
 3 years ago
A , B , E ARE POINTS ON CIRCLE AB IS DIAMETER WITH O AS A CENTRE AC AND BD ARE PERPENDICULARS ON A LINE PQ . BD MEETS THE CIRCLE AT E . PROVE THAT AC = ED

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hba
 3 years ago
Best ResponseYou've already chosen the best response.0@singhmmm A diag would be actually helpful use the draw tool :) dw:1357992984759:dw

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2well I think there are many possible diagrams. Since PQ line is not specified whether it lies inside the circle or outside or...

hba
 3 years ago
Best ResponseYou've already chosen the best response.0The 9 point diag from the Halls book may resemble :P

hba
 3 years ago
Best ResponseYou've already chosen the best response.0@singhmmm Would you mind replying ?

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2well this is not an easy stuff.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@hba ..i didn' understand vat u r trying to say

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2@singhmmm did you try this question ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0diagram is not making clear..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i don't know where to mark point E

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1357993427560:dw

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2since the question says that : i) BD meets the circle at E ii) PQ is a line ( nothing mentioned that it will be inside or outside the circle )

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2r u sure that it is AC = ED ? @singhmmm

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0somehow i think ques.statement is wrong

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2it 'might' be but m confused something about the diagram. Not sure for wrong but I think something useful is missing

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2Your welcome but I have invited some experts who can help us. Don't close this quest. now and stay updated

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1357994247928:dw

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2Wait the diagram is wrong. Let me draw a correct one

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1357994306561:dw

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1357994444885:dw now let us join AE

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1357994482792:dw

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2by property that angle AEB will be 90 degree similarly all the angles in the quad. AEDC will be 90 degrees

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1yep!! correct mathlover!!

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2Therefore AEDC is a rectangle and AC = ED ( opposite sides of rectangle are equal )

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank u so much @mathlover and experiment X

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2you are welcome @singhmmm , hope you enjoy this site. Best of luck.
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