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erin512
Group Title
What is the maximum number of possible solutions for the system shown below?
 one year ago
 one year ago
erin512 Group Title
What is the maximum number of possible solutions for the system shown below?
 one year ago
 one year ago

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erin512 Group TitleBest ResponseYou've already chosen the best response.0
the choices are 1,2,3, and 4
 one year ago

amstro Group TitleBest ResponseYou've already chosen the best response.2
y^2=36x^2(1) Sub (1) into x^24y^2=64 x^24(36x^2)=64 x^2144+4x^2=64 5x^2=64+144 5x^2=208 x=(+/ sqrt 208/5) and then continue to sub in from here to find the number of solution
 one year ago

erin512 Group TitleBest ResponseYou've already chosen the best response.0
what would the final answer be in that case? @amstro
 one year ago

erin512 Group TitleBest ResponseYou've already chosen the best response.0
i will figure it out afterwards, i just need an answer quickly, please help
 one year ago

erin512 Group TitleBest ResponseYou've already chosen the best response.0
thank you :)
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
Hint: dw:1358003669486:dw
 one year ago

amstro Group TitleBest ResponseYou've already chosen the best response.2
@erin512 Im so sorry! There is no solution as y^2=36(+/ sqrt 208/5)^2> y^2=36(208/5) hence there will be no solution as the eqn is undefined
 one year ago

erin512 Group TitleBest ResponseYou've already chosen the best response.0
no problem! thank you though :) its a multiple choice question and there options are 1,2,3 or 4 solutions, so i'm not sure which it correct :(
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
@erin512 @amstro Without solving the equations, there is a maximum _possible_ solution of 4, since they are both second degree. The actual solution is zero, still < maximum possible. The question is very vague. I would put parameters a,b,c,d instead of numbers for the purpose of the question, such as x^2ay^2=64...
 one year ago

erin512 Group TitleBest ResponseYou've already chosen the best response.0
@mathmate thank you so much :) so do you think 4 would be the correct answer in this case?
 one year ago

erin512 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much :) i really appreciate it
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
you're welcome! :)
 one year ago
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