## anonymous 4 years ago A parallel-plate capacitor is constructed with circular plates of radius 6.3×10−2 m . The plates are separated by 0.23 mm, and the space between the plates is filled with a dielectric with dielectric constant . When the charge on the capacitor is 1.9 micro-coulomb the potential difference between the plates is 730 V . Find the value of dielectric constant.

1. anonymous

The capacitance of a parallel plate capacitor is given by, $C=kA \epsilon o/d$ Also directly ,C=Q/V Find C from second eqn and insert in the first one to find k, the dielectric constant

2. anonymous

is the answer 54? or am i wrong?

3. anonymous

Yes something like that .