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ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Might wanna use the product rule.

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.2Product Rule Indeed....

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Recall that it says \((fg)' = f'g + fg'\)

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.2\[x . \frac{ d}{ dx } \ln (x) + \ln(x) .\frac{ d }{ dx }(x)\]
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