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|dw:1358017831169:dw|

|dw:1358018149270:dw|

R is the range ..(X com) is the centre of mass of the system..

Centre of mass Will Be near to Heavier Body....

and using the Formula for Range i calculated Pos ( CM) = 960 m..ryt ?

The c.m. will finally be at R. It will follow a parabolic trajectory

The answer shuld be1120m

1120m

@ yahoo! ..i am sorry for this mistake ...

No Problem bro

4mR = m*R/2 + k*3m
hw R/2 ????????

here explosion is self explosion i.e no external force is here so we apply this method

Any Reason Behind it ?..

because small part is in rest and it will drop vertically downward at R/2 distance from origin

we also solve this problem using momentum conservation ...

If u Dont Mind..Can u Show ?

i appl that method..but didnt get the result

ok..|dw:1358020235037:dw|

|dw:1358020365409:dw|
|dw:1358020404165:dw|
and find k..

|dw:1358020473006:dw|

|dw:1358020525435:dw|

any query, yahoo!

Got it..! THXXX

now i am giving you a question which is similar to it ..you are interested to solve this

Thxx...Brother.....i will try to Solve it

ok... try it.

35 ??

y=-5cm

hw....?

Huh..Silly....Careless

No..i Dont think

Since it is moving..along Y-axis...it will have an Initial P

no in the question ,it has been given that the body is moving along horizontal direction i.e X-axis

If it was Along Y-Along

*Axis

where is your confusion???

Cleared...

|dw:1358022098651:dw|

y=k (let ) for 3m/4 mass
|dw:1358022439653:dw|

Got...It

ok..

Can u Take a luk at mmy Maths Question