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studygirl18

  • one year ago

so if it was t^8 (t^10)^0 thats t^8and t^10 I would add 8 and 10 so its t^18? am i right?

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  1. satellite73
    • one year ago
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    no

  2. studygirl18
    • one year ago
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    its t^80

  3. satellite73
    • one year ago
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    any number to the power of zero is 1

  4. satellite73
    • one year ago
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    \((t^8)^0=1\)

  5. studygirl18
    • one year ago
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    1x10=10 and 10x8= 80?

  6. satellite73
    • one year ago
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    you are raising \(t^8\) to the power of zero, not to the power of one

  7. satellite73
    • one year ago
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    \((t^8)^0=t^{8\times 0}=t^0=1\)

  8. studygirl18
    • one year ago
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    thats for the 10 i think

  9. satellite73
    • one year ago
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    in general \(b^0=1\) for any number \(b\) (unless \(b=0\) but that is a different story)

  10. satellite73
    • one year ago
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    my fault, but same idea

  11. satellite73
    • one year ago
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    \((t^{10})^0=t^0=1\)

  12. studygirl18
    • one year ago
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    so its just t^8?

  13. satellite73
    • one year ago
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    to you are left with \[t^8\times t^0=t^8\times 1=t^8\]

  14. satellite73
    • one year ago
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    yes, it is \(t^8\) you are right

  15. whpalmer4
    • one year ago
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    Think of it like t^2 = t*t, so t^1 = t*t/t = t and t^0 = t*t/(t*t) = 1

  16. studygirl18
    • one year ago
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    thxs you all

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