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anonymous
 4 years ago
so if it was t^8 (t^10)^0 thats t^8and t^10
I would add 8 and 10 so its t^18? am i right?
anonymous
 4 years ago
so if it was t^8 (t^10)^0 thats t^8and t^10 I would add 8 and 10 so its t^18? am i right?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0any number to the power of zero is 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01x10=10 and 10x8= 80?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are raising \(t^8\) to the power of zero, not to the power of one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\((t^8)^0=t^{8\times 0}=t^0=1\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats for the 10 i think

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in general \(b^0=1\) for any number \(b\) (unless \(b=0\) but that is a different story)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my fault, but same idea

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0to you are left with \[t^8\times t^0=t^8\times 1=t^8\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, it is \(t^8\) you are right

whpalmer4
 4 years ago
Best ResponseYou've already chosen the best response.0Think of it like t^2 = t*t, so t^1 = t*t/t = t and t^0 = t*t/(t*t) = 1
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