anonymous
  • anonymous
so if it was t^8 (t^10)^0 thats t^8and t^10 I would add 8 and 10 so its t^18? am i right?
Pre-Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
no
anonymous
  • anonymous
its t^80
anonymous
  • anonymous
any number to the power of zero is 1

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anonymous
  • anonymous
\((t^8)^0=1\)
anonymous
  • anonymous
1x10=10 and 10x8= 80?
anonymous
  • anonymous
you are raising \(t^8\) to the power of zero, not to the power of one
anonymous
  • anonymous
\((t^8)^0=t^{8\times 0}=t^0=1\)
anonymous
  • anonymous
thats for the 10 i think
anonymous
  • anonymous
in general \(b^0=1\) for any number \(b\) (unless \(b=0\) but that is a different story)
anonymous
  • anonymous
my fault, but same idea
anonymous
  • anonymous
\((t^{10})^0=t^0=1\)
anonymous
  • anonymous
so its just t^8?
anonymous
  • anonymous
to you are left with \[t^8\times t^0=t^8\times 1=t^8\]
anonymous
  • anonymous
yes, it is \(t^8\) you are right
whpalmer4
  • whpalmer4
Think of it like t^2 = t*t, so t^1 = t*t/t = t and t^0 = t*t/(t*t) = 1
anonymous
  • anonymous
thxs you all

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