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so if it was t^8 (t^10)^0 thats t^8and t^10 I would add 8 and 10 so its t^18? am i right?

Pre-Algebra
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no
its t^80
any number to the power of zero is 1

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Other answers:

\((t^8)^0=1\)
1x10=10 and 10x8= 80?
you are raising \(t^8\) to the power of zero, not to the power of one
\((t^8)^0=t^{8\times 0}=t^0=1\)
thats for the 10 i think
in general \(b^0=1\) for any number \(b\) (unless \(b=0\) but that is a different story)
my fault, but same idea
\((t^{10})^0=t^0=1\)
so its just t^8?
to you are left with \[t^8\times t^0=t^8\times 1=t^8\]
yes, it is \(t^8\) you are right
Think of it like t^2 = t*t, so t^1 = t*t/t = t and t^0 = t*t/(t*t) = 1
thxs you all

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