anonymous
  • anonymous
(3q^2)^4 my answer 3q^8 am I right I hope ?
Pre-Algebra
schrodinger
  • schrodinger
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anonymous
  • anonymous
When you have an exponent to a power, you multiply the exponents: \[(x ^{5})^{2}= x ^{10}\] And in your example, you're right!
anonymous
  • anonymous
thxs
campbell_st
  • campbell_st
you need to change 3 to 3^4 abd evaluate it the power of 4 is operating on the 3 and the q

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anonymous
  • anonymous
really?
anonymous
  • anonymous
you have to raise everything to the power of 4, not just the \(q^2\) part
campbell_st
  • campbell_st
your answer shows the power of 4 operating on q given your answer... the question would have been 3(q^2)^4
anonymous
  • anonymous
okay
anonymous
  • anonymous
believe @campbell_st he is right
anonymous
  • anonymous
\((ab)^n=a^nb^n\) so \((3q^2)^4=3^4q^8\)
anonymous
  • anonymous
12q^8 is the answer?
anonymous
  • anonymous
careful here
anonymous
  • anonymous
\(3^4\neq 3\times 4\) \[3^3=3\times 3\times 3\times 3\]
anonymous
  • anonymous
typo there, i meant \[3^4=3\times 3\times 3\times 3\]
anonymous
  • anonymous
oh 81 I see its 81q^8
anonymous
  • anonymous
yes it is
anonymous
  • anonymous
wow thxs

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