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What is the square root of minus 1.
When i do it in a scientific calculator, it says 'i' (imaginary unit) and i have no idea what that means
 one year ago
 one year ago
What is the square root of minus 1. When i do it in a scientific calculator, it says 'i' (imaginary unit) and i have no idea what that means
 one year ago
 one year ago

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awn786Best ResponseYou've already chosen the best response.1
\[\sqrt{1} = x \] what is the value of x
 one year ago

zaynahfBest ResponseYou've already chosen the best response.0
Imaginary numbers result when you are taking the square root of any negative number: For an example, \[\sqrt{1}\] = i \[\sqrt{25} = 5i\] The 'i' is kind of like the negative sign
 one year ago

awn786Best ResponseYou've already chosen the best response.1
so what is an imaginary unit
 one year ago

zaynahfBest ResponseYou've already chosen the best response.0
I know of a video you can watch if you want to
 one year ago

awn786Best ResponseYou've already chosen the best response.1
yes what is the vid @zaynahf
 one year ago

hbaBest ResponseYou've already chosen the best response.0
did you see the link @awn786 It has everything.
 one year ago

awn786Best ResponseYou've already chosen the best response.1
yes i did but what is an imaganary unit
 one year ago

zaynahfBest ResponseYou've already chosen the best response.0
1) http://www.youtube.com/watch?v=Iv_uzy4_gec 2)https://www.khanacademy.org/math/algebra/complexnumbers/complex_numbers/v/algebraiiimaginaryandcomplexnumbers?v=C2Ln0pK3kY
 one year ago

awn786Best ResponseYou've already chosen the best response.1
WOW OMG complicated @hba
 one year ago

zaynahfBest ResponseYou've already chosen the best response.0
The first link is really straight forward, try that
 one year ago

hbaBest ResponseYou've already chosen the best response.0
@awn786 Well,I tried to simplify and put everything :)
 one year ago

awn786Best ResponseYou've already chosen the best response.1
thanks for trying. @hba
 one year ago

awn786Best ResponseYou've already chosen the best response.1
listen and can u give a simple i word answer: \[\sqrt{1}=x\] what is the value of x in numbers.
 one year ago

hbaBest ResponseYou've already chosen the best response.0
I can help you understand what imaginary numbers are. So,the base of imaginary numbers is actually laid upon some of the things like \[\huge \ i=\sqrt{1}\] The other thing is \[\huge\ \omega=\frac{ 1+i \sqrt{3} }{ 2 }\]
 one year ago

hbaBest ResponseYou've already chosen the best response.0
We call this omega,It's derivations is given in my link :)
 one year ago

hbaBest ResponseYou've already chosen the best response.0
Now as per your question. x=root{1} x=i Here i is actually iota and it is an imaginary number.
 one year ago

hbaBest ResponseYou've already chosen the best response.0
@awn786 Please check the link i have provided. It has everything Please give it a read.
 one year ago

awn786Best ResponseYou've already chosen the best response.1
i said in numbers. your answer is basicly my question
 one year ago

hbaBest ResponseYou've already chosen the best response.0
Well,In numbers it is sqrt{1}
 one year ago

awn786Best ResponseYou've already chosen the best response.1
it should be easy shouldent it.
 one year ago

awn786Best ResponseYou've already chosen the best response.1
i dont understand ur link
 one year ago

hbaBest ResponseYou've already chosen the best response.0
I have already told you what omega is.
 one year ago

hbaBest ResponseYou've already chosen the best response.0
I said it is 1+i sqrt{3}/2
 one year ago

awn786Best ResponseYou've already chosen the best response.1
ok (i dont get it but ok) i' only in year 9 doing my gcse's
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
\[\sqrt{1}\] doesn't exist as a the REAL number you are asking for, because there's no number that you can square (because of the SQUARE root) and gives you 1
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
you just need to know what a square root is
 one year ago

awn786Best ResponseYou've already chosen the best response.1
i know what a square root is ofc
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
that's why there's no sqrt of ANY negative numbers, because everthing squared is BIGGER than 0
 one year ago

awn786Best ResponseYou've already chosen the best response.1
oh i get it so its an imaganary number because it cant exist?
 one year ago

awn786Best ResponseYou've already chosen the best response.1
you have the best responce
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
EXACTLY, it CAN'T EXIST as a "normal number"
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
so mathematicians around XVII century had to figure out another type of numbers, called COMPLEX numbers, and the first number of complex numbers is \[\sqrt{1}\]
 one year ago

awn786Best ResponseYou've already chosen the best response.1
you can bring the most complex thing and make others understand. are u sure ur not related to prfsr. brian cox
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
hahaha you amuse me, nothing is hard when you have an amazing teacher, and I have it right now.
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
you understand what I drew?
 one year ago

awn786Best ResponseYou've already chosen the best response.1
yeah u drew a number line. who is ur teacher
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
My uncle, who's been teaching maths since he was 15 and he's now 57, anyway, let's go back to our imagination
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
you put the axis pararell and it's perpendicular cutting in 0
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
that's why i said almost, because you figured out ANOTHER line, and that would make a 300 year old mathematician proud
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
because they CAN be negative in their new axis, the imaginary axis
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
it is not allowed to be a negative square root in the REAL line, but it is in the imaginary one
 one year ago

awn786Best ResponseYou've already chosen the best response.1
so in imaginative can they ever be 3i or always do they have to be 3i
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
so we just call it i, like we call 1 one
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
there are imaginary postive numbers and imaginary negative numbers, under 0
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
real negatives are at the left of 0, so why can't there be negative imaginary ones?
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
if you delete the minus inside of the root, it would be a real number then!
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
Yes that's what i was writting
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
and under 0 negative, i forgot to draw it
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
just like the real line but perpendicular
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
above 0 goes posstive until inifinity and under 0 negative until infinity
 one year ago

awn786Best ResponseYou've already chosen the best response.1
and on the real line is it same?
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
they are two separated lines.
 one year ago

awn786Best ResponseYou've already chosen the best response.1
bye i need to go. if i see u tommorw here i will carry on the conversation.
 one year ago

GCR92Best ResponseYou've already chosen the best response.2
okay, sure! bye! you are smart btw, you figured the other line very well.
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
i is actually an imaginary number used to give value to \[\sqrt{1}\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
\(i\) is defined as the imaginary number such that \(i^2 = 1\), not \(i= \sqrt{1}\).
 one year ago

awn786Best ResponseYou've already chosen the best response.1
and also its just common knowlige
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Yes, \(i\) is one of the square roots of \(1\). But \(i \ne \sqrt{1}\).
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
I mean, \(\sqrt{1} =i,i\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
So you must define \(i^2 = 1\) if you don't want things to mess up
 one year ago

awn786Best ResponseYou've already chosen the best response.1
wow gcr92 was WAY better at explaining things
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
What would you like to learn?
 one year ago

awn786Best ResponseYou've already chosen the best response.1
apparantly his teacher is hgis uncle who started teaching him maths when he was 15 an now is 50
 one year ago

awn786Best ResponseYou've already chosen the best response.1
look above^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
 one year ago

nikhilchabeBest ResponseYou've already chosen the best response.0
Here you go with the link for complete solution! http://www.learnalberta.ca/content/memg/Division03/Square%20Root/index.html
 one year ago

awn786Best ResponseYou've already chosen the best response.1
ermmm it needs to be simple
 one year ago
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