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anonymous
 3 years ago
What is the square root of minus 1.
When i do it in a scientific calculator, it says 'i' (imaginary unit) and i have no idea what that means
anonymous
 3 years ago
What is the square root of minus 1. When i do it in a scientific calculator, it says 'i' (imaginary unit) and i have no idea what that means

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{1} = x \] what is the value of x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0please dont put links

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Imaginary numbers result when you are taking the square root of any negative number: For an example, \[\sqrt{1}\] = i \[\sqrt{25} = 5i\] The 'i' is kind of like the negative sign

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what is an imaginary unit

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know of a video you can watch if you want to

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes what is the vid @zaynahf

hba
 3 years ago
Best ResponseYou've already chosen the best response.0did you see the link @awn786 It has everything.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i did but what is an imaganary unit

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01) http://www.youtube.com/watch?v=Iv_uzy4_gec 2) https://www.khanacademy.org/math/algebra/complexnumbers/complex_numbers/v/algebraiiimaginaryandcomplexnumbers?v=C2Ln0pK3kY

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0WOW OMG complicated @hba

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The first link is really straight forward, try that

hba
 3 years ago
Best ResponseYou've already chosen the best response.0@awn786 Well,I tried to simplify and put everything :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks for trying. @hba

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0listen and can u give a simple i word answer: \[\sqrt{1}=x\] what is the value of x in numbers.

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I can help you understand what imaginary numbers are. So,the base of imaginary numbers is actually laid upon some of the things like \[\huge \ i=\sqrt{1}\] The other thing is \[\huge\ \omega=\frac{ 1+i \sqrt{3} }{ 2 }\]

hba
 3 years ago
Best ResponseYou've already chosen the best response.0We call this omega,It's derivations is given in my link :)

hba
 3 years ago
Best ResponseYou've already chosen the best response.0Now as per your question. x=root{1} x=i Here i is actually iota and it is an imaginary number.

hba
 3 years ago
Best ResponseYou've already chosen the best response.0@awn786 Please check the link i have provided. It has everything Please give it a read.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i said in numbers. your answer is basicly my question

hba
 3 years ago
Best ResponseYou've already chosen the best response.0Well,In numbers it is sqrt{1}

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it should be easy shouldent it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont understand ur link

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I have already told you what omega is.

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I said it is 1+i sqrt{3}/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok (i dont get it but ok) i' only in year 9 doing my gcse's

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{1}\] doesn't exist as a the REAL number you are asking for, because there's no number that you can square (because of the SQUARE root) and gives you 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you just need to know what a square root is

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know what a square root is ofc

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's why there's no sqrt of ANY negative numbers, because everthing squared is BIGGER than 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh i get it so its an imaganary number because it cant exist?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have the best responce

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0EXACTLY, it CAN'T EXIST as a "normal number"

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so mathematicians around XVII century had to figure out another type of numbers, called COMPLEX numbers, and the first number of complex numbers is \[\sqrt{1}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not really, but thanks!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ill draw you something

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can bring the most complex thing and make others understand. are u sure ur not related to prfsr. brian cox

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358026644045:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hahaha you amuse me, nothing is hard when you have an amazing teacher, and I have it right now.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you understand what I drew?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah u drew a number line. who is ur teacher

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0My uncle, who's been teaching maths since he was 15 and he's now 57, anyway, let's go back to our imagination

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358026974868:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358027044754:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358027175723:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358027034198:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you put the axis pararell and it's perpendicular cutting in 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358027255837:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's why i said almost, because you figured out ANOTHER line, and that would make a 300 year old mathematician proud

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because they CAN be negative in their new axis, the imaginary axis

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is not allowed to be a negative square root in the REAL line, but it is in the imaginary one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so in imaginative can they ever be 3i or always do they have to be 3i

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so we just call it i, like we call 1 one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there are imaginary postive numbers and imaginary negative numbers, under 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0real negatives are at the left of 0, so why can't there be negative imaginary ones?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358027454145:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you delete the minus inside of the root, it would be a real number then!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes that's what i was writting

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and under 0 negative, i forgot to draw it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just like the real line but perpendicular

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0above 0 goes posstive until inifinity and under 0 negative until infinity

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and on the real line is it same?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358027632303:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0they are two separated lines.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0bye i need to go. if i see u tommorw here i will carry on the conversation.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, sure! bye! you are smart btw, you figured the other line very well.

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.0i is actually an imaginary number used to give value to \[\sqrt{1}\]

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0\(i\) is defined as the imaginary number such that \(i^2 = 1\), not \(i= \sqrt{1}\).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and also its just common knowlige

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, \(i\) is one of the square roots of \(1\). But \(i \ne \sqrt{1}\).

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0I mean, \(\sqrt{1} =i,i\)

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0So you must define \(i^2 = 1\) if you don't want things to mess up

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wow gcr92 was WAY better at explaining things

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0What would you like to learn?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0apparantly his teacher is hgis uncle who started teaching him maths when he was 15 an now is 50

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358591619083:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0look above^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Here you go with the link for complete solution! http://www.learnalberta.ca/content/memg/Division03/Square%20Root/index.html

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ermmm it needs to be simple
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