A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
What is the square root of minus 1.
When i do it in a scientific calculator, it says 'i' (imaginary unit) and i have no idea what that means
 one year ago
What is the square root of minus 1. When i do it in a scientific calculator, it says 'i' (imaginary unit) and i have no idea what that means

This Question is Closed

awn786
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{1} = x \] what is the value of x

zaynahf
 one year ago
Best ResponseYou've already chosen the best response.0Imaginary numbers result when you are taking the square root of any negative number: For an example, \[\sqrt{1}\] = i \[\sqrt{25} = 5i\] The 'i' is kind of like the negative sign

awn786
 one year ago
Best ResponseYou've already chosen the best response.1so what is an imaginary unit

zaynahf
 one year ago
Best ResponseYou've already chosen the best response.0I know of a video you can watch if you want to

awn786
 one year ago
Best ResponseYou've already chosen the best response.1yes what is the vid @zaynahf

hba
 one year ago
Best ResponseYou've already chosen the best response.0did you see the link @awn786 It has everything.

awn786
 one year ago
Best ResponseYou've already chosen the best response.1yes i did but what is an imaganary unit

zaynahf
 one year ago
Best ResponseYou've already chosen the best response.01) http://www.youtube.com/watch?v=Iv_uzy4_gec 2)https://www.khanacademy.org/math/algebra/complexnumbers/complex_numbers/v/algebraiiimaginaryandcomplexnumbers?v=C2Ln0pK3kY

awn786
 one year ago
Best ResponseYou've already chosen the best response.1WOW OMG complicated @hba

zaynahf
 one year ago
Best ResponseYou've already chosen the best response.0The first link is really straight forward, try that

hba
 one year ago
Best ResponseYou've already chosen the best response.0@awn786 Well,I tried to simplify and put everything :)

awn786
 one year ago
Best ResponseYou've already chosen the best response.1thanks for trying. @hba

awn786
 one year ago
Best ResponseYou've already chosen the best response.1listen and can u give a simple i word answer: \[\sqrt{1}=x\] what is the value of x in numbers.

hba
 one year ago
Best ResponseYou've already chosen the best response.0I can help you understand what imaginary numbers are. So,the base of imaginary numbers is actually laid upon some of the things like \[\huge \ i=\sqrt{1}\] The other thing is \[\huge\ \omega=\frac{ 1+i \sqrt{3} }{ 2 }\]

hba
 one year ago
Best ResponseYou've already chosen the best response.0We call this omega,It's derivations is given in my link :)

hba
 one year ago
Best ResponseYou've already chosen the best response.0Now as per your question. x=root{1} x=i Here i is actually iota and it is an imaginary number.

hba
 one year ago
Best ResponseYou've already chosen the best response.0@awn786 Please check the link i have provided. It has everything Please give it a read.

awn786
 one year ago
Best ResponseYou've already chosen the best response.1i said in numbers. your answer is basicly my question

hba
 one year ago
Best ResponseYou've already chosen the best response.0Well,In numbers it is sqrt{1}

awn786
 one year ago
Best ResponseYou've already chosen the best response.1it should be easy shouldent it.

awn786
 one year ago
Best ResponseYou've already chosen the best response.1i dont understand ur link

hba
 one year ago
Best ResponseYou've already chosen the best response.0I have already told you what omega is.

hba
 one year ago
Best ResponseYou've already chosen the best response.0I said it is 1+i sqrt{3}/2

awn786
 one year ago
Best ResponseYou've already chosen the best response.1ok (i dont get it but ok) i' only in year 9 doing my gcse's

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2\[\sqrt{1}\] doesn't exist as a the REAL number you are asking for, because there's no number that you can square (because of the SQUARE root) and gives you 1

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2you just need to know what a square root is

awn786
 one year ago
Best ResponseYou've already chosen the best response.1i know what a square root is ofc

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2that's why there's no sqrt of ANY negative numbers, because everthing squared is BIGGER than 0

awn786
 one year ago
Best ResponseYou've already chosen the best response.1oh i get it so its an imaganary number because it cant exist?

awn786
 one year ago
Best ResponseYou've already chosen the best response.1you have the best responce

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2EXACTLY, it CAN'T EXIST as a "normal number"

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2so mathematicians around XVII century had to figure out another type of numbers, called COMPLEX numbers, and the first number of complex numbers is \[\sqrt{1}\]

awn786
 one year ago
Best ResponseYou've already chosen the best response.1you can bring the most complex thing and make others understand. are u sure ur not related to prfsr. brian cox

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2hahaha you amuse me, nothing is hard when you have an amazing teacher, and I have it right now.

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2you understand what I drew?

awn786
 one year ago
Best ResponseYou've already chosen the best response.1yeah u drew a number line. who is ur teacher

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2My uncle, who's been teaching maths since he was 15 and he's now 57, anyway, let's go back to our imagination

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2you put the axis pararell and it's perpendicular cutting in 0

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2that's why i said almost, because you figured out ANOTHER line, and that would make a 300 year old mathematician proud

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2because they CAN be negative in their new axis, the imaginary axis

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2it is not allowed to be a negative square root in the REAL line, but it is in the imaginary one

awn786
 one year ago
Best ResponseYou've already chosen the best response.1so in imaginative can they ever be 3i or always do they have to be 3i

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2so we just call it i, like we call 1 one

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2there are imaginary postive numbers and imaginary negative numbers, under 0

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2real negatives are at the left of 0, so why can't there be negative imaginary ones?

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2if you delete the minus inside of the root, it would be a real number then!

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2Yes that's what i was writting

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2and under 0 negative, i forgot to draw it

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2just like the real line but perpendicular

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2above 0 goes posstive until inifinity and under 0 negative until infinity

awn786
 one year ago
Best ResponseYou've already chosen the best response.1and on the real line is it same?

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2they are two separated lines.

awn786
 one year ago
Best ResponseYou've already chosen the best response.1bye i need to go. if i see u tommorw here i will carry on the conversation.

GCR92
 one year ago
Best ResponseYou've already chosen the best response.2okay, sure! bye! you are smart btw, you figured the other line very well.

AravindG
 one year ago
Best ResponseYou've already chosen the best response.0i is actually an imaginary number used to give value to \[\sqrt{1}\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0\(i\) is defined as the imaginary number such that \(i^2 = 1\), not \(i= \sqrt{1}\).

awn786
 one year ago
Best ResponseYou've already chosen the best response.1and also its just common knowlige

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0Yes, \(i\) is one of the square roots of \(1\). But \(i \ne \sqrt{1}\).

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0I mean, \(\sqrt{1} =i,i\)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0So you must define \(i^2 = 1\) if you don't want things to mess up

awn786
 one year ago
Best ResponseYou've already chosen the best response.1wow gcr92 was WAY better at explaining things

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0What would you like to learn?

awn786
 one year ago
Best ResponseYou've already chosen the best response.1apparantly his teacher is hgis uncle who started teaching him maths when he was 15 an now is 50

awn786
 one year ago
Best ResponseYou've already chosen the best response.1look above^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

nikhilchabe
 one year ago
Best ResponseYou've already chosen the best response.0Here you go with the link for complete solution! http://www.learnalberta.ca/content/memg/Division03/Square%20Root/index.html

awn786
 one year ago
Best ResponseYou've already chosen the best response.1ermmm it needs to be simple
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.