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ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0i did this with u substituion it did not work

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0i am getting something like ln2/2

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1It looks to me more an atan(2x)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1The standard integral is \( \int \frac{dx}{1+x^2} = atan(x) + C \)

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358025284718:dw

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1So you'd be integrating \( \int \frac{du}{8u(1+4t^2)} \)

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0use the equation button

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1The result is not ln(u)

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0ok i should remember that formula right?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1I suggest you use y=2t

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Yes, it's on the first page of standard integrals. Check it out.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1\( \large \int_0^{1/2} \frac{dt}{1+4t^2}= \int_0^{1} \frac{2dy}{1+y^2} = [atan(y)]_0^{1}= 2\pi/4=\pi/2 \)

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0@mathmate i found the formula to be \[\frac{ 1 }{ a }\tan^{1} \frac{ x }{ a }+c\]

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\frac{ 1 }{ a^2+x^2}=\frac{ 1 }{ a }\tan^{1} \frac{ x }{ a}+c\]

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1x is your t. you can replace the identity with \( \large \int \frac{dx}{a^2+x^2} = \int \frac{dt}{a^2(1+(t/a)^2)} \)

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0can i do \[\frac{ 1 }{ 1 }\tan^{1} \frac{ 2t }{ 1}\]

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1t is a variable, and you cannot equate it to a constant. Use the formula you found, change t for x, and 1/2 for a, then the lefthand side is exactly your question. All you need to do after that is to evaluate the righthand side.
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