A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0i did this with u substituion it did not work

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0i am getting something like ln2/2

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1It looks to me more an atan(2x)

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1The standard integral is \( \int \frac{dx}{1+x^2} = atan(x) + C \)

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1358025284718:dw

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1So you'd be integrating \( \int \frac{du}{8u(1+4t^2)} \)

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0use the equation button

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1The result is not ln(u)

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0ok i should remember that formula right?

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1I suggest you use y=2t

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, it's on the first page of standard integrals. Check it out.

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1\( \large \int_0^{1/2} \frac{dt}{1+4t^2}= \int_0^{1} \frac{2dy}{1+y^2} = [atan(y)]_0^{1}= 2\pi/4=\pi/2 \)

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0@mathmate i found the formula to be \[\frac{ 1 }{ a }\tan^{1} \frac{ x }{ a }+c\]

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\frac{ 1 }{ a^2+x^2}=\frac{ 1 }{ a }\tan^{1} \frac{ x }{ a}+c\]

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1x is your t. you can replace the identity with \( \large \int \frac{dx}{a^2+x^2} = \int \frac{dt}{a^2(1+(t/a)^2)} \)

ksaimouli
 2 years ago
Best ResponseYou've already chosen the best response.0can i do \[\frac{ 1 }{ 1 }\tan^{1} \frac{ 2t }{ 1}\]

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.1t is a variable, and you cannot equate it to a constant. Use the formula you found, change t for x, and 1/2 for a, then the lefthand side is exactly your question. All you need to do after that is to evaluate the righthand side.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.