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chase3

  • 2 years ago

help

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  1. chase3
    • 2 years ago
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  2. wio
    • 2 years ago
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    They have a common denominator, that's nice.

  3. wio
    • 2 years ago
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    Try factoring the top one.

  4. chase3
    • 2 years ago
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    alright hold up a sec

  5. chase3
    • 2 years ago
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    t(1t+6) or somethin like that

  6. wio
    • 2 years ago
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    nope

  7. wio
    • 2 years ago
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    First you should subtract the fractions to get: \[ \frac{t^2+6t-7}{t-1} \]

  8. wio
    • 2 years ago
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    Then factor \[ t^2+6t-7 \]

  9. chase3
    • 2 years ago
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    t(-1+-6)

  10. wio
    • 2 years ago
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    not quite, but close

  11. chase3
    • 2 years ago
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    yea thats what i meant to say

  12. wio
    • 2 years ago
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    \((t-1)(t+7)\)

  13. chase3
    • 2 years ago
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    so thts the simplified answer

  14. wio
    • 2 years ago
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    \[ \frac{(t-1)(t+7)}{t-1} \]We have to divide.

  15. chase3
    • 2 years ago
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    so would the t-1 cancel each other

  16. wio
    • 2 years ago
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    yes

  17. chase3
    • 2 years ago
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    alright thanks

  18. chase3
    • 2 years ago
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    so the answer is (t+7)

  19. wio
    • 2 years ago
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    yes

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