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Find the image of the set S under the given transformation:
u=0, u=1, v=0, v=1, x=v, y=u(1+v^2)
 one year ago
 one year ago
Find the image of the set S under the given transformation: u=0, u=1, v=0, v=1, x=v, y=u(1+v^2)
 one year ago
 one year ago

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wioBest ResponseYou've already chosen the best response.1
plug in \(x(0,0), x(1,1), y(0,0), y(1,1)\)
 one year ago

WislarBest ResponseYou've already chosen the best response.0
Yes, that's the function. That's it?
 one year ago

vf321Best ResponseYou've already chosen the best response.1
No, that's the function. The image is the range of values you get from the "domain" S.
 one year ago

wioBest ResponseYou've already chosen the best response.1
Seems to me that \[ x(0,0) \leq x \leq x(1,1) \]
 one year ago

WislarBest ResponseYou've already chosen the best response.0
Alright, I have (0,0)>(0,0) (1,0)>(1,1) (0,1)>(0,0) (1,1)>(1,2) Is that it?
 one year ago

wioBest ResponseYou've already chosen the best response.1
Look at the highest and lowest of x and y.
 one year ago

vf321Best ResponseYou've already chosen the best response.1
@Wislar are you implying that \(S = \{0, 1\} \times \{0, 1\}\)? From your question, it seems to just be \(S = \{ (0,0), (1,1)\}\). Please clarify.
 one year ago

WislarBest ResponseYou've already chosen the best response.0
The points on the first image are (0,0), (1,0), (1,1), (0,1) which is a square and plugging those into the equations for x=v and y=u(1+v^2) to get those points
 one year ago

vf321Best ResponseYou've already chosen the best response.1
Then your image is the set of all the transformed points.
 one year ago

vf321Best ResponseYou've already chosen the best response.1
Well, I'm not going to check your arithmetic, but it should be the four points on the right side of your arrows in your above comment. Also make sure that \(S\) only relates to those four points, and is NOT defined by \(S = \{(u, v)  u \in [0,1] \land v \in [0,1]\}\)
 one year ago

WislarBest ResponseYou've already chosen the best response.0
That's what I did. Thanks!
 one year ago
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