ksaimouli
What is the average value of the function on the interval from x=3 to x=1



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ksaimouli
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@amorfide

mathmate
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The average value of the function would be
\(\large \int_{3}^{1} g(x)dx \)
Can you do the integration?

ksaimouli
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i exactly did that does not work

mathmate
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Sorry, the integral should be divided by (1 (3))=2 to get the average value.

ksaimouli
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?

mathmate
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what did you get?

mathmate
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Average value = \( \large \int_a^b f(x)dx / (ba) \)

ksaimouli
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28/6

mathmate
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You have the correct answer, but you need to simplify it (14/3) and divide by 2 which comes from (1(3)), the length of interval of integration.

mathmate
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In the end, you should get 7/3.

ksaimouli
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ya thx

mathmate
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@oldrin.bataku I think there was a mixup with the substituted limits of integration.

ksaimouli
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i got it

mathmate
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That's good! Keep it up!