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ksaimouli

What is the average value of the function on the interval from x=-3 to x=-1

  • one year ago
  • one year ago

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  1. ksaimouli
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    http://online.math.uh.edu/apcalculus/exams/images/AP_AB_version1__85.gif

    • one year ago
  2. ksaimouli
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    @amorfide

    • one year ago
  3. mathmate
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    The average value of the function would be \(\large \int_{-3}^{-1} g(x)dx \) Can you do the integration?

    • one year ago
  4. ksaimouli
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    i exactly did that does not work

    • one year ago
  5. mathmate
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    Sorry, the integral should be divided by (-1- (-3))=2 to get the average value.

    • one year ago
  6. ksaimouli
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    ?

    • one year ago
  7. mathmate
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    what did you get?

    • one year ago
  8. mathmate
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    Average value = \( \large \int_a^b f(x)dx / (b-a) \)

    • one year ago
  9. ksaimouli
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    28/6

    • one year ago
  10. mathmate
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    You have the correct answer, but you need to simplify it (14/3) and divide by 2 which comes from (-1-(-3)), the length of interval of integration.

    • one year ago
  11. mathmate
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    In the end, you should get 7/3.

    • one year ago
  12. ksaimouli
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    ya thx

    • one year ago
  13. mathmate
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    @oldrin.bataku I think there was a mix-up with the substituted limits of integration.

    • one year ago
  14. ksaimouli
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    i got it

    • one year ago
  15. mathmate
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    That's good! Keep it up!

    • one year ago
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