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ksaimouli
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What is the average value of the function on the interval from x=3 to x=1
 one year ago
 one year ago
ksaimouli Group Title
What is the average value of the function on the interval from x=3 to x=1
 one year ago
 one year ago

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ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
http://online.math.uh.edu/apcalculus/exams/images/AP_AB_version1__85.gif
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
@amorfide
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.2
The average value of the function would be \(\large \int_{3}^{1} g(x)dx \) Can you do the integration?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i exactly did that does not work
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.2
Sorry, the integral should be divided by (1 (3))=2 to get the average value.
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.2
what did you get?
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.2
Average value = \( \large \int_a^b f(x)dx / (ba) \)
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.2
You have the correct answer, but you need to simplify it (14/3) and divide by 2 which comes from (1(3)), the length of interval of integration.
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.2
In the end, you should get 7/3.
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.2
@oldrin.bataku I think there was a mixup with the substituted limits of integration.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i got it
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.2
That's good! Keep it up!
 one year ago
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