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ksaimouli

  • 3 years ago

What is the average value of the function on the interval from x=-3 to x=-1

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  1. ksaimouli
    • 3 years ago
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    http://online.math.uh.edu/apcalculus/exams/images/AP_AB_version1__85.gif

  2. ksaimouli
    • 3 years ago
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    @amorfide

  3. mathmate
    • 3 years ago
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    The average value of the function would be \(\large \int_{-3}^{-1} g(x)dx \) Can you do the integration?

  4. ksaimouli
    • 3 years ago
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    i exactly did that does not work

  5. mathmate
    • 3 years ago
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    Sorry, the integral should be divided by (-1- (-3))=2 to get the average value.

  6. ksaimouli
    • 3 years ago
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    ?

  7. mathmate
    • 3 years ago
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    what did you get?

  8. mathmate
    • 3 years ago
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    Average value = \( \large \int_a^b f(x)dx / (b-a) \)

  9. ksaimouli
    • 3 years ago
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    28/6

  10. mathmate
    • 3 years ago
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    You have the correct answer, but you need to simplify it (14/3) and divide by 2 which comes from (-1-(-3)), the length of interval of integration.

  11. mathmate
    • 3 years ago
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    In the end, you should get 7/3.

  12. ksaimouli
    • 3 years ago
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    ya thx

  13. mathmate
    • 3 years ago
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    @oldrin.bataku I think there was a mix-up with the substituted limits of integration.

  14. ksaimouli
    • 3 years ago
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    i got it

  15. mathmate
    • 3 years ago
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    That's good! Keep it up!

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