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Spartan_Of_Ares
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what is the value of the expression sqrt(27)+sqrt(32)sqrt(75)
 one year ago
 one year ago
Spartan_Of_Ares Group Title
what is the value of the expression sqrt(27)+sqrt(32)sqrt(75)
 one year ago
 one year ago

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Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt(27)+\sqrt(32)\sqrt(75)\]
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
@zaynahf if your not busy can you help me out?
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
Sure, i can! Do you know how to simplify radicals?
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
not really
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
>< 
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
To simplify radicals, you have to try to find a perfect square that fits perfectly into the number. So for the first one: \[\sqrt{27}\] the biggest perfect square that can fit into it is 9. So, the inside would simplify to be: \[\sqrt{9 \times 3} = 3\sqrt{3}\]
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
so i can get \[\sqrt16X2 = 4\sqrt2 ?\]
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
Yeah! Now try the third one
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt75 = \sqrt5X15 = 5\sqrt5?\]
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
No, since neither 15 nor 5 are perfect squares. Here are the perfect squares: 1,4,9,16,25,36,49,64,81,100....
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
so \[aaaannnnnd`im lost\]
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
lol i'll guide you through
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
ok
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
Ok since you want to get the biggest one that goes into there, start from the top of the list. Try seeing if 100 goes into 75 (obviously not), so just start from the smallest number after 75. 64,36,25,16,4,1. When you find the one that goes into 72, let me know.
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
64
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
64 goes into 75 evenly?
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
oh no 25
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
Good! Now what times 25 is 75?
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
So thats what goes under the radical: \[\sqrt{75}= \sqrt{25 \times 3}= 5\sqrt{3}\] Right?
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
ok what do i do now multiply them together?
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
\[3\sqrt{3}+4\sqrt{2}5\sqrt{3}\] Is that what you have so far?
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
yes
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
There are only 2 with the same base radical, so you can only simplify those
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
so i get \[8\sqrt3+ 4\sqrt2\]
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
Remember, it's 35, not 3+5
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
2√3+4√2
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
is that my final answer?
 one year ago

Spartan_Of_Ares Group TitleBest ResponseYou've already chosen the best response.0
thnxs so much ^_^ now i can sleep ... eh maybe
 one year ago

zaynahf Group TitleBest ResponseYou've already chosen the best response.2
No problem! Let me know if you need other help
 one year ago
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