Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ksaimouli Group Title

limts

  • one year ago
  • one year ago

  • This Question is Closed
  1. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    http://online.math.uh.edu/apcalculus/exams/images/AP_AB_version1__91.gif

    • one year ago
  2. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @tcarroll010

    • one year ago
  3. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You can use L'Hopital's rule whereby you take the limit of the derivative of the numerator over the limit of the derivative of the denominator. All with respect to "t".

    • one year ago
  4. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yes i did that but stuck

    • one year ago
  5. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Are you able to calculate the derivative of the numerator and the derivative of the denominator? You got stuck? Ok, I'll help a little further.

    • one year ago
  6. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so \[\sec(\frac{ \pi }{ 4 })^2-(\sec \frac{ \pi }{4 })^2\]

    • one year ago
  7. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

    • one year ago
  8. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    do u know what is the answer it is 2

    • one year ago
  9. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    but it is 2 i am sure

    • one year ago
  10. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The numerator goes to: sec^2 [(1/4)pi] as "t" goes to "0" So, yes, it goes to "2"

    • one year ago
  11. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes, definitely, "2" is the answer.

    • one year ago
  12. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    how did u get that

    • one year ago
  13. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The derivative of the numerator is: sec^2 [(1/4)pi + t] and that goes to: sec^2 [(1/4)pi] as "t" goes to "0" The derivative of the denominator is just "1" So, you deal with just: sec^2 [(1/4)pi] and that = 2

    • one year ago
  14. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    what did u do with other half sec^2 [(1/4)pi + t]- sec^2 [(1/4)pi )

    • one year ago
  15. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The other half is just a constant, so when you take the derivative of that, it disappears. That was where I made an initial mistake but I corrected that.

    • one year ago
  16. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    chain rule does not apply for the first one

    • one year ago
  17. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Here's a graph of the function and you can see that the limit is "2".

    • one year ago
    1 Attachment
  18. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The chain actually does apply to the first term, but it doesn't matter, because the derivative of (pi)/4 + t is just "1", so you are multiplying that derivative by "1", so it doesn't become apparent.

    • one year ago
  19. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    alright thx

    • one year ago
  20. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Thx for the recognition btw.

    • one year ago
  21. ksaimouli Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    for long conversation

    • one year ago
  22. tcarroll010 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    And you're welcome. Sorry I went off on a tangent (no pun intended) at the beginning.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.