## geerky42 2 years ago Help Needed

1. geerky42

2. Saikam

ok. Let the mass of the particle be m. Net force acting on a particle can be written as : $F = \frac{ dP }{ dt }$ where P is the momentum of the particle. Therefore, dP = Fdt $\int\limits_{Po}^{P} dP = \int\limits_{0}^{t}Fdt$ Therfore, $P2 - P1 = \int\limits_{0}^{t}Fdt$ Which means, change in momentum = area under the Force vs. Time graph. From the given graph, area under the graph = $(\frac{ 1 }{ 2 } * 3 * 8) + (3*8) + (\frac{ 1 }{ 2 }*3*8) = 48Ns$ initial momentum = mv = m*(-4.4) = -4.4m kgm/s Let final velocity be V. Therefore, final momentum = mV Therefore change in momentum = mV - (-4.4m) = m(V+4.4) kgm/s equating, m(V+4.4) = 48 If we know the mass of the particle, we can calculate its final velocity using this equation. If mass is not known, we cannot determine the final velocity

3. geerky42

Oh, mass is known, It was reminded in previous question. Thanks.