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A car weighing 1400kg accelerates from 90 km/hr to 110 km/hr in 6.0s.
a) assuming no friction, what was the power output of the car?
b) If a frictional force of 700 N acted on the car over a distance of 400 m during the same 6.0second acceleration, what would be the power output of the car if the same speed increase was observed?
 one year ago
 one year ago
A car weighing 1400kg accelerates from 90 km/hr to 110 km/hr in 6.0s. a) assuming no friction, what was the power output of the car? b) If a frictional force of 700 N acted on the car over a distance of 400 m during the same 6.0second acceleration, what would be the power output of the car if the same speed increase was observed?
 one year ago
 one year ago

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wioBest ResponseYou've already chosen the best response.2
Figure out it's change in kinetic energy.
 one year ago

wioBest ResponseYou've already chosen the best response.2
You have the mass and two velocities. So calculate the kinetic energy before and after acceleration.
 one year ago

wioBest ResponseYou've already chosen the best response.2
Power is just going to be energy / time
 one year ago

wioBest ResponseYou've already chosen the best response.2
kinetic energy is 1/2 mass * velocity^2
 one year ago

wioBest ResponseYou've already chosen the best response.2
You probably want to convert units to m/s
 one year ago

applesjgtlBest ResponseYou've already chosen the best response.0
Multiply by 1000 and divide by 3600?
 one year ago

wioBest ResponseYou've already chosen the best response.2
For b) " 700 N acted on the car over a distance of 400 m" Just remember that work = force * distance that will tell you how much energy was taken away
 one year ago

wioBest ResponseYou've already chosen the best response.2
so subtract that out and calculate the power again.
 one year ago

applesjgtlBest ResponseYou've already chosen the best response.0
For part a, what value do I use for energy? Is it KE2KE1?
 one year ago

wioBest ResponseYou've already chosen the best response.2
then divide the change in energy by time to get power output.
 one year ago

applesjgtlBest ResponseYou've already chosen the best response.0
Oh, I get it. Thanks for your help!
 one year ago
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