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anonymous
 4 years ago
A car weighing 1400kg accelerates from 90 km/hr to 110 km/hr in 6.0s.
a) assuming no friction, what was the power output of the car?
b) If a frictional force of 700 N acted on the car over a distance of 400 m during the same 6.0second acceleration, what would be the power output of the car if the same speed increase was observed?
anonymous
 4 years ago
A car weighing 1400kg accelerates from 90 km/hr to 110 km/hr in 6.0s. a) assuming no friction, what was the power output of the car? b) If a frictional force of 700 N acted on the car over a distance of 400 m during the same 6.0second acceleration, what would be the power output of the car if the same speed increase was observed?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Figure out it's change in kinetic energy.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You have the mass and two velocities. So calculate the kinetic energy before and after acceleration.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Power is just going to be energy / time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0kinetic energy is 1/2 mass * velocity^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You probably want to convert units to m/s

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Multiply by 1000 and divide by 3600?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For b) " 700 N acted on the car over a distance of 400 m" Just remember that work = force * distance that will tell you how much energy was taken away

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so subtract that out and calculate the power again.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For part a, what value do I use for energy? Is it KE2KE1?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For part a) use energy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then divide the change in energy by time to get power output.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, I get it. Thanks for your help!
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