A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
A car weighing 1400kg accelerates from 90 km/hr to 110 km/hr in 6.0s.
a) assuming no friction, what was the power output of the car?
b) If a frictional force of 700 N acted on the car over a distance of 400 m during the same 6.0second acceleration, what would be the power output of the car if the same speed increase was observed?
 2 years ago
A car weighing 1400kg accelerates from 90 km/hr to 110 km/hr in 6.0s. a) assuming no friction, what was the power output of the car? b) If a frictional force of 700 N acted on the car over a distance of 400 m during the same 6.0second acceleration, what would be the power output of the car if the same speed increase was observed?

This Question is Closed

wio
 2 years ago
Best ResponseYou've already chosen the best response.2Figure out it's change in kinetic energy.

wio
 2 years ago
Best ResponseYou've already chosen the best response.2You have the mass and two velocities. So calculate the kinetic energy before and after acceleration.

wio
 2 years ago
Best ResponseYou've already chosen the best response.2Power is just going to be energy / time

wio
 2 years ago
Best ResponseYou've already chosen the best response.2kinetic energy is 1/2 mass * velocity^2

wio
 2 years ago
Best ResponseYou've already chosen the best response.2You probably want to convert units to m/s

applesjgtl
 2 years ago
Best ResponseYou've already chosen the best response.0Multiply by 1000 and divide by 3600?

wio
 2 years ago
Best ResponseYou've already chosen the best response.2For b) " 700 N acted on the car over a distance of 400 m" Just remember that work = force * distance that will tell you how much energy was taken away

wio
 2 years ago
Best ResponseYou've already chosen the best response.2so subtract that out and calculate the power again.

applesjgtl
 2 years ago
Best ResponseYou've already chosen the best response.0For part a, what value do I use for energy? Is it KE2KE1?

wio
 2 years ago
Best ResponseYou've already chosen the best response.2then divide the change in energy by time to get power output.

applesjgtl
 2 years ago
Best ResponseYou've already chosen the best response.0Oh, I get it. Thanks for your help!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.