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MaeganR

Point-Slope Form: "Graph each equation."

  • one year ago
  • one year ago

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  1. MaeganR
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    #5. y-2=2(x+3) #6. y+3=-2(x+1) #7. y+1=-3/5(x+5)

    • one year ago
  2. DHASHNI
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    |dw:1358042338363:dw|

    • one year ago
  3. MaeganR
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    How do you show your work?

    • one year ago
  4. DHASHNI
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    i made a mistake !!!!!

    • one year ago
  5. MaeganR
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    :O

    • one year ago
  6. DHASHNI
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    buts its k i'll tell u how to plot

    • one year ago
  7. MaeganR
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    yeah i need to show my work too

    • one year ago
  8. DHASHNI
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    for the given equation u got to make up a table for getting the points

    • one year ago
  9. MaeganR
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    huh.?

    • one year ago
  10. MaeganR
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    ?

    • one year ago
  11. DHASHNI
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    for the given equation u got to make up a table for getting the points when u put x=0 in the given equation y value becomes 8 so , (0,8) is one of the points in the given straight line when u put y=0 in the given equation x value becomes 3 so, (3,0 ) is also one of the points in the given straight line|dw:1358043164412:dw|

    • one year ago
  12. DHASHNI
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    |dw:1358043209533:dw|

    • one year ago
  13. DHASHNI
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    and for the rest equation do the same u'll easily get plotted!

    • one year ago
  14. MaeganR
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    what the. im forever stupid. i hate math.

    • one year ago
  15. DHASHNI
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    huh.?

    • one year ago
  16. MaeganR
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    im so confused.

    • one year ago
  17. Azteck
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    #5. \[y=2x+8\] #6. \[y=-2x-5\] #7.\[y=-\frac{ 3 }{ 5 }-4\] |dw:1358111862798:dw| |dw:1358111959201:dw|

    • one year ago
  18. Azteck
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    The #7 had a mistype. \[y=-\frac{ 3 }{ 5 }x-4\] forgot the x.

    • one year ago
  19. MaeganR
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    How do you do that?

    • one year ago
  20. Azteck
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    Make sure when you draw the graphs, include the corresponding equation next to the line.

    • one year ago
  21. Azteck
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    Okay, please specify. Are you stuck with getting the equations into intercept form or are you stuck with the sketching onto the graph?

    • one year ago
  22. Azteck
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    Just to let you know I purposely haven't done #7 just to see where your mind is at. So if you're stuck with sketching we can go through #7 together as an example to make sure you understand.

    • one year ago
  23. Azteck
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    purposely didn't do*

    • one year ago
  24. MaeganR
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    #5 this is what I got when I did it: y -2= 2(x+3) 1 - 2 +2(1+3) 1-2=2(4) 1-2=8 (-8,-1)

    • one year ago
  25. MaeganR
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    1-2=2(1+3) Ooops.^

    • one year ago
  26. Azteck
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    okay, don't do that. That's a very slow way of sketching them. I got used to a method, where once you learn it completely, you can sketch the equation straight away in 10 seconds after looking at the equation.

    • one year ago
  27. MaeganR
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    how do you do that? and btw: is that correct anyways?

    • one year ago
  28. MaeganR
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    ?

    • one year ago
  29. Azteck
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    Okay, do you know how to put the equations in to point intercept form?

    • one year ago
  30. Azteck
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    y=mx+b where m is the gradient of the line, b is a constant.

    • one year ago
  31. MaeganR
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    y=mx+b is the formula, but i dont know how to do anything

    • one year ago
  32. Azteck
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    Okay, good.

    • one year ago
  33. Azteck
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    Do you know how to expand?

    • one year ago
  34. MaeganR
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    m is the slope ik that

    • one year ago
  35. MaeganR
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    what is expanding?

    • one year ago
  36. Azteck
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    Ah, okay. Now that is something your teacher should have taught you before all this sketching and stuff.

    • one year ago
  37. MaeganR
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    my teacher just teaches everything in the book. in fact, we dont even use books. she just teaches us on the board and thats how we "LEARN".

    • one year ago
  38. Azteck
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    #5. y-2=2(x+3) Expand this part: \[2(x+3)\]

    • one year ago
  39. Azteck
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    Don't you know how to remove the brackets?

    • one year ago
  40. MaeganR
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    is it also called distribute?

    • one year ago
  41. MaeganR
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    what is a bracket?

    • one year ago
  42. MaeganR
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    []?

    • one year ago
  43. Azteck
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    I think so. Because I'm probably not from your country where you might teach differently. I meant paranthesis. I just call it brackets because it's maths and maths teachers don't care about the technical terms of that stuff.

    • one year ago
  44. Azteck
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    Okay, If you expand/distribute \[2(x+3)\] Wouldn't you get \[2(x)+2(3)\]

    • one year ago
  45. Azteck
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    and then you get \[2x+6\]

    • one year ago
  46. MaeganR
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    yesh brb

    • one year ago
  47. MaeganR
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    ok so hi

    • one year ago
  48. MaeganR
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    #5. y-2=2(x+3) How do we do this?

    • one year ago
  49. Azteck
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    okay now, you have y-2=2x+6

    • one year ago
  50. MaeganR
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    yes

    • one year ago
  51. Azteck
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    you want to put that into y=mx+b. Wouldn't you have to move the -2 to the LHS(Left Hand Side)?

    • one year ago
  52. MaeganR
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    wait how do you get the y+3 to be y-2?

    • one year ago
  53. Azteck
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    what? where's that?

    • one year ago
  54. Azteck
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    You're looking at the second one. I'm at the first one.

    • one year ago
  55. MaeganR
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    nvm. sorrry i was looking at two different problems.

    • one year ago
  56. MaeganR
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    yeah lol

    • one year ago
  57. Azteck
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    Okay, so put \[y-2=2x+6\] into this form y=mx+b

    • one year ago
  58. MaeganR
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    is 2 m or is 6 m? 2?

    • one year ago
  59. MaeganR
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    because 6 would be b right?

    • one year ago
  60. Azteck
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    You're confusing me and we haven't started doing the other parts yet. Look at \[y−2=2x+6\]

    • one year ago
  61. Azteck
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    Now tell me what's the difference between this when you disregard the m's and b's in this equation: \[y=mx+b\]

    • one year ago
  62. MaeganR
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    y=x?

    • one year ago
  63. Azteck
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    Okay. Have you played a game called Spot The Difference? You're trying to find the difference between that equation and the first one.

    • one year ago
  64. Azteck
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    Come'on, this is the easiest form of mathematics at a standard level. You must know this in order to continue.

    • one year ago
  65. Azteck
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    Okay, here's something you should know. Collect the like terms.

    • one year ago
  66. Azteck
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    Do you know what collecting like terms is? Or have you not paid attention in class for a few years?

    • one year ago
  67. MaeganR
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    Ok. This is what ive done if it helps any.

    • one year ago
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  68. MaeganR
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    and its backwards.

    • one year ago
  69. Azteck
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    That's going to be hard to read don't you think. Okay, I'm asking you this sole question.

    • one year ago
  70. MaeganR
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    The teacher I have does not explain, she only gives us frayer diagrams to follow. This is why this is so confusing to me.

    • one year ago
  71. Azteck
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    Do you understand the statement: "Collecting like terms"

    • one year ago
  72. MaeganR
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    yeah

    • one year ago
  73. MaeganR
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    is y=2x+8 anything to do with the answer?

    • one year ago
  74. Azteck
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    Yes!! Great work!!!

    • one year ago
  75. Azteck
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    Now, this is the easy part. That's what I think.

    • one year ago
  76. MaeganR
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    so now what do i do to get it to be point-slope form?

    • one year ago
  77. Azteck
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    All you have to do when sketching is find the x and y intercepts!

    • one year ago
  78. Azteck
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    That is point-slope form?

    • one year ago
  79. MaeganR
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    ok so i can plug in like (1,1) and (3,3)?

    • one year ago
  80. Azteck
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    No!!!

    • one year ago
  81. MaeganR
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    y=2x+8 is slope-intercept form. I need it to be point-slope form which is y-y1=m(x-x1). Wait.. I think i know how to do that..

    • one year ago
  82. Azteck
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    Always when sketching lines, you start off by making x=0

    • one year ago
  83. Azteck
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    so that means, you substitute x with 0!

    • one year ago
  84. Azteck
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    y=2(0)+ 8

    • one year ago
  85. Azteck
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    Anything multiplied by 0 always gives you zero!!

    • one year ago
  86. Azteck
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    Now you found that when you substitute x with 0 you get y=8

    • one year ago
  87. Azteck
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    And your coordinates would be (0, 8). Because coordinates always look like this: (x, y)

    • one year ago
  88. MaeganR
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    i get it. y=2x+8 y=2(0)+8 y=0+8 y=8 !!! :D

    • one year ago
  89. Azteck
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    Yes!! Now that's called finding the y-intercept. What would you do to find the x-intercept? How would you eliminate y in order to find x?

    • one year ago
  90. MaeganR
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    whoa. whoa. whoa. hold up. let me think...

    • one year ago
  91. MaeganR
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    you would plug in 0 for y?

    • one year ago
  92. Azteck
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    WELL DONE! awesome job @MaeganR!

    • one year ago
  93. Azteck
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    So what would you get for x?

    • one year ago
  94. Azteck
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    when you plug in 0 into y?

    • one year ago
  95. MaeganR
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    let me solve it..

    • one year ago
  96. MaeganR
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    0=2x+8 is how you start right.?

    • one year ago
  97. Azteck
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    Yes.

    • one year ago
  98. MaeganR
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    -4=x !?!?!?!

    • one year ago
  99. Azteck
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    Yes!!!Correct!!

    • one year ago
  100. MaeganR
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    so it would be (-4,8) but how do you go up or down.?

    • one year ago
  101. Azteck
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    so now what would the co-ordinates of the x-intercept be? Remember the coordinates take in the shape of this: (x-value, y-value)

    • one year ago
  102. Azteck
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    Yes!

    • one year ago
  103. MaeganR
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    wait. slope=2 2/1 up 2 over 1?

    • one year ago
  104. Azteck
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    No!! Don't do that.

    • one year ago
  105. Azteck
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    Forget the slope when sketching.

    • one year ago
  106. MaeganR
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    but htats what my teacher says to do? ):

    • one year ago
  107. Azteck
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    Haha, when you go up to senior years, all you do is put important features when sketching. The sketch doesn't need to be 00% perfect and to scale.

    • one year ago
  108. Azteck
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    100%

    • one year ago
  109. MaeganR
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    im in 7th grade advanced, so were taking a 9th grade class in 7th grade. legit, no joke

    • one year ago
  110. MaeganR
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    oh. oh. oh. I get it.

    • one year ago
  111. Azteck
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    Then if you're in 7th grade advanced, you should be smart as hell. Taking a 9th grade class when you're in 7th grade would require some form of intelligence and dexterity at mathematics. You should know allt his because this is 7th grade maths.

    • one year ago
  112. MaeganR
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    so (-4,0) and (0,-8)!?!?!?!?!

    • one year ago
  113. Azteck
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    Yes.

    • one year ago
  114. Azteck
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    Now run run a line along the two points

    • one year ago
  115. Azteck
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    You don't need to be precise in your placement of the coordinates.

    • one year ago
  116. Azteck
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    but make sure the x and y intecept are on the x and y axis respectively.

    • one year ago
  117. MaeganR
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    but were not leaning 7th grade stuff. we wont learn 8th grade stuff either. its like 7th grade=9th grade 8thgrade=10th grade 9th grade=11th grade 10th grade=12th grade 11th+12th grade=college for free in high school. basically im skipping grades. its so confusing.

    • one year ago
  118. Azteck
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    Why are you skipping grades with this limited knowledge of maths? If you keep going at this rate, you're on the road to failure.

    • one year ago
  119. Azteck
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    That's my 2 cents.

    • one year ago
  120. MaeganR
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    yay. thank you so much. ive been so frustrated for a month because nobody would actually take the time to explain the whole thing to me in unbig scarey words. thank you so much. :)

    • one year ago
  121. Azteck
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    No worries. I think keeping it simple and just using baby talk always makes more sense than sophisticated and complicated words.

    • one year ago
  122. MaeganR
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    because i have to do this. theres no way out of the advanced program. once the school puts you in it without youre choice youre there, whether you fail or not.

    • one year ago
  123. MaeganR
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    yeah. always^.

    • one year ago
  124. MaeganR
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    im going to close the question now, but you can message me(:

    • one year ago
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