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MaeganR

  • 2 years ago

Point-Slope Form: "Graph each equation."

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  1. MaeganR
    • 2 years ago
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    #5. y-2=2(x+3) #6. y+3=-2(x+1) #7. y+1=-3/5(x+5)

  2. DHASHNI
    • 2 years ago
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    |dw:1358042338363:dw|

  3. MaeganR
    • 2 years ago
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    How do you show your work?

  4. DHASHNI
    • 2 years ago
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    i made a mistake !!!!!

  5. MaeganR
    • 2 years ago
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    :O

  6. DHASHNI
    • 2 years ago
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    buts its k i'll tell u how to plot

  7. MaeganR
    • 2 years ago
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    yeah i need to show my work too

  8. DHASHNI
    • 2 years ago
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    for the given equation u got to make up a table for getting the points

  9. MaeganR
    • 2 years ago
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    huh.?

  10. MaeganR
    • 2 years ago
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    ?

  11. DHASHNI
    • 2 years ago
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    for the given equation u got to make up a table for getting the points when u put x=0 in the given equation y value becomes 8 so , (0,8) is one of the points in the given straight line when u put y=0 in the given equation x value becomes 3 so, (3,0 ) is also one of the points in the given straight line|dw:1358043164412:dw|

  12. DHASHNI
    • 2 years ago
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    |dw:1358043209533:dw|

  13. DHASHNI
    • 2 years ago
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    and for the rest equation do the same u'll easily get plotted!

  14. MaeganR
    • 2 years ago
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    what the. im forever stupid. i hate math.

  15. DHASHNI
    • 2 years ago
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    huh.?

  16. MaeganR
    • 2 years ago
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    im so confused.

  17. Azteck
    • 2 years ago
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    #5. \[y=2x+8\] #6. \[y=-2x-5\] #7.\[y=-\frac{ 3 }{ 5 }-4\] |dw:1358111862798:dw| |dw:1358111959201:dw|

  18. Azteck
    • 2 years ago
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    The #7 had a mistype. \[y=-\frac{ 3 }{ 5 }x-4\] forgot the x.

  19. MaeganR
    • 2 years ago
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    How do you do that?

  20. Azteck
    • 2 years ago
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    Make sure when you draw the graphs, include the corresponding equation next to the line.

  21. Azteck
    • 2 years ago
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    Okay, please specify. Are you stuck with getting the equations into intercept form or are you stuck with the sketching onto the graph?

  22. Azteck
    • 2 years ago
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    Just to let you know I purposely haven't done #7 just to see where your mind is at. So if you're stuck with sketching we can go through #7 together as an example to make sure you understand.

  23. Azteck
    • 2 years ago
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    purposely didn't do*

  24. MaeganR
    • 2 years ago
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    #5 this is what I got when I did it: y -2= 2(x+3) 1 - 2 +2(1+3) 1-2=2(4) 1-2=8 (-8,-1)

  25. MaeganR
    • 2 years ago
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    1-2=2(1+3) Ooops.^

  26. Azteck
    • 2 years ago
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    okay, don't do that. That's a very slow way of sketching them. I got used to a method, where once you learn it completely, you can sketch the equation straight away in 10 seconds after looking at the equation.

  27. MaeganR
    • 2 years ago
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    how do you do that? and btw: is that correct anyways?

  28. MaeganR
    • 2 years ago
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    ?

  29. Azteck
    • 2 years ago
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    Okay, do you know how to put the equations in to point intercept form?

  30. Azteck
    • 2 years ago
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    y=mx+b where m is the gradient of the line, b is a constant.

  31. MaeganR
    • 2 years ago
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    y=mx+b is the formula, but i dont know how to do anything

  32. Azteck
    • 2 years ago
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    Okay, good.

  33. Azteck
    • 2 years ago
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    Do you know how to expand?

  34. MaeganR
    • 2 years ago
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    m is the slope ik that

  35. MaeganR
    • 2 years ago
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    what is expanding?

  36. Azteck
    • 2 years ago
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    Ah, okay. Now that is something your teacher should have taught you before all this sketching and stuff.

  37. MaeganR
    • 2 years ago
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    my teacher just teaches everything in the book. in fact, we dont even use books. she just teaches us on the board and thats how we "LEARN".

  38. Azteck
    • 2 years ago
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    #5. y-2=2(x+3) Expand this part: \[2(x+3)\]

  39. Azteck
    • 2 years ago
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    Don't you know how to remove the brackets?

  40. MaeganR
    • 2 years ago
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    is it also called distribute?

  41. MaeganR
    • 2 years ago
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    what is a bracket?

  42. MaeganR
    • 2 years ago
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    []?

  43. Azteck
    • 2 years ago
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    I think so. Because I'm probably not from your country where you might teach differently. I meant paranthesis. I just call it brackets because it's maths and maths teachers don't care about the technical terms of that stuff.

  44. Azteck
    • 2 years ago
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    Okay, If you expand/distribute \[2(x+3)\] Wouldn't you get \[2(x)+2(3)\]

  45. Azteck
    • 2 years ago
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    and then you get \[2x+6\]

  46. MaeganR
    • 2 years ago
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    yesh brb

  47. MaeganR
    • 2 years ago
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    ok so hi

  48. MaeganR
    • 2 years ago
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    #5. y-2=2(x+3) How do we do this?

  49. Azteck
    • 2 years ago
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    okay now, you have y-2=2x+6

  50. MaeganR
    • 2 years ago
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    yes

  51. Azteck
    • 2 years ago
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    you want to put that into y=mx+b. Wouldn't you have to move the -2 to the LHS(Left Hand Side)?

  52. MaeganR
    • 2 years ago
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    wait how do you get the y+3 to be y-2?

  53. Azteck
    • 2 years ago
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    what? where's that?

  54. Azteck
    • 2 years ago
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    You're looking at the second one. I'm at the first one.

  55. MaeganR
    • 2 years ago
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    nvm. sorrry i was looking at two different problems.

  56. MaeganR
    • 2 years ago
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    yeah lol

  57. Azteck
    • 2 years ago
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    Okay, so put \[y-2=2x+6\] into this form y=mx+b

  58. MaeganR
    • 2 years ago
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    is 2 m or is 6 m? 2?

  59. MaeganR
    • 2 years ago
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    because 6 would be b right?

  60. Azteck
    • 2 years ago
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    You're confusing me and we haven't started doing the other parts yet. Look at \[y−2=2x+6\]

  61. Azteck
    • 2 years ago
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    Now tell me what's the difference between this when you disregard the m's and b's in this equation: \[y=mx+b\]

  62. MaeganR
    • 2 years ago
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    y=x?

  63. Azteck
    • 2 years ago
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    Okay. Have you played a game called Spot The Difference? You're trying to find the difference between that equation and the first one.

  64. Azteck
    • 2 years ago
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    Come'on, this is the easiest form of mathematics at a standard level. You must know this in order to continue.

  65. Azteck
    • 2 years ago
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    Okay, here's something you should know. Collect the like terms.

  66. Azteck
    • 2 years ago
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    Do you know what collecting like terms is? Or have you not paid attention in class for a few years?

  67. MaeganR
    • 2 years ago
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    Ok. This is what ive done if it helps any.

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  68. MaeganR
    • 2 years ago
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    and its backwards.

  69. Azteck
    • 2 years ago
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    That's going to be hard to read don't you think. Okay, I'm asking you this sole question.

  70. MaeganR
    • 2 years ago
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    The teacher I have does not explain, she only gives us frayer diagrams to follow. This is why this is so confusing to me.

  71. Azteck
    • 2 years ago
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    Do you understand the statement: "Collecting like terms"

  72. MaeganR
    • 2 years ago
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    yeah

  73. MaeganR
    • 2 years ago
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    is y=2x+8 anything to do with the answer?

  74. Azteck
    • 2 years ago
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    Yes!! Great work!!!

  75. Azteck
    • 2 years ago
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    Now, this is the easy part. That's what I think.

  76. MaeganR
    • 2 years ago
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    so now what do i do to get it to be point-slope form?

  77. Azteck
    • 2 years ago
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    All you have to do when sketching is find the x and y intercepts!

  78. Azteck
    • 2 years ago
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    That is point-slope form?

  79. MaeganR
    • 2 years ago
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    ok so i can plug in like (1,1) and (3,3)?

  80. Azteck
    • 2 years ago
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    No!!!

  81. MaeganR
    • 2 years ago
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    y=2x+8 is slope-intercept form. I need it to be point-slope form which is y-y1=m(x-x1). Wait.. I think i know how to do that..

  82. Azteck
    • 2 years ago
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    Always when sketching lines, you start off by making x=0

  83. Azteck
    • 2 years ago
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    so that means, you substitute x with 0!

  84. Azteck
    • 2 years ago
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    y=2(0)+ 8

  85. Azteck
    • 2 years ago
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    Anything multiplied by 0 always gives you zero!!

  86. Azteck
    • 2 years ago
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    Now you found that when you substitute x with 0 you get y=8

  87. Azteck
    • 2 years ago
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    And your coordinates would be (0, 8). Because coordinates always look like this: (x, y)

  88. MaeganR
    • 2 years ago
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    i get it. y=2x+8 y=2(0)+8 y=0+8 y=8 !!! :D

  89. Azteck
    • 2 years ago
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    Yes!! Now that's called finding the y-intercept. What would you do to find the x-intercept? How would you eliminate y in order to find x?

  90. MaeganR
    • 2 years ago
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    whoa. whoa. whoa. hold up. let me think...

  91. MaeganR
    • 2 years ago
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    you would plug in 0 for y?

  92. Azteck
    • 2 years ago
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    WELL DONE! awesome job @MaeganR!

  93. Azteck
    • 2 years ago
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    So what would you get for x?

  94. Azteck
    • 2 years ago
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    when you plug in 0 into y?

  95. MaeganR
    • 2 years ago
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    let me solve it..

  96. MaeganR
    • 2 years ago
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    0=2x+8 is how you start right.?

  97. Azteck
    • 2 years ago
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    Yes.

  98. MaeganR
    • 2 years ago
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    -4=x !?!?!?!

  99. Azteck
    • 2 years ago
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    Yes!!!Correct!!

  100. MaeganR
    • 2 years ago
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    so it would be (-4,8) but how do you go up or down.?

  101. Azteck
    • 2 years ago
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    so now what would the co-ordinates of the x-intercept be? Remember the coordinates take in the shape of this: (x-value, y-value)

  102. Azteck
    • 2 years ago
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    Yes!

  103. MaeganR
    • 2 years ago
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    wait. slope=2 2/1 up 2 over 1?

  104. Azteck
    • 2 years ago
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    No!! Don't do that.

  105. Azteck
    • 2 years ago
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    Forget the slope when sketching.

  106. MaeganR
    • 2 years ago
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    but htats what my teacher says to do? ):

  107. Azteck
    • 2 years ago
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    Haha, when you go up to senior years, all you do is put important features when sketching. The sketch doesn't need to be 00% perfect and to scale.

  108. Azteck
    • 2 years ago
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    100%

  109. MaeganR
    • 2 years ago
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    im in 7th grade advanced, so were taking a 9th grade class in 7th grade. legit, no joke

  110. MaeganR
    • 2 years ago
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    oh. oh. oh. I get it.

  111. Azteck
    • 2 years ago
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    Then if you're in 7th grade advanced, you should be smart as hell. Taking a 9th grade class when you're in 7th grade would require some form of intelligence and dexterity at mathematics. You should know allt his because this is 7th grade maths.

  112. MaeganR
    • 2 years ago
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    so (-4,0) and (0,-8)!?!?!?!?!

  113. Azteck
    • 2 years ago
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    Yes.

  114. Azteck
    • 2 years ago
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    Now run run a line along the two points

  115. Azteck
    • 2 years ago
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    You don't need to be precise in your placement of the coordinates.

  116. Azteck
    • 2 years ago
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    but make sure the x and y intecept are on the x and y axis respectively.

  117. MaeganR
    • 2 years ago
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    but were not leaning 7th grade stuff. we wont learn 8th grade stuff either. its like 7th grade=9th grade 8thgrade=10th grade 9th grade=11th grade 10th grade=12th grade 11th+12th grade=college for free in high school. basically im skipping grades. its so confusing.

  118. Azteck
    • 2 years ago
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    Why are you skipping grades with this limited knowledge of maths? If you keep going at this rate, you're on the road to failure.

  119. Azteck
    • 2 years ago
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    That's my 2 cents.

  120. MaeganR
    • 2 years ago
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    yay. thank you so much. ive been so frustrated for a month because nobody would actually take the time to explain the whole thing to me in unbig scarey words. thank you so much. :)

  121. Azteck
    • 2 years ago
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    No worries. I think keeping it simple and just using baby talk always makes more sense than sophisticated and complicated words.

  122. MaeganR
    • 2 years ago
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    because i have to do this. theres no way out of the advanced program. once the school puts you in it without youre choice youre there, whether you fail or not.

  123. MaeganR
    • 2 years ago
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    yeah. always^.

  124. MaeganR
    • 2 years ago
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    im going to close the question now, but you can message me(:

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