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Point-Slope Form: "Graph each equation."

Linear Algebra
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#5. y-2=2(x+3) #6. y+3=-2(x+1) #7. y+1=-3/5(x+5)
|dw:1358042338363:dw|
How do you show your work?

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Other answers:

i made a mistake !!!!!
:O
buts its k i'll tell u how to plot
yeah i need to show my work too
for the given equation u got to make up a table for getting the points
huh.?
?
for the given equation u got to make up a table for getting the points when u put x=0 in the given equation y value becomes 8 so , (0,8) is one of the points in the given straight line when u put y=0 in the given equation x value becomes 3 so, (3,0 ) is also one of the points in the given straight line|dw:1358043164412:dw|
|dw:1358043209533:dw|
and for the rest equation do the same u'll easily get plotted!
what the. im forever stupid. i hate math.
huh.?
im so confused.
#5. \[y=2x+8\] #6. \[y=-2x-5\] #7.\[y=-\frac{ 3 }{ 5 }-4\] |dw:1358111862798:dw| |dw:1358111959201:dw|
The #7 had a mistype. \[y=-\frac{ 3 }{ 5 }x-4\] forgot the x.
How do you do that?
Make sure when you draw the graphs, include the corresponding equation next to the line.
Okay, please specify. Are you stuck with getting the equations into intercept form or are you stuck with the sketching onto the graph?
Just to let you know I purposely haven't done #7 just to see where your mind is at. So if you're stuck with sketching we can go through #7 together as an example to make sure you understand.
purposely didn't do*
#5 this is what I got when I did it: y -2= 2(x+3) 1 - 2 +2(1+3) 1-2=2(4) 1-2=8 (-8,-1)
1-2=2(1+3) Ooops.^
okay, don't do that. That's a very slow way of sketching them. I got used to a method, where once you learn it completely, you can sketch the equation straight away in 10 seconds after looking at the equation.
how do you do that? and btw: is that correct anyways?
?
Okay, do you know how to put the equations in to point intercept form?
y=mx+b where m is the gradient of the line, b is a constant.
y=mx+b is the formula, but i dont know how to do anything
Okay, good.
Do you know how to expand?
m is the slope ik that
what is expanding?
Ah, okay. Now that is something your teacher should have taught you before all this sketching and stuff.
my teacher just teaches everything in the book. in fact, we dont even use books. she just teaches us on the board and thats how we "LEARN".
#5. y-2=2(x+3) Expand this part: \[2(x+3)\]
Don't you know how to remove the brackets?
is it also called distribute?
what is a bracket?
[]?
I think so. Because I'm probably not from your country where you might teach differently. I meant paranthesis. I just call it brackets because it's maths and maths teachers don't care about the technical terms of that stuff.
Okay, If you expand/distribute \[2(x+3)\] Wouldn't you get \[2(x)+2(3)\]
and then you get \[2x+6\]
yesh brb
ok so hi
#5. y-2=2(x+3) How do we do this?
okay now, you have y-2=2x+6
yes
you want to put that into y=mx+b. Wouldn't you have to move the -2 to the LHS(Left Hand Side)?
wait how do you get the y+3 to be y-2?
what? where's that?
You're looking at the second one. I'm at the first one.
nvm. sorrry i was looking at two different problems.
yeah lol
Okay, so put \[y-2=2x+6\] into this form y=mx+b
is 2 m or is 6 m? 2?
because 6 would be b right?
You're confusing me and we haven't started doing the other parts yet. Look at \[y−2=2x+6\]
Now tell me what's the difference between this when you disregard the m's and b's in this equation: \[y=mx+b\]
y=x?
Okay. Have you played a game called Spot The Difference? You're trying to find the difference between that equation and the first one.
Come'on, this is the easiest form of mathematics at a standard level. You must know this in order to continue.
Okay, here's something you should know. Collect the like terms.
Do you know what collecting like terms is? Or have you not paid attention in class for a few years?
Ok. This is what ive done if it helps any.
1 Attachment
and its backwards.
That's going to be hard to read don't you think. Okay, I'm asking you this sole question.
The teacher I have does not explain, she only gives us frayer diagrams to follow. This is why this is so confusing to me.
Do you understand the statement: "Collecting like terms"
yeah
is y=2x+8 anything to do with the answer?
Yes!! Great work!!!
Now, this is the easy part. That's what I think.
so now what do i do to get it to be point-slope form?
All you have to do when sketching is find the x and y intercepts!
That is point-slope form?
ok so i can plug in like (1,1) and (3,3)?
No!!!
y=2x+8 is slope-intercept form. I need it to be point-slope form which is y-y1=m(x-x1). Wait.. I think i know how to do that..
Always when sketching lines, you start off by making x=0
so that means, you substitute x with 0!
y=2(0)+ 8
Anything multiplied by 0 always gives you zero!!
Now you found that when you substitute x with 0 you get y=8
And your coordinates would be (0, 8). Because coordinates always look like this: (x, y)
i get it. y=2x+8 y=2(0)+8 y=0+8 y=8 !!! :D
Yes!! Now that's called finding the y-intercept. What would you do to find the x-intercept? How would you eliminate y in order to find x?
whoa. whoa. whoa. hold up. let me think...
you would plug in 0 for y?
WELL DONE! awesome job @MaeganR!
So what would you get for x?
when you plug in 0 into y?
let me solve it..
0=2x+8 is how you start right.?
Yes.
-4=x !?!?!?!
Yes!!!Correct!!
so it would be (-4,8) but how do you go up or down.?
so now what would the co-ordinates of the x-intercept be? Remember the coordinates take in the shape of this: (x-value, y-value)
Yes!
wait. slope=2 2/1 up 2 over 1?
No!! Don't do that.
Forget the slope when sketching.
but htats what my teacher says to do? ):
Haha, when you go up to senior years, all you do is put important features when sketching. The sketch doesn't need to be 00% perfect and to scale.
100%
im in 7th grade advanced, so were taking a 9th grade class in 7th grade. legit, no joke
oh. oh. oh. I get it.
Then if you're in 7th grade advanced, you should be smart as hell. Taking a 9th grade class when you're in 7th grade would require some form of intelligence and dexterity at mathematics. You should know allt his because this is 7th grade maths.
so (-4,0) and (0,-8)!?!?!?!?!
Yes.
Now run run a line along the two points
You don't need to be precise in your placement of the coordinates.
but make sure the x and y intecept are on the x and y axis respectively.
but were not leaning 7th grade stuff. we wont learn 8th grade stuff either. its like 7th grade=9th grade 8thgrade=10th grade 9th grade=11th grade 10th grade=12th grade 11th+12th grade=college for free in high school. basically im skipping grades. its so confusing.
Why are you skipping grades with this limited knowledge of maths? If you keep going at this rate, you're on the road to failure.
That's my 2 cents.
yay. thank you so much. ive been so frustrated for a month because nobody would actually take the time to explain the whole thing to me in unbig scarey words. thank you so much. :)
No worries. I think keeping it simple and just using baby talk always makes more sense than sophisticated and complicated words.
because i have to do this. theres no way out of the advanced program. once the school puts you in it without youre choice youre there, whether you fail or not.
yeah. always^.
im going to close the question now, but you can message me(:

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