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MaeganR

  • one year ago

Point-Slope Form: "Graph each equation."

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  1. MaeganR
    • one year ago
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    #5. y-2=2(x+3) #6. y+3=-2(x+1) #7. y+1=-3/5(x+5)

  2. DHASHNI
    • one year ago
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    |dw:1358042338363:dw|

  3. MaeganR
    • one year ago
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    How do you show your work?

  4. DHASHNI
    • one year ago
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    i made a mistake !!!!!

  5. MaeganR
    • one year ago
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    :O

  6. DHASHNI
    • one year ago
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    buts its k i'll tell u how to plot

  7. MaeganR
    • one year ago
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    yeah i need to show my work too

  8. DHASHNI
    • one year ago
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    for the given equation u got to make up a table for getting the points

  9. MaeganR
    • one year ago
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    huh.?

  10. MaeganR
    • one year ago
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    ?

  11. DHASHNI
    • one year ago
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    for the given equation u got to make up a table for getting the points when u put x=0 in the given equation y value becomes 8 so , (0,8) is one of the points in the given straight line when u put y=0 in the given equation x value becomes 3 so, (3,0 ) is also one of the points in the given straight line|dw:1358043164412:dw|

  12. DHASHNI
    • one year ago
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    |dw:1358043209533:dw|

  13. DHASHNI
    • one year ago
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    and for the rest equation do the same u'll easily get plotted!

  14. MaeganR
    • one year ago
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    what the. im forever stupid. i hate math.

  15. DHASHNI
    • one year ago
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    huh.?

  16. MaeganR
    • one year ago
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    im so confused.

  17. Azteck
    • one year ago
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    #5. \[y=2x+8\] #6. \[y=-2x-5\] #7.\[y=-\frac{ 3 }{ 5 }-4\] |dw:1358111862798:dw| |dw:1358111959201:dw|

  18. Azteck
    • one year ago
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    The #7 had a mistype. \[y=-\frac{ 3 }{ 5 }x-4\] forgot the x.

  19. MaeganR
    • one year ago
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    How do you do that?

  20. Azteck
    • one year ago
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    Make sure when you draw the graphs, include the corresponding equation next to the line.

  21. Azteck
    • one year ago
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    Okay, please specify. Are you stuck with getting the equations into intercept form or are you stuck with the sketching onto the graph?

  22. Azteck
    • one year ago
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    Just to let you know I purposely haven't done #7 just to see where your mind is at. So if you're stuck with sketching we can go through #7 together as an example to make sure you understand.

  23. Azteck
    • one year ago
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    purposely didn't do*

  24. MaeganR
    • one year ago
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    #5 this is what I got when I did it: y -2= 2(x+3) 1 - 2 +2(1+3) 1-2=2(4) 1-2=8 (-8,-1)

  25. MaeganR
    • one year ago
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    1-2=2(1+3) Ooops.^

  26. Azteck
    • one year ago
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    okay, don't do that. That's a very slow way of sketching them. I got used to a method, where once you learn it completely, you can sketch the equation straight away in 10 seconds after looking at the equation.

  27. MaeganR
    • one year ago
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    how do you do that? and btw: is that correct anyways?

  28. MaeganR
    • one year ago
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    ?

  29. Azteck
    • one year ago
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    Okay, do you know how to put the equations in to point intercept form?

  30. Azteck
    • one year ago
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    y=mx+b where m is the gradient of the line, b is a constant.

  31. MaeganR
    • one year ago
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    y=mx+b is the formula, but i dont know how to do anything

  32. Azteck
    • one year ago
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    Okay, good.

  33. Azteck
    • one year ago
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    Do you know how to expand?

  34. MaeganR
    • one year ago
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    m is the slope ik that

  35. MaeganR
    • one year ago
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    what is expanding?

  36. Azteck
    • one year ago
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    Ah, okay. Now that is something your teacher should have taught you before all this sketching and stuff.

  37. MaeganR
    • one year ago
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    my teacher just teaches everything in the book. in fact, we dont even use books. she just teaches us on the board and thats how we "LEARN".

  38. Azteck
    • one year ago
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    #5. y-2=2(x+3) Expand this part: \[2(x+3)\]

  39. Azteck
    • one year ago
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    Don't you know how to remove the brackets?

  40. MaeganR
    • one year ago
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    is it also called distribute?

  41. MaeganR
    • one year ago
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    what is a bracket?

  42. MaeganR
    • one year ago
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    []?

  43. Azteck
    • one year ago
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    I think so. Because I'm probably not from your country where you might teach differently. I meant paranthesis. I just call it brackets because it's maths and maths teachers don't care about the technical terms of that stuff.

  44. Azteck
    • one year ago
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    Okay, If you expand/distribute \[2(x+3)\] Wouldn't you get \[2(x)+2(3)\]

  45. Azteck
    • one year ago
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    and then you get \[2x+6\]

  46. MaeganR
    • one year ago
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    yesh brb

  47. MaeganR
    • one year ago
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    ok so hi

  48. MaeganR
    • one year ago
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    #5. y-2=2(x+3) How do we do this?

  49. Azteck
    • one year ago
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    okay now, you have y-2=2x+6

  50. MaeganR
    • one year ago
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    yes

  51. Azteck
    • one year ago
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    you want to put that into y=mx+b. Wouldn't you have to move the -2 to the LHS(Left Hand Side)?

  52. MaeganR
    • one year ago
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    wait how do you get the y+3 to be y-2?

  53. Azteck
    • one year ago
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    what? where's that?

  54. Azteck
    • one year ago
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    You're looking at the second one. I'm at the first one.

  55. MaeganR
    • one year ago
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    nvm. sorrry i was looking at two different problems.

  56. MaeganR
    • one year ago
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    yeah lol

  57. Azteck
    • one year ago
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    Okay, so put \[y-2=2x+6\] into this form y=mx+b

  58. MaeganR
    • one year ago
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    is 2 m or is 6 m? 2?

  59. MaeganR
    • one year ago
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    because 6 would be b right?

  60. Azteck
    • one year ago
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    You're confusing me and we haven't started doing the other parts yet. Look at \[y−2=2x+6\]

  61. Azteck
    • one year ago
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    Now tell me what's the difference between this when you disregard the m's and b's in this equation: \[y=mx+b\]

  62. MaeganR
    • one year ago
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    y=x?

  63. Azteck
    • one year ago
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    Okay. Have you played a game called Spot The Difference? You're trying to find the difference between that equation and the first one.

  64. Azteck
    • one year ago
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    Come'on, this is the easiest form of mathematics at a standard level. You must know this in order to continue.

  65. Azteck
    • one year ago
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    Okay, here's something you should know. Collect the like terms.

  66. Azteck
    • one year ago
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    Do you know what collecting like terms is? Or have you not paid attention in class for a few years?

  67. MaeganR
    • one year ago
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    Ok. This is what ive done if it helps any.

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  68. MaeganR
    • one year ago
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    and its backwards.

  69. Azteck
    • one year ago
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    That's going to be hard to read don't you think. Okay, I'm asking you this sole question.

  70. MaeganR
    • one year ago
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    The teacher I have does not explain, she only gives us frayer diagrams to follow. This is why this is so confusing to me.

  71. Azteck
    • one year ago
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    Do you understand the statement: "Collecting like terms"

  72. MaeganR
    • one year ago
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    yeah

  73. MaeganR
    • one year ago
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    is y=2x+8 anything to do with the answer?

  74. Azteck
    • one year ago
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    Yes!! Great work!!!

  75. Azteck
    • one year ago
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    Now, this is the easy part. That's what I think.

  76. MaeganR
    • one year ago
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    so now what do i do to get it to be point-slope form?

  77. Azteck
    • one year ago
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    All you have to do when sketching is find the x and y intercepts!

  78. Azteck
    • one year ago
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    That is point-slope form?

  79. MaeganR
    • one year ago
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    ok so i can plug in like (1,1) and (3,3)?

  80. Azteck
    • one year ago
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    No!!!

  81. MaeganR
    • one year ago
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    y=2x+8 is slope-intercept form. I need it to be point-slope form which is y-y1=m(x-x1). Wait.. I think i know how to do that..

  82. Azteck
    • one year ago
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    Always when sketching lines, you start off by making x=0

  83. Azteck
    • one year ago
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    so that means, you substitute x with 0!

  84. Azteck
    • one year ago
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    y=2(0)+ 8

  85. Azteck
    • one year ago
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    Anything multiplied by 0 always gives you zero!!

  86. Azteck
    • one year ago
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    Now you found that when you substitute x with 0 you get y=8

  87. Azteck
    • one year ago
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    And your coordinates would be (0, 8). Because coordinates always look like this: (x, y)

  88. MaeganR
    • one year ago
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    i get it. y=2x+8 y=2(0)+8 y=0+8 y=8 !!! :D

  89. Azteck
    • one year ago
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    Yes!! Now that's called finding the y-intercept. What would you do to find the x-intercept? How would you eliminate y in order to find x?

  90. MaeganR
    • one year ago
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    whoa. whoa. whoa. hold up. let me think...

  91. MaeganR
    • one year ago
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    you would plug in 0 for y?

  92. Azteck
    • one year ago
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    WELL DONE! awesome job @MaeganR!

  93. Azteck
    • one year ago
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    So what would you get for x?

  94. Azteck
    • one year ago
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    when you plug in 0 into y?

  95. MaeganR
    • one year ago
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    let me solve it..

  96. MaeganR
    • one year ago
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    0=2x+8 is how you start right.?

  97. Azteck
    • one year ago
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    Yes.

  98. MaeganR
    • one year ago
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    -4=x !?!?!?!

  99. Azteck
    • one year ago
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    Yes!!!Correct!!

  100. MaeganR
    • one year ago
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    so it would be (-4,8) but how do you go up or down.?

  101. Azteck
    • one year ago
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    so now what would the co-ordinates of the x-intercept be? Remember the coordinates take in the shape of this: (x-value, y-value)

  102. Azteck
    • one year ago
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    Yes!

  103. MaeganR
    • one year ago
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    wait. slope=2 2/1 up 2 over 1?

  104. Azteck
    • one year ago
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    No!! Don't do that.

  105. Azteck
    • one year ago
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    Forget the slope when sketching.

  106. MaeganR
    • one year ago
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    but htats what my teacher says to do? ):

  107. Azteck
    • one year ago
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    Haha, when you go up to senior years, all you do is put important features when sketching. The sketch doesn't need to be 00% perfect and to scale.

  108. Azteck
    • one year ago
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    100%

  109. MaeganR
    • one year ago
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    im in 7th grade advanced, so were taking a 9th grade class in 7th grade. legit, no joke

  110. MaeganR
    • one year ago
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    oh. oh. oh. I get it.

  111. Azteck
    • one year ago
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    Then if you're in 7th grade advanced, you should be smart as hell. Taking a 9th grade class when you're in 7th grade would require some form of intelligence and dexterity at mathematics. You should know allt his because this is 7th grade maths.

  112. MaeganR
    • one year ago
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    so (-4,0) and (0,-8)!?!?!?!?!

  113. Azteck
    • one year ago
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    Yes.

  114. Azteck
    • one year ago
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    Now run run a line along the two points

  115. Azteck
    • one year ago
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    You don't need to be precise in your placement of the coordinates.

  116. Azteck
    • one year ago
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    but make sure the x and y intecept are on the x and y axis respectively.

  117. MaeganR
    • one year ago
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    but were not leaning 7th grade stuff. we wont learn 8th grade stuff either. its like 7th grade=9th grade 8thgrade=10th grade 9th grade=11th grade 10th grade=12th grade 11th+12th grade=college for free in high school. basically im skipping grades. its so confusing.

  118. Azteck
    • one year ago
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    Why are you skipping grades with this limited knowledge of maths? If you keep going at this rate, you're on the road to failure.

  119. Azteck
    • one year ago
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    That's my 2 cents.

  120. MaeganR
    • one year ago
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    yay. thank you so much. ive been so frustrated for a month because nobody would actually take the time to explain the whole thing to me in unbig scarey words. thank you so much. :)

  121. Azteck
    • one year ago
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    No worries. I think keeping it simple and just using baby talk always makes more sense than sophisticated and complicated words.

  122. MaeganR
    • one year ago
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    because i have to do this. theres no way out of the advanced program. once the school puts you in it without youre choice youre there, whether you fail or not.

  123. MaeganR
    • one year ago
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    yeah. always^.

  124. MaeganR
    • one year ago
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    im going to close the question now, but you can message me(:

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