MaeganR
  • MaeganR
Point-Slope Form: "Graph each equation."
Linear Algebra
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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MaeganR
  • MaeganR
#5. y-2=2(x+3) #6. y+3=-2(x+1) #7. y+1=-3/5(x+5)
anonymous
  • anonymous
|dw:1358042338363:dw|
MaeganR
  • MaeganR
How do you show your work?

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anonymous
  • anonymous
i made a mistake !!!!!
MaeganR
  • MaeganR
:O
anonymous
  • anonymous
buts its k i'll tell u how to plot
MaeganR
  • MaeganR
yeah i need to show my work too
anonymous
  • anonymous
for the given equation u got to make up a table for getting the points
MaeganR
  • MaeganR
huh.?
MaeganR
  • MaeganR
?
anonymous
  • anonymous
for the given equation u got to make up a table for getting the points when u put x=0 in the given equation y value becomes 8 so , (0,8) is one of the points in the given straight line when u put y=0 in the given equation x value becomes 3 so, (3,0 ) is also one of the points in the given straight line|dw:1358043164412:dw|
anonymous
  • anonymous
|dw:1358043209533:dw|
anonymous
  • anonymous
and for the rest equation do the same u'll easily get plotted!
MaeganR
  • MaeganR
what the. im forever stupid. i hate math.
anonymous
  • anonymous
huh.?
MaeganR
  • MaeganR
im so confused.
anonymous
  • anonymous
#5. \[y=2x+8\] #6. \[y=-2x-5\] #7.\[y=-\frac{ 3 }{ 5 }-4\] |dw:1358111862798:dw| |dw:1358111959201:dw|
anonymous
  • anonymous
The #7 had a mistype. \[y=-\frac{ 3 }{ 5 }x-4\] forgot the x.
MaeganR
  • MaeganR
How do you do that?
anonymous
  • anonymous
Make sure when you draw the graphs, include the corresponding equation next to the line.
anonymous
  • anonymous
Okay, please specify. Are you stuck with getting the equations into intercept form or are you stuck with the sketching onto the graph?
anonymous
  • anonymous
Just to let you know I purposely haven't done #7 just to see where your mind is at. So if you're stuck with sketching we can go through #7 together as an example to make sure you understand.
anonymous
  • anonymous
purposely didn't do*
MaeganR
  • MaeganR
#5 this is what I got when I did it: y -2= 2(x+3) 1 - 2 +2(1+3) 1-2=2(4) 1-2=8 (-8,-1)
MaeganR
  • MaeganR
1-2=2(1+3) Ooops.^
anonymous
  • anonymous
okay, don't do that. That's a very slow way of sketching them. I got used to a method, where once you learn it completely, you can sketch the equation straight away in 10 seconds after looking at the equation.
MaeganR
  • MaeganR
how do you do that? and btw: is that correct anyways?
MaeganR
  • MaeganR
?
anonymous
  • anonymous
Okay, do you know how to put the equations in to point intercept form?
anonymous
  • anonymous
y=mx+b where m is the gradient of the line, b is a constant.
MaeganR
  • MaeganR
y=mx+b is the formula, but i dont know how to do anything
anonymous
  • anonymous
Okay, good.
anonymous
  • anonymous
Do you know how to expand?
MaeganR
  • MaeganR
m is the slope ik that
MaeganR
  • MaeganR
what is expanding?
anonymous
  • anonymous
Ah, okay. Now that is something your teacher should have taught you before all this sketching and stuff.
MaeganR
  • MaeganR
my teacher just teaches everything in the book. in fact, we dont even use books. she just teaches us on the board and thats how we "LEARN".
anonymous
  • anonymous
#5. y-2=2(x+3) Expand this part: \[2(x+3)\]
anonymous
  • anonymous
Don't you know how to remove the brackets?
MaeganR
  • MaeganR
is it also called distribute?
MaeganR
  • MaeganR
what is a bracket?
MaeganR
  • MaeganR
[]?
anonymous
  • anonymous
I think so. Because I'm probably not from your country where you might teach differently. I meant paranthesis. I just call it brackets because it's maths and maths teachers don't care about the technical terms of that stuff.
anonymous
  • anonymous
Okay, If you expand/distribute \[2(x+3)\] Wouldn't you get \[2(x)+2(3)\]
anonymous
  • anonymous
and then you get \[2x+6\]
MaeganR
  • MaeganR
yesh brb
MaeganR
  • MaeganR
ok so hi
MaeganR
  • MaeganR
#5. y-2=2(x+3) How do we do this?
anonymous
  • anonymous
okay now, you have y-2=2x+6
MaeganR
  • MaeganR
yes
anonymous
  • anonymous
you want to put that into y=mx+b. Wouldn't you have to move the -2 to the LHS(Left Hand Side)?
MaeganR
  • MaeganR
wait how do you get the y+3 to be y-2?
anonymous
  • anonymous
what? where's that?
anonymous
  • anonymous
You're looking at the second one. I'm at the first one.
MaeganR
  • MaeganR
nvm. sorrry i was looking at two different problems.
MaeganR
  • MaeganR
yeah lol
anonymous
  • anonymous
Okay, so put \[y-2=2x+6\] into this form y=mx+b
MaeganR
  • MaeganR
is 2 m or is 6 m? 2?
MaeganR
  • MaeganR
because 6 would be b right?
anonymous
  • anonymous
You're confusing me and we haven't started doing the other parts yet. Look at \[y−2=2x+6\]
anonymous
  • anonymous
Now tell me what's the difference between this when you disregard the m's and b's in this equation: \[y=mx+b\]
MaeganR
  • MaeganR
y=x?
anonymous
  • anonymous
Okay. Have you played a game called Spot The Difference? You're trying to find the difference between that equation and the first one.
anonymous
  • anonymous
Come'on, this is the easiest form of mathematics at a standard level. You must know this in order to continue.
anonymous
  • anonymous
Okay, here's something you should know. Collect the like terms.
anonymous
  • anonymous
Do you know what collecting like terms is? Or have you not paid attention in class for a few years?
MaeganR
  • MaeganR
Ok. This is what ive done if it helps any.
1 Attachment
MaeganR
  • MaeganR
and its backwards.
anonymous
  • anonymous
That's going to be hard to read don't you think. Okay, I'm asking you this sole question.
MaeganR
  • MaeganR
The teacher I have does not explain, she only gives us frayer diagrams to follow. This is why this is so confusing to me.
anonymous
  • anonymous
Do you understand the statement: "Collecting like terms"
MaeganR
  • MaeganR
yeah
MaeganR
  • MaeganR
is y=2x+8 anything to do with the answer?
anonymous
  • anonymous
Yes!! Great work!!!
anonymous
  • anonymous
Now, this is the easy part. That's what I think.
MaeganR
  • MaeganR
so now what do i do to get it to be point-slope form?
anonymous
  • anonymous
All you have to do when sketching is find the x and y intercepts!
anonymous
  • anonymous
That is point-slope form?
MaeganR
  • MaeganR
ok so i can plug in like (1,1) and (3,3)?
anonymous
  • anonymous
No!!!
MaeganR
  • MaeganR
y=2x+8 is slope-intercept form. I need it to be point-slope form which is y-y1=m(x-x1). Wait.. I think i know how to do that..
anonymous
  • anonymous
Always when sketching lines, you start off by making x=0
anonymous
  • anonymous
so that means, you substitute x with 0!
anonymous
  • anonymous
y=2(0)+ 8
anonymous
  • anonymous
Anything multiplied by 0 always gives you zero!!
anonymous
  • anonymous
Now you found that when you substitute x with 0 you get y=8
anonymous
  • anonymous
And your coordinates would be (0, 8). Because coordinates always look like this: (x, y)
MaeganR
  • MaeganR
i get it. y=2x+8 y=2(0)+8 y=0+8 y=8 !!! :D
anonymous
  • anonymous
Yes!! Now that's called finding the y-intercept. What would you do to find the x-intercept? How would you eliminate y in order to find x?
MaeganR
  • MaeganR
whoa. whoa. whoa. hold up. let me think...
MaeganR
  • MaeganR
you would plug in 0 for y?
anonymous
  • anonymous
WELL DONE! awesome job @MaeganR!
anonymous
  • anonymous
So what would you get for x?
anonymous
  • anonymous
when you plug in 0 into y?
MaeganR
  • MaeganR
let me solve it..
MaeganR
  • MaeganR
0=2x+8 is how you start right.?
anonymous
  • anonymous
Yes.
MaeganR
  • MaeganR
-4=x !?!?!?!
anonymous
  • anonymous
Yes!!!Correct!!
MaeganR
  • MaeganR
so it would be (-4,8) but how do you go up or down.?
anonymous
  • anonymous
so now what would the co-ordinates of the x-intercept be? Remember the coordinates take in the shape of this: (x-value, y-value)
anonymous
  • anonymous
Yes!
MaeganR
  • MaeganR
wait. slope=2 2/1 up 2 over 1?
anonymous
  • anonymous
No!! Don't do that.
anonymous
  • anonymous
Forget the slope when sketching.
MaeganR
  • MaeganR
but htats what my teacher says to do? ):
anonymous
  • anonymous
Haha, when you go up to senior years, all you do is put important features when sketching. The sketch doesn't need to be 00% perfect and to scale.
anonymous
  • anonymous
100%
MaeganR
  • MaeganR
im in 7th grade advanced, so were taking a 9th grade class in 7th grade. legit, no joke
MaeganR
  • MaeganR
oh. oh. oh. I get it.
anonymous
  • anonymous
Then if you're in 7th grade advanced, you should be smart as hell. Taking a 9th grade class when you're in 7th grade would require some form of intelligence and dexterity at mathematics. You should know allt his because this is 7th grade maths.
MaeganR
  • MaeganR
so (-4,0) and (0,-8)!?!?!?!?!
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
Now run run a line along the two points
anonymous
  • anonymous
You don't need to be precise in your placement of the coordinates.
anonymous
  • anonymous
but make sure the x and y intecept are on the x and y axis respectively.
MaeganR
  • MaeganR
but were not leaning 7th grade stuff. we wont learn 8th grade stuff either. its like 7th grade=9th grade 8thgrade=10th grade 9th grade=11th grade 10th grade=12th grade 11th+12th grade=college for free in high school. basically im skipping grades. its so confusing.
anonymous
  • anonymous
Why are you skipping grades with this limited knowledge of maths? If you keep going at this rate, you're on the road to failure.
anonymous
  • anonymous
That's my 2 cents.
MaeganR
  • MaeganR
yay. thank you so much. ive been so frustrated for a month because nobody would actually take the time to explain the whole thing to me in unbig scarey words. thank you so much. :)
anonymous
  • anonymous
No worries. I think keeping it simple and just using baby talk always makes more sense than sophisticated and complicated words.
MaeganR
  • MaeganR
because i have to do this. theres no way out of the advanced program. once the school puts you in it without youre choice youre there, whether you fail or not.
MaeganR
  • MaeganR
yeah. always^.
MaeganR
  • MaeganR
im going to close the question now, but you can message me(:

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