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#5. y-2=2(x+3)
#6. y+3=-2(x+1)
#7. y+1=-3/5(x+5)

|dw:1358042338363:dw|

How do you show your work?

i made a mistake !!!!!

:O

buts its k i'll tell u how to plot

yeah i need to show my work too

for the given equation u got to make up a table for getting the points

huh.?

?

|dw:1358043209533:dw|

and for the rest equation do the same u'll easily get plotted!

what the. im forever stupid. i hate math.

huh.?

im so confused.

The #7 had a mistype.
\[y=-\frac{ 3 }{ 5 }x-4\]
forgot the x.

How do you do that?

Make sure when you draw the graphs, include the corresponding equation next to the line.

purposely didn't do*

#5
this is what I got when I did it:
y -2= 2(x+3)
1 - 2 +2(1+3)
1-2=2(4)
1-2=8
(-8,-1)

1-2=2(1+3) Ooops.^

how do you do that? and btw: is that correct anyways?

?

Okay, do you know how to put the equations in to point intercept form?

y=mx+b where m is the gradient of the line, b is a constant.

y=mx+b is the formula, but i dont know how to do anything

Okay, good.

Do you know how to expand?

m is the slope ik that

what is expanding?

#5. y-2=2(x+3)
Expand this part:
\[2(x+3)\]

Don't you know how to remove the brackets?

is it also called distribute?

what is a bracket?

[]?

Okay, If you expand/distribute \[2(x+3)\]
Wouldn't you get \[2(x)+2(3)\]

and then you get
\[2x+6\]

yesh brb

ok so hi

#5. y-2=2(x+3) How do we do this?

okay now, you have y-2=2x+6

yes

you want to put that into y=mx+b. Wouldn't you have to move the -2 to the LHS(Left Hand Side)?

wait how do you get the y+3 to be y-2?

what? where's that?

You're looking at the second one. I'm at the first one.

nvm. sorrry i was looking at two different problems.

yeah lol

Okay, so put
\[y-2=2x+6\]
into this form
y=mx+b

is 2 m or is 6 m? 2?

because 6 would be b right?

You're confusing me and we haven't started doing the other parts yet.
Look at \[yâˆ’2=2x+6\]

y=x?

Okay, here's something you should know. Collect the like terms.

Do you know what collecting like terms is? Or have you not paid attention in class for a few years?

Ok. This is what ive done if it helps any.

and its backwards.

That's going to be hard to read don't you think. Okay, I'm asking you this sole question.

Do you understand the statement: "Collecting like terms"

yeah

is y=2x+8 anything to do with the answer?

Yes!! Great work!!!

Now, this is the easy part. That's what I think.

so now what do i do to get it to be point-slope form?

All you have to do when sketching is find the x and y intercepts!

That is point-slope form?

ok so i can plug in like (1,1) and (3,3)?

No!!!

Always when sketching lines, you start off by making x=0

so that means, you substitute x with 0!

y=2(0)+ 8

Anything multiplied by 0 always gives you zero!!

Now you found that when you substitute x with 0 you get y=8

And your coordinates would be (0, 8). Because coordinates always look like this: (x, y)

i get it. y=2x+8 y=2(0)+8 y=0+8 y=8 !!! :D

whoa. whoa. whoa. hold up. let me think...

you would plug in 0 for y?

So what would you get for x?

when you plug in 0 into y?

let me solve it..

0=2x+8 is how you start right.?

Yes.

-4=x !?!?!?!

Yes!!!Correct!!

so it would be (-4,8) but how do you go up or down.?

Yes!

wait. slope=2 2/1 up 2 over 1?

No!! Don't do that.

Forget the slope when sketching.

but htats what my teacher says to do? ):

100%

im in 7th grade advanced, so were taking a 9th grade class in 7th grade. legit, no joke

oh. oh. oh. I get it.

so (-4,0) and (0,-8)!?!?!?!?!

Yes.

Now run run a line along the two points

You don't need to be precise in your placement of the coordinates.

but make sure the x and y intecept are on the x and y axis respectively.

That's my 2 cents.

yeah. always^.

im going to close the question now, but you can message me(: