Point-Slope Form:
"Graph each equation."

- MaeganR

Point-Slope Form:
"Graph each equation."

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- schrodinger

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- MaeganR

#5. y-2=2(x+3)
#6. y+3=-2(x+1)
#7. y+1=-3/5(x+5)

- anonymous

|dw:1358042338363:dw|

- MaeganR

How do you show your work?

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## More answers

- anonymous

i made a mistake !!!!!

- MaeganR

:O

- anonymous

buts its k i'll tell u how to plot

- MaeganR

yeah i need to show my work too

- anonymous

for the given equation u got to make up a table for getting the points

- MaeganR

huh.?

- MaeganR

?

- anonymous

for the given equation u got to make up a table for getting the points
when u put x=0 in the given equation
y value becomes 8
so , (0,8) is one of the points in the given straight line
when u put y=0 in the given equation
x value becomes 3
so, (3,0 ) is also one of the points in the given straight line|dw:1358043164412:dw|

- anonymous

|dw:1358043209533:dw|

- anonymous

and for the rest equation do the same u'll easily get plotted!

- MaeganR

what the. im forever stupid. i hate math.

- anonymous

huh.?

- MaeganR

im so confused.

- anonymous

#5. \[y=2x+8\]
#6. \[y=-2x-5\]
#7.\[y=-\frac{ 3 }{ 5 }-4\]
|dw:1358111862798:dw|
|dw:1358111959201:dw|

- anonymous

The #7 had a mistype.
\[y=-\frac{ 3 }{ 5 }x-4\]
forgot the x.

- MaeganR

How do you do that?

- anonymous

Make sure when you draw the graphs, include the corresponding equation next to the line.

- anonymous

Okay, please specify. Are you stuck with getting the equations into intercept form or are you stuck with the sketching onto the graph?

- anonymous

Just to let you know I purposely haven't done #7 just to see where your mind is at. So if you're stuck with sketching we can go through #7 together as an example to make sure you understand.

- anonymous

purposely didn't do*

- MaeganR

#5
this is what I got when I did it:
y -2= 2(x+3)
1 - 2 +2(1+3)
1-2=2(4)
1-2=8
(-8,-1)

- MaeganR

1-2=2(1+3) Ooops.^

- anonymous

okay, don't do that. That's a very slow way of sketching them. I got used to a method, where once you learn it completely, you can sketch the equation straight away in 10 seconds after looking at the equation.

- MaeganR

how do you do that? and btw: is that correct anyways?

- MaeganR

?

- anonymous

Okay, do you know how to put the equations in to point intercept form?

- anonymous

y=mx+b where m is the gradient of the line, b is a constant.

- MaeganR

y=mx+b is the formula, but i dont know how to do anything

- anonymous

Okay, good.

- anonymous

Do you know how to expand?

- MaeganR

m is the slope ik that

- MaeganR

what is expanding?

- anonymous

Ah, okay. Now that is something your teacher should have taught you before all this sketching and stuff.

- MaeganR

my teacher just teaches everything in the book. in fact, we dont even use books. she just teaches us on the board and thats how we "LEARN".

- anonymous

#5. y-2=2(x+3)
Expand this part:
\[2(x+3)\]

- anonymous

Don't you know how to remove the brackets?

- MaeganR

is it also called distribute?

- MaeganR

what is a bracket?

- MaeganR

[]?

- anonymous

I think so. Because I'm probably not from your country where you might teach differently. I meant paranthesis. I just call it brackets because it's maths and maths teachers don't care about the technical terms of that stuff.

- anonymous

Okay, If you expand/distribute \[2(x+3)\]
Wouldn't you get \[2(x)+2(3)\]

- anonymous

and then you get
\[2x+6\]

- MaeganR

yesh brb

- MaeganR

ok so hi

- MaeganR

#5. y-2=2(x+3) How do we do this?

- anonymous

okay now, you have y-2=2x+6

- MaeganR

yes

- anonymous

you want to put that into y=mx+b. Wouldn't you have to move the -2 to the LHS(Left Hand Side)?

- MaeganR

wait how do you get the y+3 to be y-2?

- anonymous

what? where's that?

- anonymous

You're looking at the second one. I'm at the first one.

- MaeganR

nvm. sorrry i was looking at two different problems.

- MaeganR

yeah lol

- anonymous

Okay, so put
\[y-2=2x+6\]
into this form
y=mx+b

- MaeganR

is 2 m or is 6 m? 2?

- MaeganR

because 6 would be b right?

- anonymous

You're confusing me and we haven't started doing the other parts yet.
Look at \[yâˆ’2=2x+6\]

- anonymous

Now tell me what's the difference between this when you disregard the m's and b's in this equation:
\[y=mx+b\]

- MaeganR

y=x?

- anonymous

Okay. Have you played a game called Spot The Difference? You're trying to find the difference between that equation and the first one.

- anonymous

Come'on, this is the easiest form of mathematics at a standard level. You must know this in order to continue.

- anonymous

Okay, here's something you should know. Collect the like terms.

- anonymous

Do you know what collecting like terms is? Or have you not paid attention in class for a few years?

- MaeganR

Ok. This is what ive done if it helps any.

##### 1 Attachment

- MaeganR

and its backwards.

- anonymous

That's going to be hard to read don't you think. Okay, I'm asking you this sole question.

- MaeganR

The teacher I have does not explain, she only gives us frayer diagrams to follow. This is why this is so confusing to me.

- anonymous

Do you understand the statement: "Collecting like terms"

- MaeganR

yeah

- MaeganR

is y=2x+8 anything to do with the answer?

- anonymous

Yes!! Great work!!!

- anonymous

Now, this is the easy part. That's what I think.

- MaeganR

so now what do i do to get it to be point-slope form?

- anonymous

All you have to do when sketching is find the x and y intercepts!

- anonymous

That is point-slope form?

- MaeganR

ok so i can plug in like (1,1) and (3,3)?

- anonymous

No!!!

- MaeganR

y=2x+8 is slope-intercept form. I need it to be point-slope form which is y-y1=m(x-x1). Wait.. I think i know how to do that..

- anonymous

Always when sketching lines, you start off by making x=0

- anonymous

so that means, you substitute x with 0!

- anonymous

y=2(0)+ 8

- anonymous

Anything multiplied by 0 always gives you zero!!

- anonymous

Now you found that when you substitute x with 0 you get y=8

- anonymous

And your coordinates would be (0, 8). Because coordinates always look like this: (x, y)

- MaeganR

i get it. y=2x+8 y=2(0)+8 y=0+8 y=8 !!! :D

- anonymous

Yes!! Now that's called finding the y-intercept. What would you do to find the x-intercept? How would you eliminate y in order to find x?

- MaeganR

whoa. whoa. whoa. hold up. let me think...

- MaeganR

you would plug in 0 for y?

- anonymous

WELL DONE! awesome job @MaeganR!

- anonymous

So what would you get for x?

- anonymous

when you plug in 0 into y?

- MaeganR

let me solve it..

- MaeganR

0=2x+8 is how you start right.?

- anonymous

Yes.

- MaeganR

-4=x !?!?!?!

- anonymous

Yes!!!Correct!!

- MaeganR

so it would be (-4,8) but how do you go up or down.?

- anonymous

so now what would the co-ordinates of the x-intercept be? Remember the coordinates take in the shape of this: (x-value, y-value)

- anonymous

Yes!

- MaeganR

wait. slope=2 2/1 up 2 over 1?

- anonymous

No!! Don't do that.

- anonymous

Forget the slope when sketching.

- MaeganR

but htats what my teacher says to do? ):

- anonymous

Haha, when you go up to senior years, all you do is put important features when sketching. The sketch doesn't need to be 00% perfect and to scale.

- anonymous

100%

- MaeganR

im in 7th grade advanced, so were taking a 9th grade class in 7th grade. legit, no joke

- MaeganR

oh. oh. oh. I get it.

- anonymous

Then if you're in 7th grade advanced, you should be smart as hell. Taking a 9th grade class when you're in 7th grade would require some form of intelligence and dexterity at mathematics. You should know allt his because this is 7th grade maths.

- MaeganR

so (-4,0) and (0,-8)!?!?!?!?!

- anonymous

Yes.

- anonymous

Now run run a line along the two points

- anonymous

You don't need to be precise in your placement of the coordinates.

- anonymous

but make sure the x and y intecept are on the x and y axis respectively.

- MaeganR

but were not leaning 7th grade stuff. we wont learn 8th grade stuff either. its like 7th grade=9th grade 8thgrade=10th grade 9th grade=11th grade 10th grade=12th grade 11th+12th grade=college for free in high school. basically im skipping grades. its so confusing.

- anonymous

Why are you skipping grades with this limited knowledge of maths? If you keep going at this rate, you're on the road to failure.

- anonymous

That's my 2 cents.

- MaeganR

yay. thank you so much. ive been so frustrated for a month because nobody would actually take the time to explain the whole thing to me in unbig scarey words. thank you so much. :)

- anonymous

No worries. I think keeping it simple and just using baby talk always makes more sense than sophisticated and complicated words.

- MaeganR

because i have to do this. theres no way out of the advanced program. once the school puts you in it without youre choice youre there, whether you fail or not.

- MaeganR

yeah. always^.

- MaeganR

im going to close the question now, but you can message me(:

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