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anonymous
 3 years ago
find the absolute minimum and absolute maximum for the given funtion f(x)=x2sinx between 0 and 2(pi)
anonymous
 3 years ago
find the absolute minimum and absolute maximum for the given funtion f(x)=x2sinx between 0 and 2(pi)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0PLS GIVE A SIMFILICATION TO SOLVE THE PROBLEM

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Use the derivative:\[f'(x)=12\cos x\]Solve the equation:\[f'(x)=0 \Leftrightarrow 12\cos x = 0 \Leftrightarrow \cos x = \frac{ 1 }{ 2 }\]There are two solutions in [0, 2pi]. These are the xvalues where f has a (local) extreme. You can calculate the extremes by substituting the solutions of f' in f. Also calculate f(0) and f(2pi) to get the extremes in the endpoints. If you have all the extremes, you can decide what the absolute maximum and minimum values are.
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