MaeganR
Point-Slope Form:
y+3=2(x+1)
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Butterfly16
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What do you need help with?
MaeganR
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ok. um. how do you solve and graph it? ill show you what ive already done.
MaeganR
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y+3=-2(x+1)
y+3=-2x+2
-3 -3
y=-2x...
Thats where im stuck.
MaeganR
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...
Butterfly16
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To find the points so you can graph it, just plug 0 in for x or y:
y+3=2(x+1)
0+3=2(x+1)
3=2x+1
2=2x
1=x
Here's a point: (1, 0)
y+3=2(x+1)
y+3=2(0+1)
y+3=2
y= -1
Heres another point: (0, -1)
You can plug any number in for x or y to find the a point. :o)
Butterfly16
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Also, is it 2(x+1) or -2(x+1)?
MaeganR
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y+3=-2(x+1)
Butterfly16
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Okay, then ignore that last comment lol.
y+3=-2(x+1)
0+3=-2x-2
3=-2x-2
5=-2x
-2.5=x
(-2.5, 0)
y+3=-2(0+1)
y+3=-2
y=-5
(0, -5)
MaeganR
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oh. |:
Butterfly16
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You can do this and find a few different points and then you can graph them. :o)
MaeganR
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ok
Butterfly16
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MaeganR
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can you help me with y+1=(x+5) also?
Azteck
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@MaeganR didn't word the question too well. She said "solve" as in put it in point intercept form: y=mx+b
MaeganR
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y+1=-3/5(x+5) oops.
Azteck
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MaeganR. Expand/Distribute the LHS (Left Hand Side)
MaeganR
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i should really write that down..