MaeganR
  • MaeganR
Point-Slope Form: y+3=2(x+1)
Linear Algebra
katieb
  • katieb
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anonymous
  • anonymous
What do you need help with?
MaeganR
  • MaeganR
ok. um. how do you solve and graph it? ill show you what ive already done.
MaeganR
  • MaeganR
y+3=-2(x+1) y+3=-2x+2 -3 -3 y=-2x... Thats where im stuck.

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MaeganR
  • MaeganR
...
anonymous
  • anonymous
To find the points so you can graph it, just plug 0 in for x or y: y+3=2(x+1) 0+3=2(x+1) 3=2x+1 2=2x 1=x Here's a point: (1, 0) y+3=2(x+1) y+3=2(0+1) y+3=2 y= -1 Heres another point: (0, -1) You can plug any number in for x or y to find the a point. :o)
anonymous
  • anonymous
Also, is it 2(x+1) or -2(x+1)?
MaeganR
  • MaeganR
y+3=-2(x+1)
anonymous
  • anonymous
Okay, then ignore that last comment lol. y+3=-2(x+1) 0+3=-2x-2 3=-2x-2 5=-2x -2.5=x (-2.5, 0) y+3=-2(0+1) y+3=-2 y=-5 (0, -5)
MaeganR
  • MaeganR
oh. |:
anonymous
  • anonymous
You can do this and find a few different points and then you can graph them. :o)
MaeganR
  • MaeganR
ok
anonymous
  • anonymous
1 Attachment
MaeganR
  • MaeganR
can you help me with y+1=(x+5) also?
anonymous
  • anonymous
@MaeganR didn't word the question too well. She said "solve" as in put it in point intercept form: y=mx+b
MaeganR
  • MaeganR
y+1=-3/5(x+5) oops.
anonymous
  • anonymous
MaeganR. Expand/Distribute the LHS (Left Hand Side)
MaeganR
  • MaeganR
i should really write that down..

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