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MaeganR

  • 2 years ago

Point-Slope Form: y+3=2(x+1)

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  1. Butterfly16
    • 2 years ago
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    What do you need help with?

  2. MaeganR
    • 2 years ago
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    ok. um. how do you solve and graph it? ill show you what ive already done.

  3. MaeganR
    • 2 years ago
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    y+3=-2(x+1) y+3=-2x+2 -3 -3 y=-2x... Thats where im stuck.

  4. MaeganR
    • 2 years ago
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    ...

  5. Butterfly16
    • 2 years ago
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    To find the points so you can graph it, just plug 0 in for x or y: y+3=2(x+1) 0+3=2(x+1) 3=2x+1 2=2x 1=x Here's a point: (1, 0) y+3=2(x+1) y+3=2(0+1) y+3=2 y= -1 Heres another point: (0, -1) You can plug any number in for x or y to find the a point. :o)

  6. Butterfly16
    • 2 years ago
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    Also, is it 2(x+1) or -2(x+1)?

  7. MaeganR
    • 2 years ago
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    y+3=-2(x+1)

  8. Butterfly16
    • 2 years ago
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    Okay, then ignore that last comment lol. y+3=-2(x+1) 0+3=-2x-2 3=-2x-2 5=-2x -2.5=x (-2.5, 0) y+3=-2(0+1) y+3=-2 y=-5 (0, -5)

  9. MaeganR
    • 2 years ago
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    oh. |:

  10. Butterfly16
    • 2 years ago
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    You can do this and find a few different points and then you can graph them. :o)

  11. MaeganR
    • 2 years ago
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    ok

  12. Butterfly16
    • 2 years ago
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  13. MaeganR
    • 2 years ago
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    can you help me with y+1=(x+5) also?

  14. Azteck
    • 2 years ago
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    @MaeganR didn't word the question too well. She said "solve" as in put it in point intercept form: y=mx+b

  15. MaeganR
    • 2 years ago
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    y+1=-3/5(x+5) oops.

  16. Azteck
    • 2 years ago
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    MaeganR. Expand/Distribute the LHS (Left Hand Side)

  17. MaeganR
    • 2 years ago
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    i should really write that down..

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