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applesjgtl
Group Title
A monkey uses a fishing pole to raise 750g of bananas up to his position 15m above the ground. If the monkey's power output was 330 W, how long did it take to reel in the bananas?
 one year ago
 one year ago
applesjgtl Group Title
A monkey uses a fishing pole to raise 750g of bananas up to his position 15m above the ground. If the monkey's power output was 330 W, how long did it take to reel in the bananas?
 one year ago
 one year ago

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Shane_B Group TitleBest ResponseYou've already chosen the best response.1
Let me restate that...calculate the PE :)
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
Oh, okay. \[PE=mg \Delta y\]?
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
Yes \[\Delta PE = mg\Delta h\]
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
Okay: \[(750g)(9.81m/s^2)(15m)=110,362.5J\]
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
Almost...your mass needs to be in kg. Anyway, you'll get 110.3625J
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
So the mass would be 7.5 kg?
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
No :) 750g = 0.75kg
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
Sorry, what is s?
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
\[Watts=\frac{Joules}{second}\]
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
and that would be equal to 330W
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
To be more clear:\[330W=\frac{330Joules}{second}\]
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
Hm. That can't be right, can it? Perhaps: \[330W=110.3625J/time (s)\]
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
That's not what I'm saying :) I just showed the conversion of 330W to Joules/second
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
Oh right, I guess I knew that.
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
So if you have 330J/s of power available and need to perform 110.3625J of work, how long would that take?
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
36419.63 seconds?
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
That seems really long.
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
Also seems wrong.
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
It is. So your intuition is correct...that's not the answer
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{110.3625J}{330J/s}=?\]
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
It will take about 1/3 of a second :)
 one year ago

applesjgtl Group TitleBest ResponseYou've already chosen the best response.0
I got .3344 seconds. Don't know how I got so confused the first time around. Thanks for your help, Shane!
 one year ago

Shane_B Group TitleBest ResponseYou've already chosen the best response.1
no problem. I get confused sometimes too...it's physics after all!
 one year ago
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