anonymous
  • anonymous
A monkey uses a fishing pole to raise 750g of bananas up to his position 15m above the ground. If the monkey's power output was 330 W, how long did it take to reel in the bananas?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
W=f*d?
Shane_B
  • Shane_B
Let me restate that...calculate the PE :)
anonymous
  • anonymous
Oh, okay. \[PE=mg \Delta y\]?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Shane_B
  • Shane_B
Yes \[\Delta PE = mg\Delta h\]
anonymous
  • anonymous
Okay: \[(750g)(9.81m/s^2)(15m)=110,362.5J\]
Shane_B
  • Shane_B
Almost...your mass needs to be in kg. Anyway, you'll get 110.3625J
anonymous
  • anonymous
So the mass would be 7.5 kg?
Shane_B
  • Shane_B
No :) 750g = 0.75kg
anonymous
  • anonymous
Sorry, what is s?
Shane_B
  • Shane_B
seconds
Shane_B
  • Shane_B
\[Watts=\frac{Joules}{second}\]
anonymous
  • anonymous
and that would be equal to 330W
Shane_B
  • Shane_B
To be more clear:\[330W=\frac{330Joules}{second}\]
anonymous
  • anonymous
Hm. That can't be right, can it? Perhaps: \[330W=110.3625J/time (s)\]
Shane_B
  • Shane_B
That's not what I'm saying :) I just showed the conversion of 330W to Joules/second
anonymous
  • anonymous
Oh right, I guess I knew that.
Shane_B
  • Shane_B
So if you have 330J/s of power available and need to perform 110.3625J of work, how long would that take?
anonymous
  • anonymous
36419.63 seconds?
anonymous
  • anonymous
That seems really long.
anonymous
  • anonymous
Also seems wrong.
Shane_B
  • Shane_B
It is. So your intuition is correct...that's not the answer
Shane_B
  • Shane_B
\[\frac{110.3625J}{330J/s}=?\]
Shane_B
  • Shane_B
It will take about 1/3 of a second :)
anonymous
  • anonymous
I got .3344 seconds. Don't know how I got so confused the first time around. Thanks for your help, Shane!
Shane_B
  • Shane_B
no problem. I get confused sometimes too...it's physics after all!

Looking for something else?

Not the answer you are looking for? Search for more explanations.