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 2 years ago
please helppppp! I'm horrible at math :/
In the below system, solve for y in the first equation.
x + 3y = 6
2x – y = 10
one thirdx + 2
negative one thirdx + 6
–x + 2
negative one thirdx + 2
 2 years ago
please helppppp! I'm horrible at math :/ In the below system, solve for y in the first equation. x + 3y = 6 2x – y = 10 one thirdx + 2 negative one thirdx + 6 –x + 2 negative one thirdx + 2

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magenxoxo
 2 years ago
Best ResponseYou've already chosen the best response.0oh! i missed a few steps...or did something wrong i guess. thank you <3

magenxoxo
 2 years ago
Best ResponseYou've already chosen the best response.0Use the substitution method to solve the following system of equations. 4x – y = 3 7x – 9y = –2 (1, 1) (6, –3) (6, 1) (1, –3)

CalebBeavers
 2 years ago
Best ResponseYou've already chosen the best response.1(1,1) is right for that one
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