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magenxoxo
Group Title
please helppppp! I'm horrible at math :/
In the below system, solve for y in the first equation.
x + 3y = 6
2x – y = 10
one thirdx + 2
negative one thirdx + 6
–x + 2
negative one thirdx + 2
 one year ago
 one year ago
magenxoxo Group Title
please helppppp! I'm horrible at math :/ In the below system, solve for y in the first equation. x + 3y = 6 2x – y = 10 one thirdx + 2 negative one thirdx + 6 –x + 2 negative one thirdx + 2
 one year ago
 one year ago

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itsladyrw Group TitleBest ResponseYou've already chosen the best response.0
y = 1/3x + 2 ?
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.0
looks right to me!
 one year ago

itsladyrw Group TitleBest ResponseYou've already chosen the best response.0
Is your last choice.
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.0
oh! i missed a few steps...or did something wrong i guess. thank you <3
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.0
Use the substitution method to solve the following system of equations. 4x – y = 3 7x – 9y = –2 (1, 1) (6, –3) (6, 1) (1, –3)
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.0
would it be (1,1)?
 one year ago

CalebBeavers Group TitleBest ResponseYou've already chosen the best response.1
(1,1) is right for that one
 one year ago
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