A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
https://dl.dropbox.com/u/63664351/Physics/Electromagnetic%20Induction.PNG
https://dl.dropbox.com/u/63664351/Physics/Electromagnetic%20Induction%20Answers.PNG
anonymous
 3 years ago
https://dl.dropbox.com/u/63664351/Physics/Electromagnetic%20Induction.PNG https://dl.dropbox.com/u/63664351/Physics/Electromagnetic%20Induction%20Answers.PNG

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this one kinda trips you up at first glance. ok here's the thing since the mag field is uniform, as you pull the loop, the flux doesn't change. no flux change = no e.m.f = no work done to pull the loop. Therefore, the answer is E.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait hang on. If there is no flux change then the Work is constant right? Then the answer is A?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm very sorry. I was in a hurry and I read the question wrong. Neglect my previous reply. Here's the right analysis: Ok first of all, if there is no change in flux, it like having no magnetic field at all. You see my point? suppose you're pulling the ring through air without any mag field at all. But you are increasing it's velocity i.e. you are accelerating it. Since this is a graph of W versus v, let's see what the slope gives us, okay? \[\large \begin{align}\mathrm{d}W&=m \frac{\mathrm{d} v}{\mathrm{d} t}\times\mathrm{d} s\\ \frac{\mathrm{d}W}{\mathrm{d} v}&=m\frac{\mathrm{d} s}{\mathrm{d} t}\\ &=m\mathrm{d} v=\text{change in momentum.} \end{align}\] Now, m is constant. what is dv? dv is a very very small part of the velocity axis. You get it by cutting the velocity axis into an infinite number of infinitesimally small equal pieces. So that's a constant too. Therefore, the slope of this graph is constant. The only graph that shows this behavior is B.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The point you have to note here is that you don't have to do any work against the mag field.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hang on a sec. when the loop partially out of the magnetic field, the loop experienced change in magnetic flux linkage, right? Work done need to be done to oppose that change.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but i thought the magnetic field extended on all sides indefinitely...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.