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dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 5} 1/(1+5)^4\]

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1It would be infinity

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Do you know L'Hopital's rule

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0nope. is it the only way?

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0the answer is infinity. just have no clue how to work it out.

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Ok what you can do is:

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1wait i just noticed

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1u mean it's x5 in the denominator right? otherwise it wouldn't be infinity

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 5} \frac{x}{(x5)^4}\]\[=\lim_{x \rightarrow 5} \frac{x}{(x5)^4}\]\[=\lim_{x \rightarrow 5} \frac{x}{(x5)^2(x5)^2}\]\[=\lim_{x \rightarrow 5} \frac{x}{(x5)(x5)(x5)(x5)}\]\[=\lim_{x \rightarrow 5} \frac{x/x}{(x/x5/x)(x/x5/x)(x/x5/x)(x/x5/x)}\]\[=\lim_{x \rightarrow 5} \frac{1}{(15/x)(15/x)(15/x)(15)}\]

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1oops the last factor should also be (15/x)

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0awesome, thanks for your effort! just wondering line 6. why are you diving everything by x?

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1I hope you see that the bottom factors are (11) when substituting x=5, so you get like "1/0" > infinity

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1hm it's true that was a useless step

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1I was thinking that it was going to x>infinity at first, but i realized it was x>5 after lol

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0ahhh, yes. i see that. thank you. is that a legal move though? because you are changing the function?

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0for example, (x5) doesn't equal (15/x)

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0sorry, i guess it is. just would have never thought of that!

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Nope :) If you divide the top and bottom by x, it is perfectly valid (it's like you are dividing by "1") Example: \[\frac{2}{3} = \frac{\frac{2}{x}}{\frac{3}{x}}=\frac{2}{x}*\frac{x}{3}=\frac{2}{3}\]

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1I divided the numerator by x as well: I did x/x = 1 in the numerator, and divided the whole denominator by x

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1if you divide the numerator, you MUST also divide the denominator!

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0awesome, this is just amazing. never would have figured out this.

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1you will learn a neat theorem called "L'hopital's rule" later which will make the computation even easier :)

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0k. thanks for your time. im now 'a fan' haha.

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Hehe awesome ;) Good luck with everything
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