Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
brinethery
Group Title
A neutron star has a constant density of 6 * 10^27 kg/m^3 and a mass five times that of our Sun. Compare its rotational inertia with that of the Earth (assume constant density). In both cases, the rotation axis is an axis through the center of the sphere.
 one year ago
 one year ago
brinethery Group Title
A neutron star has a constant density of 6 * 10^27 kg/m^3 and a mass five times that of our Sun. Compare its rotational inertia with that of the Earth (assume constant density). In both cases, the rotation axis is an axis through the center of the sphere.
 one year ago
 one year ago

This Question is Closed

Mashy Group TitleBest ResponseYou've already chosen the best response.0
what about the radius ?!
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.0
@Mashy you know the density and the mass of the star. you can find the radius.
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
the ratio of the rotational inertia or the moment of inertia of star to the earth would be m1*(R1)^2/ m2*(R2)^2 m1 is five times the solar mass m2,R2 are the mass and radius of the earth R1 can be calcualted as follows 4/3pi(R1)^3 * d = m1 where d is the density
 one year ago

brinethery Group TitleBest ResponseYou've already chosen the best response.0
Thank you very much Diwakar. Yeah, I can see where you're going with that last calculation... just multiply volume of the sphere times the density, and volume cancels out, and the only variable left to solve for is r. Thanks so much!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.