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## anonymous 3 years ago How would you solve the following limit: limit (x -> 0+) (x-11)/sin(x)

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1. anonymous

you can do it manually, and figure out its negative infinity. but is there any algebraic way.

2. anonymous

$\lim_{x \rightarrow 0+} (x-11)/\sin(x)$

3. anonymous

$\lim_{x \rightarrow 0}(sinx/x)=1$

4. kirbykirby

$You know \lim_{x \rightarrow 0+} \frac{\sin x}{x}=1$

5. kirbykirby

so: do the same trick I told you before: Divide the top and bottom by x

6. anonymous

and $\lim_{x \rightarrow 0}(11/sinx)\rightarrow \infty$

7. kirbykirby

$\lim_{x \rightarrow 0+} \frac{\frac{11-x}{x}}{\frac{\sin x}{x}} = \lim_{x \rightarrow 0+} \frac{11/x-1}{\frac{\sin x}{x}}=$$\frac{\infty-1}{1}=\infty$

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