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How would you solve the following limit:
limit (x > 0+) (x11)/sin(x)
 one year ago
 one year ago
How would you solve the following limit: limit (x > 0+) (x11)/sin(x)
 one year ago
 one year ago

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dgamma3Best ResponseYou've already chosen the best response.0
you can do it manually, and figure out its negative infinity. but is there any algebraic way.
 one year ago

dgamma3Best ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 0+} (x11)/\sin(x)\]
 one year ago

nitzBest ResponseYou've already chosen the best response.1
\[\lim_{x \rightarrow 0}(sinx/x)=1\]
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
\[You know \lim_{x \rightarrow 0+} \frac{\sin x}{x}=1 \]
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
so: do the same trick I told you before: Divide the top and bottom by x
 one year ago

nitzBest ResponseYou've already chosen the best response.1
and \[\lim_{x \rightarrow 0}(11/sinx)\rightarrow \infty \]
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
\[\lim_{x \rightarrow 0+} \frac{\frac{11x}{x}}{\frac{\sin x}{x}} = \lim_{x \rightarrow 0+} \frac{11/x1}{\frac{\sin x}{x}}=\]\[\frac{\infty1}{1}=\infty\]
 one year ago
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