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dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0you can do it manually, and figure out its negative infinity. but is there any algebraic way.

dgamma3
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0+} (x11)/\sin(x)\]

nitz
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}(sinx/x)=1\]

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1\[You know \lim_{x \rightarrow 0+} \frac{\sin x}{x}=1 \]

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1so: do the same trick I told you before: Divide the top and bottom by x

nitz
 one year ago
Best ResponseYou've already chosen the best response.1and \[\lim_{x \rightarrow 0}(11/sinx)\rightarrow \infty \]

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0+} \frac{\frac{11x}{x}}{\frac{\sin x}{x}} = \lim_{x \rightarrow 0+} \frac{11/x1}{\frac{\sin x}{x}}=\]\[\frac{\infty1}{1}=\infty\]
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