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dgamma3
 2 years ago
Best ResponseYou've already chosen the best response.0you can do it manually, and figure out its negative infinity. but is there any algebraic way.

dgamma3
 2 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0+} (x11)/\sin(x)\]

nitz
 2 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}(sinx/x)=1\]

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1\[You know \lim_{x \rightarrow 0+} \frac{\sin x}{x}=1 \]

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1so: do the same trick I told you before: Divide the top and bottom by x

nitz
 2 years ago
Best ResponseYou've already chosen the best response.1and \[\lim_{x \rightarrow 0}(11/sinx)\rightarrow \infty \]

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0+} \frac{\frac{11x}{x}}{\frac{\sin x}{x}} = \lim_{x \rightarrow 0+} \frac{11/x1}{\frac{\sin x}{x}}=\]\[\frac{\infty1}{1}=\infty\]
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