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emilyoo Group TitleBest ResponseYou've already chosen the best response.0
dw:1358068473382:dw
 one year ago

emilyoo Group TitleBest ResponseYou've already chosen the best response.0
this is how far i got
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
t=sin x would do it
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
because derivative of sinx (ie cos x ) is readily available!
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.4
you don't even need to use that trig identity by the way.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.4
just let \(u=2x\) in the original integral, it'd work fine.
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.1
\(\int (65\cdot2\sin x \cos x)dx=\int6dx10\int\sin x \cos xdx\). Try to make a substitution \(t=\sin x,\quad dt=\cos x\). Good luck.
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
@wio'smethod is the simplest :)
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.4
\[ \int \sin(2x)dx = \int \sin(u)\frac{ du}{2} \]
 one year ago
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