emilyoo
simple integration by substitution:
65sin(2x)



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emilyoo
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dw:1358068473382:dw

emilyoo
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this is how far i got

AravindG
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t=sin x would do it

AravindG
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because derivative of sinx (ie cos x ) is readily available!

wio
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you don't even need to use that trig identity by the way.

wio
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just let \(u=2x\) in the original integral, it'd work fine.

klimenkov
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\(\int (65\cdot2\sin x \cos x)dx=\int6dx10\int\sin x \cos xdx\). Try to make a substitution \(t=\sin x,\quad dt=\cos x\). Good luck.

AravindG
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@wio'smethod is the simplest :)

wio
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\[
\int \sin(2x)dx = \int \sin(u)\frac{ du}{2}
\]