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sauravshakya

  • 3 years ago

Is there any formula for this?

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  1. sauravshakya
    • 3 years ago
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    |dw:1358085079043:dw|

  2. skullpatrol
    • 3 years ago
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    Looks like a factorial.

  3. mathmate
    • 3 years ago
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    The following should work: \( \huge g(n)=\frac{(2n)!}{(2^n n!)^2} \)

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