## josh96b 2 years ago limx->0 ((a^2x)-1)/((a^x)-1) the answer is 2, but i have no idea how or why

1. Saikam

$a ^{2x} - 1 = (a ^{x} - 1) * (a ^{x}+1)$

2. Saikam

the expression reduces to : $a ^{x} +1 = 1 +1 = 2 as x tends \to 0$

3. josh96b

thank you so much!