- Faman39

Please help! I dont understand anything in this one

- schrodinger

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- Faman39

##### 1 Attachment

- anonymous

like terms are the positive terms , first collect them

- Faman39

I dont get the whole process way they showed

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## More answers

- Faman39

i m confuse from step 3

- anonymous

solve like this (2x/5 +x/5) +4/5-1
=3x/5+4/5-1
=(3x+4)/5-1
=(3x+4-5)/5

- JA1

i was gonna answer but it seems singhmmm has this under control

- anonymous

then u will get
(3x-1)/5

- Faman39

Thank you so much guys coming for help and thanks alot @singhmmm :)

- anonymous

ur welcum

- Faman39

what abt 4/5?

- Faman39

I need better explanation, how do we come up there, i tried to understand, it seems still blurry to me

- JA1

what do you need?

- anonymous

solve like this (2x/5 +x/5) +4/5-1
=3x/5+4/5-1
here we will take the LCM of 3x/5+4/5
=(3x+4)/5-1
=(3x+4-5)/5
=(3x-1)/5

- JA1

O_O um ok just a sec

- Faman39

but it showed 3/5 x - 1/5

- Faman39

@Chlorophyll i m kinda confused with this

- anonymous

Rearrange to combine x terms together ( commutative )
2x/ 5 + x/5 = 3x/ 5
then, the rest is constant:
-1 + 4/5 = -5/5 + 4/5

- anonymous

@Faman39 Pretend x terms are candies, constant numbers are cookies
you want to sort them out, so it'll be easier to combine together!

- Faman39

3x/5 i understand this but last one, it is still making me confuse

- Faman39

i meant last part - 1/5

- anonymous

Do you know that in order to combine -1 + 4/5, you need to convert into same denominator?

- Faman39

i thought -1 +4/5 would be like that 3/5

- anonymous

No, -1 = - 5/5

- Faman39

oh ok, thank you so so much for helping @Chlorophyll, i been so confused with this little thing, thank you so much

- anonymous

Because: 1 = 5/5 --> -1 = -5/5

- Faman39

ok, it was kinda tricky, i m pretty clear now with your help, thank you! :)

- anonymous

As long as the numerator is the same as denom. , the result is 1

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