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like terms are the positive terms , first collect them
I dont get the whole process way they showed
i m confuse from step 3
solve like this (2x/5 +x/5) +4/5-1 =3x/5+4/5-1 =(3x+4)/5-1 =(3x+4-5)/5
i was gonna answer but it seems singhmmm has this under control
then u will get (3x-1)/5
Thank you so much guys coming for help and thanks alot @singhmmm :)
what abt 4/5?
I need better explanation, how do we come up there, i tried to understand, it seems still blurry to me
what do you need?
solve like this (2x/5 +x/5) +4/5-1 =3x/5+4/5-1 here we will take the LCM of 3x/5+4/5 =(3x+4)/5-1 =(3x+4-5)/5 =(3x-1)/5
O_O um ok just a sec
but it showed 3/5 x - 1/5
@Chlorophyll i m kinda confused with this
Rearrange to combine x terms together ( commutative ) 2x/ 5 + x/5 = 3x/ 5 then, the rest is constant: -1 + 4/5 = -5/5 + 4/5
@Faman39 Pretend x terms are candies, constant numbers are cookies you want to sort them out, so it'll be easier to combine together!
3x/5 i understand this but last one, it is still making me confuse
i meant last part - 1/5
Do you know that in order to combine -1 + 4/5, you need to convert into same denominator?
i thought -1 +4/5 would be like that 3/5
No, -1 = - 5/5
oh ok, thank you so so much for helping @Chlorophyll, i been so confused with this little thing, thank you so much
Because: 1 = 5/5 --> -1 = -5/5
ok, it was kinda tricky, i m pretty clear now with your help, thank you! :)
As long as the numerator is the same as denom. , the result is 1