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I got the number 0.583

the correct answer is 1.79.
I'm not sure where i went wrong

how did you get 0.583 ? mind showing your work/steps ?

is it \( \large \frac{(1+7/x)^x}{12}\) or \( \large (1+7/x)^{x/12} \)

y=lim (1+7/x)^x/12
ln(y)=lim x/12 ln(1+7/x)
\[\frac{ \ln(1+\frac{ 7 }{x} }{\frac{12 }x }\]

mathmate it's the second

\[\lim_{x \rightarrow ∞} \frac{ (1+7)^x }{ 12 }\]

then i took d/dx to both the numerator and the denominator

the problem is
\[\lim_{x \rightarrow \infty} (1+\frac{ 7 }{ 12})^\frac{ x }{12 }\]

do you know a general formula
\[\lim_{y \rightarrow 0} (1+y)^{\frac{ 1}{y}}=...?\]

if you know ^ that, then you can put 7/x = y
in your limit question first, to bring in that form.

im trying that right now

okay :) take your time...

thanks i got the right answer

good! you're welcome ^_^