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grobles27

  • one year ago

The position function for an object is given by s(t)=6t^2+240t, where s is measured in feet and t is measured in seconds. Find the velocity of the object when t=2 seconds.

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  1. wio
    • one year ago
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    Velocity is the derivative of the position with respect to time. Are you given the position with respect to time. All you have to do is differentiate.

  2. grobles27
    • one year ago
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    Do I have to plug in the 2?

  3. ASAAD123
    • one year ago
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    v(t)=ds/dt v(t)=12t+240 v(2)=12*2+240=264 feet/second

  4. wio
    • one year ago
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    You plug the 2 into the derivative.

  5. wio
    • one year ago
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    You mean you have to use: \[ \sin(x/2) = \pm\sqrt{\frac{1-\cos(x)}{2}} \]?

  6. wio
    • one year ago
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    In that case split it into: 1 + 12

  7. wio
    • one year ago
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    you're going to have to split it regardless.

  8. vaibhav_s
    • one year ago
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    just differentiate the given function with respect to 't' It will give you velocity as a function of 't'. just plug in the required value i.e '2' to obtain velocity at time 2 seconds...

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