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 one year ago
The position function for an object is given by s(t)=6t^2+240t, where s is measured in feet and t is measured in seconds. Find the velocity of the object when t=2 seconds.
 one year ago
The position function for an object is given by s(t)=6t^2+240t, where s is measured in feet and t is measured in seconds. Find the velocity of the object when t=2 seconds.

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wio
 one year ago
Best ResponseYou've already chosen the best response.1Velocity is the derivative of the position with respect to time. Are you given the position with respect to time. All you have to do is differentiate.

grobles27
 one year ago
Best ResponseYou've already chosen the best response.0Do I have to plug in the 2?

ASAAD123
 one year ago
Best ResponseYou've already chosen the best response.2v(t)=ds/dt v(t)=12t+240 v(2)=12*2+240=264 feet/second

wio
 one year ago
Best ResponseYou've already chosen the best response.1You plug the 2 into the derivative.

wio
 one year ago
Best ResponseYou've already chosen the best response.1You mean you have to use: \[ \sin(x/2) = \pm\sqrt{\frac{1\cos(x)}{2}} \]?

wio
 one year ago
Best ResponseYou've already chosen the best response.1In that case split it into: 1 + 12

wio
 one year ago
Best ResponseYou've already chosen the best response.1you're going to have to split it regardless.

vaibhav_s
 one year ago
Best ResponseYou've already chosen the best response.0just differentiate the given function with respect to 't' It will give you velocity as a function of 't'. just plug in the required value i.e '2' to obtain velocity at time 2 seconds...
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