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The position function for an object is given by s(t)=6t^2+240t, where s is measured in feet and t is measured in seconds. Find the velocity of the object when t=2 seconds.
 one year ago
 one year ago
The position function for an object is given by s(t)=6t^2+240t, where s is measured in feet and t is measured in seconds. Find the velocity of the object when t=2 seconds.
 one year ago
 one year ago

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wioBest ResponseYou've already chosen the best response.1
Velocity is the derivative of the position with respect to time. Are you given the position with respect to time. All you have to do is differentiate.
 one year ago

grobles27Best ResponseYou've already chosen the best response.0
Do I have to plug in the 2?
 one year ago

ASAAD123Best ResponseYou've already chosen the best response.2
v(t)=ds/dt v(t)=12t+240 v(2)=12*2+240=264 feet/second
 one year ago

wioBest ResponseYou've already chosen the best response.1
You plug the 2 into the derivative.
 one year ago

wioBest ResponseYou've already chosen the best response.1
You mean you have to use: \[ \sin(x/2) = \pm\sqrt{\frac{1\cos(x)}{2}} \]?
 one year ago

wioBest ResponseYou've already chosen the best response.1
In that case split it into: 1 + 12
 one year ago

wioBest ResponseYou've already chosen the best response.1
you're going to have to split it regardless.
 one year ago

vaibhav_sBest ResponseYou've already chosen the best response.0
just differentiate the given function with respect to 't' It will give you velocity as a function of 't'. just plug in the required value i.e '2' to obtain velocity at time 2 seconds...
 one year ago
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