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anonymous
 4 years ago
The position function for an object is given by s(t)=6t^2+240t, where s is measured in feet and t is measured in seconds. Find the velocity of the object when t=2 seconds.
anonymous
 4 years ago
The position function for an object is given by s(t)=6t^2+240t, where s is measured in feet and t is measured in seconds. Find the velocity of the object when t=2 seconds.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Velocity is the derivative of the position with respect to time. Are you given the position with respect to time. All you have to do is differentiate.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do I have to plug in the 2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0v(t)=ds/dt v(t)=12t+240 v(2)=12*2+240=264 feet/second

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You plug the 2 into the derivative.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You mean you have to use: \[ \sin(x/2) = \pm\sqrt{\frac{1\cos(x)}{2}} \]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In that case split it into: 1 + 12

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you're going to have to split it regardless.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just differentiate the given function with respect to 't' It will give you velocity as a function of 't'. just plug in the required value i.e '2' to obtain velocity at time 2 seconds...
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