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Find all solutions in the interval [0, 2π). cos2x + 2 cos x + 1 = 0

Mathematics
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cos^2 x+ 2 cos x +1=0
this is a quadratic equation which will factorise
\[\cos²(x) + 2\cos(x) + 1 = (\cos(x) + 1)²\] Hence the roots are all x out of [0,2pi) for which cos(x) = -1. -pi and pi

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Other answers:

Sorry, of course it's just + pi as there are no negative numbers in this interval
what about 0 as a solution?
no sorry - its -1
cos 0 = 1 of course
the answer choices are a) x=2pi B)x=pi c) x=pi/4, 7pi/4
are you sure you have the correct question is it cos 2x or cos^2 x ?
it is cos^2 x
It's B) x = pi as in my answer.
in that case the answer is as Stiwam said
thankyou!
yw

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