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Would someone please help me see how to work out the problem f/g, when f(x) = square root of 3-x, and g(x) = square root of x^2-1 please? and I need to figure out the domain. Thank you

Calculus1
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Well, from where to where do this mappings go? Are they supposed to map from the real numbers into the real numbers?
In addition, I suppose by square root you only mean the positive root? Else those aren't functions
domain is R-{-1,1},i.e all real numbers except {-1,1}

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Other answers:

brackets must be ( ),,sorry
first of all g(x) must be not equal to zero,and sqrt must not be negative value as then sqrt will be undefined..therefore work out the the in equality x^2-1>0 whis is modified as (x-1)(x+1)>0.
that's not true. what if x > 3? Then we have a square root of a negative number.
sorry i forgot to take the upper one into consideration ,the answer will be (-inf,-1)U(1,3]

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