Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

turbomatt75

  • 3 years ago

Would someone please help me see how to work out the problem f/g, when f(x) = square root of 3-x, and g(x) = square root of x^2-1 please? and I need to figure out the domain. Thank you

  • This Question is Closed
  1. Stiwan
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well, from where to where do this mappings go? Are they supposed to map from the real numbers into the real numbers?

  2. Stiwan
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    In addition, I suppose by square root you only mean the positive root? Else those aren't functions

  3. vaibhav_s
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    domain is R-{-1,1},i.e all real numbers except {-1,1}

  4. vaibhav_s
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    brackets must be ( ),,sorry

  5. vaibhav_s
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    first of all g(x) must be not equal to zero,and sqrt must not be negative value as then sqrt will be undefined..therefore work out the the in equality x^2-1>0 whis is modified as (x-1)(x+1)>0.

  6. Stiwan
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that's not true. what if x > 3? Then we have a square root of a negative number.

  7. vaibhav_s
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry i forgot to take the upper one into consideration ,the answer will be (-inf,-1)U(1,3]

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy