anonymous
  • anonymous
You live near a bridge that goes over a river. The underside of the bridge is an arch that can be modeled with the function y = –0.000471x² + .837x where x and y are measured in feet. How high above the river is the bridge (the top of the arch)? How long is the section of bridge above the arch? The bridge is about 1,777.07 ft. above the river, and the length of the bridge above the arch is about 888.54 ft. The bridge is about 371.85 ft. above the river, and the length of the bridge above the arch is about 1,777.07 ft. The bridge is about 371.85 ft. above the river, and the length of the bri
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
The bridge is about 1,777.07 ft. above the river, and the length of the bridge above the arch is about 888.54 ft. The bridge is about 371.85 ft. above the river, and the length of the bridge above the arch is about 1,777.07 ft. The bridge is about 371.85 ft. above the river, and the length of the bridge above the arch is about 888.54 ft. The bridge is about 1,777.07 ft. above the river, and the length of the bridge above the arch is about 371.85 ft.
anonymous
  • anonymous
plss help???
campbell_st
  • campbell_st
ok... to find the distance spanned by the arch you need to solve it so \[-0.00047x^2 + 0.837x = 0... or... -x(0.00047x - 0.837)\] so x = 0 or 0.837/0.00047 the distance between the points will be the distance spanned. |dw:1358113884987:dw|

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More answers

campbell_st
  • campbell_st
ok... do you know to differentiate..?
anonymous
  • anonymous
no lol what is that?
campbell_st
  • campbell_st
ok... do you know how to find the line of symmetry of the curve...?
anonymous
  • anonymous
no
campbell_st
  • campbell_st
what answer did you get got the distance spanned by the bridge..?
anonymous
  • anonymous
1,780.851
anonymous
  • anonymous
@campbell_st
campbell_st
  • campbell_st
oops missed a digit it should be 0.837/0.000471 and you should get 1777.07
campbell_st
  • campbell_st
ok so the parabola is symmetric and the highest point of the arch is on the line of symmetry... do you know how to find the line of symmetry..?
anonymous
  • anonymous
is it the line that goes down the middle?
campbell_st
  • campbell_st
thats it...
anonymous
  • anonymous
so how do i figure it out?
campbell_st
  • campbell_st
ok... so find half the distance spanned by the arch... then substitute that value into the equation for the bridge... that will give the height does that make sense..
anonymous
  • anonymous
soooo divide 1777.07 by 2?
campbell_st
  • campbell_st
yep... then substitute it... the highest point is at the centre of the acrch
anonymous
  • anonymous
which equation?
campbell_st
  • campbell_st
the original equation 0.000471x^2 + 0.837x
anonymous
  • anonymous
okay so when i divided it by 2 i got 888.535..... which number do i sub that for in the equation?
campbell_st
  • campbell_st
thats correct...
anonymous
  • anonymous
so do i sub that in for x?
campbell_st
  • campbell_st
yes so its \[-0.000471\times(888.535)^2 + 0.837\times888.535\]
anonymous
  • anonymous
so it's D
campbell_st
  • campbell_st
what did you get for the height..? the length is 1777.07
anonymous
  • anonymous
371.85
campbell_st
  • campbell_st
ok... which answer has height 371.85 and length 1777.07
anonymous
  • anonymous
B
campbell_st
  • campbell_st
thats it.. well done
anonymous
  • anonymous
did we answer the last part of the question? How high above the river is the bridge (the top of the arch)? How long is the section of bridge above the arch?
campbell_st
  • campbell_st
yes... you have all the answers you need height = 371.85 and length 1777.07

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