At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
first.., find the slope using the third formula that you write.., then use point-slope formula to find the equation..
m=y2-y1/x2-x1 (4, 0) (-2, 1) m=1-0/-2-4 m=1/-6 m=y2-y1/x2-x1 (-3, -2), (5, 3) m=3-(-2)/5-(-3) m=5/8 m=y2-y1/x2-x1 (-5, 1) (3, 4) m=4-1/3-(-5) m=3/8
@Butterfly16 Thats what I've done before, but then people come along, and tell me I'm wrong! ):
And why are you finding the slope 3 times?
because you have three questions and each question have equation... :)
oh, well I'm on #11.
y-y1=m(x-x1) (4,0), (-2,1) y-0=(1/-6)(x-4) y-0= -0.16x+0.7 y=-0.16x+0.7 Yeah, I just finding the slope for all of them. :o)
Im so freaking confused.
now.., using the similar way.., you can solve questions #12 and #13 can you? :)
y1 and x1 just stand for the points. So (4, 0) is the point, so y1 is 0 and x1 is 4. That would the equation for the point-slope form for that set of points.
but you have to write it in point-slope form?!
Then, I guess you can just plug in the numbers into the point-slope form so it'd just be: y-0=(1/-6)(x-4)
but don't you have to do 2 equations because of (4,0) and (-2,1)
@Butterfly16 has write it in slope-intercept form slope-intercept form is y = mx+ c , No.., points (4,0) and (-2,1) are on the same line.., so just choose one of them..
because like that?
Yip, the line would look like that. :o)
yup.., it's for the second line... :)
Awesome job! :o)
y-y1=m(x-x1) y--2=1/2(x--3) help
The points for number 12?
#12. i got that far but I'm stuck now.
y-y1=m(x-x1) (-3, -2) (5, 3) y-(-2)=(5/8)(x-(-3)) y+2=0.625x-1.875 y=0.625x-3.875
Yup, so for #12 it'd be y=0.625x-3.875
but thats y=mx-b it should be y=mx+b though right?
why are you guys using decimals? fractions are easier
no, it depends, if you are adding a negative, its the same as subtracting, and its okay @MaeganR
Can someone show mw how you get #13 now?
4-1/ 3--5 (or 3+5) so what is that?
And @erdog82 what are you doing?
how do you get from y-1= 3/8 x--5 to y=mx +b form?
its as simple as adding 1 number
idk. I was trying to do it like @Butterfly16 was doing it.
oh and its y-1=3/8 x+5
so you add 1 to 5 and you get..
so its y=3/8 x +6
wasn't that easier than you thought?
A lil bit
Well, it seemed like the other people were kinda confusing..
just a little
well.. your done!