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anonymous
 3 years ago
I'm trying to solve this using the elimination process:
3x+(5/2)y=21
x+2y=14
have i done it right so far? I'm new to the elimination process..
3x+(5/2)y=21
(x+2y=14)
2x + 1/2y = 7
anonymous
 3 years ago
I'm trying to solve this using the elimination process: 3x+(5/2)y=21 x+2y=14 have i done it right so far? I'm new to the elimination process.. 3x+(5/2)y=21 (x+2y=14) 2x + 1/2y = 7

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no... lets get rid of the fraction in the first equation by multiplying it by 2.. (2)3x + (2)5/2y = (2)21 6x + 5y = 42(thats better) Now the problem reads.... 6x + 5y = 42 x + 2y = 14 >(6)x + 2y = 14  6x + 5y = 42 6x  12y =  84 (result of multiplying by 6) add 0  7y =  42 7y =  42 (divide by 7 to get y by itself) 7y/7 = 42/7 y = 6 now sub 6 in for y in either of the original equations... x + 2y = 14 x + 2(6) = 14 x + 12 = 14 (subtract 12 from both sides to get x by itself) x + 12  12 = 14  12 x = 2 now check by subbing in your known variables... x + 2y = 14 2 + 2(6) = 14 2 + 12 = 14 14 = 14 (correct) What you have to try to do in elimination is eliminate " get rid of " one of the variables, so you can find the other variable. Sometimes you have to do this by multiplying the equation by a number so that the variables will cancel each other out. That is why I multiplied the second equation by a 6. And as you can see, it made the x's cancel out and I was able to solve for y. Once finding y, I then substituted what I got for y into the second equation and found x. You can substitute into either one of the equations and you will get the answer. Then I checked my answer by subbing in the known variables and if they equal, which they did, then the problem is correct.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your quite welcome....thats what I am here for
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