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I'm trying to solve this using the elimination process:
3x+(5/2)y=21
x+2y=14
have i done it right so far? I'm new to the elimination process..
3x+(5/2)y=21
(x+2y=14)
2x + 1/2y = 7
 one year ago
 one year ago
I'm trying to solve this using the elimination process: 3x+(5/2)y=21 x+2y=14 have i done it right so far? I'm new to the elimination process.. 3x+(5/2)y=21 (x+2y=14) 2x + 1/2y = 7
 one year ago
 one year ago

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texaschic101Best ResponseYou've already chosen the best response.1
no... lets get rid of the fraction in the first equation by multiplying it by 2.. (2)3x + (2)5/2y = (2)21 6x + 5y = 42(thats better) Now the problem reads.... 6x + 5y = 42 x + 2y = 14 >(6)x + 2y = 14  6x + 5y = 42 6x  12y =  84 (result of multiplying by 6) add 0  7y =  42 7y =  42 (divide by 7 to get y by itself) 7y/7 = 42/7 y = 6 now sub 6 in for y in either of the original equations... x + 2y = 14 x + 2(6) = 14 x + 12 = 14 (subtract 12 from both sides to get x by itself) x + 12  12 = 14  12 x = 2 now check by subbing in your known variables... x + 2y = 14 2 + 2(6) = 14 2 + 12 = 14 14 = 14 (correct) What you have to try to do in elimination is eliminate " get rid of " one of the variables, so you can find the other variable. Sometimes you have to do this by multiplying the equation by a number so that the variables will cancel each other out. That is why I multiplied the second equation by a 6. And as you can see, it made the x's cancel out and I was able to solve for y. Once finding y, I then substituted what I got for y into the second equation and found x. You can substitute into either one of the equations and you will get the answer. Then I checked my answer by subbing in the known variables and if they equal, which they did, then the problem is correct.
 one year ago

texaschic101Best ResponseYou've already chosen the best response.1
your quite welcome....thats what I am here for
 one year ago
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