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anonymous
 4 years ago
Find all values of x for which the function y=(2(85x))/(x+1)
anonymous
 4 years ago
Find all values of x for which the function y=(2(85x))/(x+1)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think question is incomplete !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y=([\sqrt{85x}\])/(x+1)...it's a square root also..not a two

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=\frac{\sqrt{85x}}{x+1}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, that's what it looks like!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok u must check for continuity first

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when I graphed it, it looked like 1/x graph

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah its something like that..maybe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so how do I check for continuity?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok u have some restrictions here.. division by zero is not allowed under radical cant be negative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually u must find domain of ur function

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and what about radical?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when u have something like \[\sqrt{x}\] u must have \[x\ge0\] right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what about the expression under square root sign?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0emm i mean u must have \(85x\ge0\) and this leads to\[x\le\frac{8}{5}\]make sense?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh yes sorry i meant to do that sign instead of the nonequal sign

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so the domain of function becomes\[x\le \frac{8}{5} \ \ \text{and} \ \ x\neq1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or u can write it like this\[(\infty,1)\cup (1,\frac{8}{5}]\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0got it. so is that where it's differentiable?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes thats it ... and just one more point function is not continous at end points \(x=1\) and \(x=\frac{8}{5}\) so it'll not be differentiable at that points...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thank you so much! i appreciate it :)
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