Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ellieb34

  • 2 years ago

Find all values of x for which the function y=(2(8-5x))/(x+1)

  • This Question is Closed
  1. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think question is incomplete !

  2. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is differentiable.

  3. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=([\sqrt{8-5x}\])/(x+1)...it's a square root also..not a two

  4. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[f(x)=\frac{\sqrt{8-5x}}{x+1}\]

  5. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes, that's what it looks like!

  6. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok u must check for continuity first

  7. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    when I graphed it, it looked like 1/x graph

  8. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah its something like that..maybe

  9. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so how do I check for continuity?

  10. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok u have some restrictions here.. division by zero is not allowed under radical cant be negative

  11. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    actually u must find domain of ur function

  12. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    domain is x=-1

  13. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[x\neq -1\]

  14. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohyeah you're right

  15. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and what about radical?

  16. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what's radical?

  17. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    square root

  18. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x\[\neq5/8\]

  19. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    er 8/5

  20. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    when u have something like \[\sqrt{x}\] u must have \[x\ge0\] right ?

  21. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  22. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so what about the expression under square root sign?

  23. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[x \neq 8/5\]

  24. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    emm i mean u must have \(8-5x\ge0\) and this leads to\[x\le\frac{8}{5}\]make sense?

  25. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh yes sorry i meant to do that sign instead of the nonequal sign

  26. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it does make sense

  27. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    good

  28. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so the domain of function becomes\[x\le \frac{8}{5} \ \ \text{and} \ \ x\neq-1\]

  29. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    or u can write it like this\[(-\infty,-1)\cup (-1,\frac{8}{5}]\]

  30. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    got it. so is that where it's differentiable?

  31. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes thats it ... and just one more point function is not continous at end points \(x=-1\) and \(x=\frac{8}{5}\) so it'll not be differentiable at that points...

  32. ellieb34
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok thank you so much! i appreciate it :)

  33. mukushla
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    very welcome :)

  34. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.