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mukushla
 one year ago
Best ResponseYou've already chosen the best response.0i think question is incomplete !

ellieb34
 one year ago
Best ResponseYou've already chosen the best response.0y=([\sqrt{85x}\])/(x+1)...it's a square root also..not a two

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=\frac{\sqrt{85x}}{x+1}\]

ellieb34
 one year ago
Best ResponseYou've already chosen the best response.0yes, that's what it looks like!

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0ok u must check for continuity first

ellieb34
 one year ago
Best ResponseYou've already chosen the best response.0when I graphed it, it looked like 1/x graph

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0yeah its something like that..maybe

ellieb34
 one year ago
Best ResponseYou've already chosen the best response.0so how do I check for continuity?

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0ok u have some restrictions here.. division by zero is not allowed under radical cant be negative

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0actually u must find domain of ur function

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0and what about radical?

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0when u have something like \[\sqrt{x}\] u must have \[x\ge0\] right ?

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0so what about the expression under square root sign?

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0emm i mean u must have \(85x\ge0\) and this leads to\[x\le\frac{8}{5}\]make sense?

ellieb34
 one year ago
Best ResponseYou've already chosen the best response.0oh yes sorry i meant to do that sign instead of the nonequal sign

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0ok so the domain of function becomes\[x\le \frac{8}{5} \ \ \text{and} \ \ x\neq1\]

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0or u can write it like this\[(\infty,1)\cup (1,\frac{8}{5}]\]

ellieb34
 one year ago
Best ResponseYou've already chosen the best response.0got it. so is that where it's differentiable?

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0yes thats it ... and just one more point function is not continous at end points \(x=1\) and \(x=\frac{8}{5}\) so it'll not be differentiable at that points...

ellieb34
 one year ago
Best ResponseYou've already chosen the best response.0ok thank you so much! i appreciate it :)
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