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nooce
 2 years ago
Best ResponseYou've already chosen the best response.1Simplify the x^12 and y^16 first

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1Remember:\[(x^a)^b x^{a• b}\]

kandsbbf
 2 years ago
Best ResponseYou've already chosen the best response.0do i just simplify the exponents?

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1We're simplifying them first, cause it's easier haha, we'll move on to the 240 after you simplify the exponents

kandsbbf
 2 years ago
Best ResponseYou've already chosen the best response.0so how do i simplify them?

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1Well since, \[(x^a)^b = x^{a•b}\] divide x^12 and y^16 by 4. What do you get?

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1(I mean the powers of x and y)

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1Wait, but 12/4 = 3, not 2. Also, it would be y^4

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1But moving on, now we simplify \[\sqrt[4]{2901}\] Do you have any idea on how to do this? (just asking)

kandsbbf
 2 years ago
Best ResponseYou've already chosen the best response.0no lol, but i really appreciate u teaching me

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1No problem, I'm glad to help :) Well, first, we need to find a factor of 2901 that is a power of 4. (ex. 16, because 2^4 = 16)

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1Here's a list of em: \[2^4 = 16\] \[3^4 = 81\] \[4^4 = 256\] \[5^4 = 625\] \[6^4 = 1296\] Are any of these numbers factors of 2901?

kandsbbf
 2 years ago
Best ResponseYou've already chosen the best response.0no i get dec. for all of them

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1The number in the problem is 2901, right?

nooce
 2 years ago
Best ResponseYou've already chosen the best response.1Alright, since we know 2401 = 7^4, we can take that out of the radical :) So we get, \[\sqrt[4]{2401x^{12}y^{16}} = 7x^3y^4\] Do you get it? :D
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