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kandsbbf

  • 3 years ago

What is a simpler form of the radical expression?

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  1. kandsbbf
    • 3 years ago
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    |dw:1358117374152:dw|

  2. kandsbbf
    • 3 years ago
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    @Butterfly16

  3. kandsbbf
    • 3 years ago
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    some pls help

  4. kandsbbf
    • 3 years ago
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    @loveudrew123

  5. nooce
    • 3 years ago
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    Simplify the x^12 and y^16 first

  6. nooce
    • 3 years ago
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    Remember:\[(x^a)^b x^{a• b}\]

  7. kandsbbf
    • 3 years ago
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    do i just simplify the exponents?

  8. nooce
    • 3 years ago
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    We're simplifying them first, cause it's easier haha, we'll move on to the 240 after you simplify the exponents

  9. nooce
    • 3 years ago
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    2901*

  10. kandsbbf
    • 3 years ago
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    so how do i simplify them?

  11. nooce
    • 3 years ago
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    Well since, \[(x^a)^b = x^{a•b}\] divide x^12 and y^16 by 4. What do you get?

  12. nooce
    • 3 years ago
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    (I mean the powers of x and y)

  13. kandsbbf
    • 3 years ago
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    x^2 x^4

  14. nooce
    • 3 years ago
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    Wait, but 12/4 = 3, not 2. Also, it would be y^4

  15. nooce
    • 3 years ago
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    But moving on, now we simplify \[\sqrt[4]{2901}\] Do you have any idea on how to do this? (just asking)

  16. kandsbbf
    • 3 years ago
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    no lol, but i really appreciate u teaching me

  17. nooce
    • 3 years ago
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    No problem, I'm glad to help :) Well, first, we need to find a factor of 2901 that is a power of 4. (ex. 16, because 2^4 = 16)

  18. kandsbbf
    • 3 years ago
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    how do we do that lol

  19. nooce
    • 3 years ago
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    Here's a list of em: \[2^4 = 16\] \[3^4 = 81\] \[4^4 = 256\] \[5^4 = 625\] \[6^4 = 1296\] Are any of these numbers factors of 2901?

  20. kandsbbf
    • 3 years ago
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    no i get dec. for all of them

  21. nooce
    • 3 years ago
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    The number in the problem is 2901, right?

  22. nooce
    • 3 years ago
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    Or is it 2401?

  23. nooce
    • 3 years ago
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    because, \[7^4 = 2401\]

  24. kandsbbf
    • 3 years ago
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    2401 sorry(:

  25. kandsbbf
    • 3 years ago
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    @nooce

  26. nooce
    • 3 years ago
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    Alright, since we know 2401 = 7^4, we can take that out of the radical :) So we get, \[\sqrt[4]{2401x^{12}y^{16}} = 7x^3y^4\] Do you get it? :D

  27. kandsbbf
    • 3 years ago
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    yes thankyou!

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