At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

|dw:1358117374152:dw|

some pls help

Simplify the x^12 and y^16 first

Remember:\[(x^a)^b x^{a• b}\]

do i just simplify the exponents?

2901*

so how do i simplify them?

Well since, \[(x^a)^b = x^{a•b}\]
divide x^12 and y^16 by 4. What do you get?

(I mean the powers of x and y)

x^2 x^4

Wait, but 12/4 = 3, not 2.
Also, it would be y^4

no lol, but i really appreciate u teaching me

how do we do that lol

no i get dec. for all of them

The number in the problem is 2901, right?

Or is it 2401?

because,
\[7^4 = 2401\]

2401 sorry(:

yes thankyou!